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Using Lemma 8.1 <strong>of</strong> Bhattacharya and Rao (1976, p.57), we get<br />
where Z 1<br />
Thus<br />
Since<br />
log (t) =<br />
nX<br />
j=1<br />
log(1 ; ih) =;ih + h2<br />
2<br />
0<br />
2 2<br />
i j + 4<br />
3<br />
(1 ; v) 3<br />
dv<br />
(1 ; ivh) 4<br />
nX<br />
j=1<br />
3 3<br />
i j + O(<br />
+ ih3<br />
3 +(ih)4<br />
Z 1<br />
Z 1<br />
1<br />
0 (j1+jvhj2 dv<br />
) 2<br />
nX<br />
j=1<br />
0<br />
(1 ; v) 3<br />
dv<br />
(1 ; ivh) 4<br />
Z 1<br />
0<br />
1dv =1:<br />
4<br />
j )=i 2 Tr(S 2 )+ 4<br />
3 i3Tr(S 3 )+O(Tr(S 4 )): (6.10)<br />
Cum2(Q) =2Tr([BnRn] 2 ) Cum3(Q) =8Tr([BnRn] 3 ) Cum4(Q) =48Tr([BnRn] 4 ) (6.11)<br />
(6.10) implies (6.9). Note now that<br />
by (6.2), where<br />
Cum2(Q) =<br />
p (2)<br />
m (t) =<br />
2X<br />
pv=1<br />
2X<br />
pv=1<br />
tptvE[ZpZv] =t 0<br />
tptv(E[ZpZv] ; ep+v):<br />
t + p (2)<br />
m (t)<br />
Since is positive de nite, such thatt 0 t jjtjj 2 =4, in view <strong>of</strong> (6.2)<br />
so it follows that for large enough m<br />
By Lemma 7.5,<br />
where<br />
Finally, sinceEQ =0,<br />
Cum3(Q) =<br />
2X<br />
ijk=1<br />
using Lemma 7.5. Hence by (6.9),<br />
jp (2)<br />
m (t)j C mjjtjj 2 <br />
Var(Q) =Cum2(Q) jjtjj 2 =8: (6.12)<br />
E[ZiZjZk]titjtk = m ;1=2 p (3) (t)+O(e 2<br />
m)jjtjj 3<br />
p (3) (t) =2<br />
2X<br />
ijk=1<br />
ei+j+ktitjtk:<br />
Cum4(Q) =EQ 4 ; 3(EQ 2 ) 2 = O(e 2<br />
m jjtjj4 ) (6.13)<br />
log (t) =; 1<br />
2 t0<br />
t + p(2) m (it)<br />
2! + m;1=2p (3) (it)<br />
+ O(e<br />
3!<br />
2<br />
mjjtjj 4<br />
+) (6.14)<br />
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