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Using Lemma 8.1 <strong>of</strong> Bhattacharya and Rao (1976, p.57), we get<br />

where Z 1<br />

Thus<br />

Since<br />

log (t) =<br />

nX<br />

j=1<br />

log(1 ; ih) =;ih + h2<br />

2<br />

0<br />

2 2<br />

i j + 4<br />

3<br />

(1 ; v) 3<br />

dv<br />

(1 ; ivh) 4<br />

nX<br />

j=1<br />

3 3<br />

i j + O(<br />

+ ih3<br />

3 +(ih)4<br />

Z 1<br />

Z 1<br />

1<br />

0 (j1+jvhj2 dv<br />

) 2<br />

nX<br />

j=1<br />

0<br />

(1 ; v) 3<br />

dv<br />

(1 ; ivh) 4<br />

Z 1<br />

0<br />

1dv =1:<br />

4<br />

j )=i 2 Tr(S 2 )+ 4<br />

3 i3Tr(S 3 )+O(Tr(S 4 )): (6.10)<br />

Cum2(Q) =2Tr([BnRn] 2 ) Cum3(Q) =8Tr([BnRn] 3 ) Cum4(Q) =48Tr([BnRn] 4 ) (6.11)<br />

(6.10) implies (6.9). Note now that<br />

by (6.2), where<br />

Cum2(Q) =<br />

p (2)<br />

m (t) =<br />

2X<br />

pv=1<br />

2X<br />

pv=1<br />

tptvE[ZpZv] =t 0<br />

tptv(E[ZpZv] ; ep+v):<br />

t + p (2)<br />

m (t)<br />

Since is positive de nite, such thatt 0 t jjtjj 2 =4, in view <strong>of</strong> (6.2)<br />

so it follows that for large enough m<br />

By Lemma 7.5,<br />

where<br />

Finally, sinceEQ =0,<br />

Cum3(Q) =<br />

2X<br />

ijk=1<br />

using Lemma 7.5. Hence by (6.9),<br />

jp (2)<br />

m (t)j C mjjtjj 2 <br />

Var(Q) =Cum2(Q) jjtjj 2 =8: (6.12)<br />

E[ZiZjZk]titjtk = m ;1=2 p (3) (t)+O(e 2<br />

m)jjtjj 3<br />

p (3) (t) =2<br />

2X<br />

ijk=1<br />

ei+j+ktitjtk:<br />

Cum4(Q) =EQ 4 ; 3(EQ 2 ) 2 = O(e 2<br />

m jjtjj4 ) (6.13)<br />

log (t) =; 1<br />

2 t0<br />

t + p(2) m (it)<br />

2! + m;1=2p (3) (it)<br />

+ O(e<br />

3!<br />

2<br />

mjjtjj 4<br />

+) (6.14)<br />

27

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