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4.3. Algebraisk form<br />
Algebraisk form fortsat<br />
Ikkebasisvariabler: x 1 = x 2 = 0<br />
Værdierne af Z og basisvariablerne kan aflæses<br />
Z − 3x 1 − 5x 2 = 0<br />
x 1 + x 3 = 4<br />
2x 2 + x 4 = 12<br />
3x 1 + 2x 2 + x 5 = 18<br />
Indkommende variabel: x 2<br />
Udgående variabel: x 4<br />
4. Simplexmetoden – p. 5/31<br />
Z − 3x 1 − 5x 2 = 0<br />
x 1 + x 3 = 4<br />
2x 2 + x 4 = 12<br />
3x 1 + 2x 2 + x 5 = 18<br />
Z − 3x 1 + 5/2x 4 = 30<br />
x 1 + x 3 = 4<br />
x 2 + 1/2x 4 = 6<br />
3x 1 − x 4 + x 5 = 6<br />
x 1 ind<br />
x 5 ud<br />
4. Simplexmetoden – p. 6/31<br />
Algebraisk form fortsat igenigen<br />
Z − 3x 1 + 5/2x 4 = 30<br />
x 1 + x 3 = 4<br />
+ x 2 + 1/2x 4 = 6<br />
3x 1 − x 4 + x 5 = 6<br />
Z + 3/2x 4 + x 5 = 36<br />
x 3 + 1/3x 4 − 1/3x 5 = 2<br />
+ x 2 + 1/2x 4 = 6<br />
x 1 − 1/3x 4 + 1/3x 5 = 2<br />
Optimum: Z ∗ = 36, x ∗ = (2, 6, 2, 0, 0)<br />
4. Simplexmetoden – p. 7/31<br />
4.4. Tableauform<br />
Basisvariabler antydes med et enkelt 1 i søjlen<br />
Rækkenummer udelades<br />
Z x 1 x 2 x 3 x 4 x 5<br />
1 −3 −5 0<br />
1 0 1 4<br />
0 ⇒ 2 1 12<br />
3 2 1 18<br />
1 −3 5/2 30<br />
1 1 0 4<br />
0 1 1/2 6<br />
⇒ 3 −1 1 6<br />
4. Simplexmetoden – p. 8/31