Phase splitter Concertina Phase Splitter

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C 1 V in R 1 V B1 R 2 V C1 R c V out1 V CC R c V out2 Q1 Q2 I REE V E R EE -V EE V C2 R 1 V B2 R 2 + C 2 + V in Vout1 RCRC =− ≅− h V h + R h in ie ie - i b R 1//R 2 fe h fei b h ie R C V out1 R C R EE h fei b i b h ie hie hie R= R EE // ≅ 1+ h 1+ h fe fe
<strong>Phase</strong> <strong>splitter</strong> Synthesis The circuit is symmetric so the emitter resistor can be divided in two parallel resistors with value 2REE and the synthesis can be done considering half circuit. The following assumptions are used VCC=-VEE=10V,VBEQ=0.65V, ICQ=1 mA,VCEQ=5V, VEQ=0. CC CEQ 1) Calculate RC : RC= = 5kΩ ICQ 2) Calculate 2R EE : 3) Calculate R 2 : 4) Calculate R 1: V −V VEQ + VEE10V 2REE = = = 10kΩ I 1mA CQ The R EE condition must be veryfied : For the BC107 h = h ⋅0.95 ≅ 211 FE 1mA FE 2mA ICQ 1mA IR2 = 10I BQ = 10 ≅10 ≅47μ A h 211 VB V BE 065 . V R2 = = ≅ ≅14kΩ I I 47μ A R2 R2 FE 1mA VCC −VBE9.35V IR1 ≅ IR2→ R1= = ≅ 200kΩ I 47μA R1 ( ) R > 100 ⋅ h / 1+ h EE ie fe R1 R2 V B I R1 I R2 I BQ I CQ BJT V CC Rc V CQ V EQ 2R EE -V EE
Page 1 and 2: Phase splitter Concertina Phase Spl
Page 3: Phase splitter Long-tailed pair Pha
Page 7 and 8: v out = A d (v in1-v in2) + A c (v
Page 9 and 10: 2) V in1 = V d/2 and V in2 = -V d/2
Page 11 and 12: To measure the two amplification yo

Phase splitter Concertina Phase Splitter

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