I0N34a THERMODYNAMICA Oefenzitting 4 - bio-ingenieur - home

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I0N34a Thermodynamica 2 de studiefase bio-ingenieurswetenschappen P 0,65 MPa 4 T 360 K 4 S 4 2, 26 kJ / kgK H 4 660 kJ / kg c) Energiebalans – steady state dU dt 0 W M in( H 4 H 3) W T 43 H H 780 660 120 kJ / kg M in 3MW 3000kW 3000 kJ / s 3000 kJ / s isobutaan M 25 kg / s 120 kJ / kg e) Compressor : Q=0 (adiabatische omkeerbare compressie) W H 2H1 (290 275) kJ / kg 15 kJ / kg M in W (15 kJ / kg)*(25 kg / s) 375 kJ / s P Turbine : adiabatische omkeerbare expansie : -WT/Min =120 kJ/kg Condensatievat : isobare warmteafgifte Q M C in Boiler : Q M B in H 1H4 (275 660) kJ / kg 385 kJ / kg H 3H2 (780 290) kJ / kg 490 kJ / kg Q 490 kJ / kg *25 kg / s 12,3 MJ / s B f) Efficiëntie : netto arbeid uit 3000 375 kJ / s 0,213 of 21,3% warmte in boiler 12,3*1000 kJ / s Oefenzitting 4 - Oplossingen 2/4
I0N34a Thermodynamica 2 de studiefase bio-ingenieurswetenschappen Oefening 4 a) 1→2: boiler 2 3 1 V1 = 1,917 10 -3 m 3 P1 = 10 5 Pa T1=300K condensatievat V2 =V1/18= 1,065 10 -4 m 3 P2 =P1V1 γ V2 -γ =5,72 10 6 Pa W = (P1 V1 γ ( 1 ) ( 1 ) V 2 V1 ) 1 1 PV 2 2 T2 = T1 PV 1 1 2→3: = 953 K V3 = 2V2=2,13 10 -4 m 3 P3 =P2= 5,72 10 6 Pa W =- P ∆V = - 609,2 J PV 3 3 T3 = T2 = 1906 K PV 3→4: 2 2 V4 = V1 = 1,917 10 -3 m 3 4 = 1044 J Oefenzitting 4 - Oplossingen 3/4
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I0N34a THERMODYNAMICA Oefenzitting 4 - bio-ingenieur - home

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