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Differentiation of a Function III<br />

n<br />

y = ax<br />

dy<br />

= anx<br />

dx<br />

n−1<br />

Example<br />

3<br />

y = 2x<br />

dy<br />

= 2(3) x =<br />

6x<br />

dx<br />

2 2<br />

Differentiation of a Fractional Function<br />

1<br />

y = n<br />

x<br />

Rewrite<br />

−n<br />

y = x<br />

dy −n−1 −n<br />

=− nx =<br />

dx x<br />

Example<br />

1<br />

y =<br />

x<br />

−1<br />

y = x<br />

dy −2<br />

−1<br />

=− 1x<br />

= 2<br />

dx x<br />

Law of Differentiation<br />

n+<br />

1<br />

Sum and Difference Rule<br />

y = u± v u and v are functions in x<br />

dy du dv<br />

= ±<br />

dx dx dx<br />

Example<br />

3 2<br />

y = 2x + 5x<br />

dy<br />

2 2<br />

= 2(3) x + 5(2) x= 6x + 10x<br />

dx<br />

http://www.one-school.net/notes.html<br />

10<br />

Chain Rule<br />

ONE-SCHOOL.NET<br />

n<br />

y = u u and v are functions in x<br />

dy dy du<br />

= ×<br />

dx du dx<br />

Example<br />

2 5<br />

y = (2x + 3)<br />

2<br />

du<br />

u = 2x + 3, therefore = 4x<br />

dx<br />

5 dy 4<br />

y = u , therefore = 5u<br />

du<br />

dy dy du<br />

= ×<br />

dx du dx<br />

= ×<br />

= 5(2x + 3) × 4x= 20 x(2x + 3)<br />

4<br />

5u 4x<br />

2 4 2 4<br />

Or differentiate directly<br />

n<br />

y = ( ax+ b)<br />

dy<br />

n−1<br />

= na ..( ax+ b)<br />

dx<br />

2 5<br />

y = (2x + 3)<br />

dy<br />

= 5(2x dx<br />

+ 3) × 4x= 20 x(2x + 3)<br />

2 4 2 4

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