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Test 1 Practice Questions (First set) (1) Consider the following linear ...

Test 1 Practice Questions (First set) (1) Consider the following linear ...

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<strong>Test</strong> 1 <strong>Practice</strong> <strong>Questions</strong> (<strong>First</strong> <strong>set</strong>)<br />

(1) <strong>Consider</strong> <strong>the</strong> <strong>following</strong> <strong>linear</strong> system and answer <strong>the</strong> questions.<br />

⎧<br />

⎨<br />

⎩<br />

x + y − z = −2<br />

3x − 5y + 13z = 18<br />

x − 2y + 5z = k<br />

(a) Write down <strong>the</strong> augmented matrix.<br />

(b) For which k does this system have one solution?<br />

(c) Is <strong>the</strong> coefficient matrix A invertible? Explain your answer.<br />

(d) Let A be <strong>the</strong> coefficient matrix of this <strong>linear</strong> system and let T be <strong>the</strong> <strong>linear</strong><br />

transformation defined by A. Find <strong>the</strong> kernel and image of T .<br />

(2) <strong>Consider</strong> <strong>the</strong> <strong>following</strong> <strong>linear</strong> system and answer <strong>the</strong> questions.<br />

⎧<br />

⎨<br />

⎩<br />

x + 2y + 3z = 4<br />

x + ky + 4z = 6<br />

x + 2y + (k + 2)z = 6<br />

(a) For which k does this system have a unique solution?<br />

(b) When is <strong>the</strong>re no solution?<br />

(c) When are <strong>the</strong>re infinitely many solutions?<br />

(3) Find <strong>the</strong> polynomial of degree 2 whose graph goes through <strong>the</strong> points (1, 1), (2, 3)<br />

and (3, 13).<br />

(4) Find all vectors in R3 that are perpendicular to <strong>the</strong> <strong>following</strong> two vectors:<br />

⎡<br />

v1 = ⎣ 1<br />

⎤<br />

⎡<br />

3 ⎦ , and v1 = ⎣<br />

0<br />

1<br />

⎤<br />

1 ⎦ .<br />

1<br />

(5) The cross product of two vectors in R3 is given by<br />

⎡ ⎤ ⎡ ⎤ ⎡<br />

⎣ a1<br />

a2<br />

a3<br />

⎦ ×<br />

⎣ b1<br />

b2<br />

b3<br />

⎦ =<br />

⎣ a2b3 − a3b2<br />

a3b1 − a1b3<br />

a1b2 − a2b1<br />

Now fix an arbitrary vector v in R 3 . Is <strong>the</strong> transformation T (x) = v × x from R 3 to<br />

R 3 <strong>linear</strong>? If so, find its matrix in terms of <strong>the</strong> entries of v.<br />

(6) Suppose a line L in R3 contains <strong>the</strong> vector<br />

⎡ ⎤<br />

u =<br />

⎣ a1<br />

a2<br />

Find <strong>the</strong> matrix A of <strong>the</strong> <strong>linear</strong> transformation T (x) = proj L(x).<br />

1<br />

a3<br />

⎦ .<br />

⎤<br />

⎦ .


(7) For<br />

A =<br />

⎡<br />

⎢<br />

⎣<br />

0 1 2<br />

0 2 4<br />

0 3 6<br />

1 4 8<br />

(a) Find a vector b in R 4 such that <strong>the</strong> system Ax = b is inconsistent;<br />

(b) Find a vector c in R 4 such that <strong>the</strong> system Ax = c is consistent.<br />

<br />

1 10<br />

(8) Let A =<br />

. Find a scalar λ such that A − λI2 fails to be invertible. For<br />

−3 12<br />

each scalar λ you find, find a nonzero vector x such that Ax = λx.<br />

(9) Answer <strong>the</strong> <strong>following</strong> questions<br />

(a) Describe <strong>the</strong> kernel of <strong>the</strong> matrix ⎣<br />

⎡<br />

⎤<br />

⎥<br />

⎦ ,<br />

1 1 1<br />

1 2 3<br />

1 3 5<br />

(b) Describe <strong>the</strong> image of <strong>the</strong> <strong>linear</strong> transformation T (x) = Ax for A = ⎣<br />

(10) For <strong>the</strong> matrix<br />

⎡<br />

A = ⎣<br />

0 1 0<br />

0 0 1<br />

0 0 0<br />

describe <strong>the</strong> images and kernels of <strong>the</strong> matrices A, A 2 , A 3 .<br />

⎤<br />

⎦;<br />

⎡<br />

1 1 1<br />

1 1 1<br />

1 1 1<br />

(11) <strong>Consider</strong> a n × p matrix A and a p × m matrix B such that ker(A) = {0} and<br />

ker(B) = {0}. Find ker(AB).<br />

(12) For two invertible n × n matrices A and B, determine which of <strong>the</strong> formulas below<br />

are necessarily true.<br />

(a) (A + B) 2 = A 2 + 2AB + B 2<br />

(b) A 2 is invertible and (A 2 ) −1 = (A −1 ) 2<br />

(c) A + B is invertible, and (A + B) −1 = A −1 + B −1<br />

(d) (A + B)(A − B) = A 2 − B 2<br />

(e) ABB −1 A −1 = In<br />

(f) ABA −1 = B<br />

(g) (ABA −1 ) 3 = AB 3 A −1<br />

(h) (In + A)(In + A −1 ) = 2In + A + A −1<br />

(i) A −1 B is invertible, and (A −1 B) −1 = B −1 A.<br />

2<br />

⎤<br />

⎦ ,<br />

⎤<br />

⎦.

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