Prime Implicant
Prime Implicant
Prime Implicant
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Petrick’s Petrick Method<br />
Example (cont.):<br />
Use to delete redundant terms from P<br />
P = PP<br />
P + PP<br />
P P + P PP<br />
P + P PP<br />
P<br />
1<br />
1<br />
1<br />
4<br />
4<br />
3<br />
5<br />
+ PP<br />
P P<br />
= PP<br />
P<br />
5<br />
4<br />
6<br />
1<br />
1<br />
2<br />
2<br />
3implicants<br />
Two minimum solutions:<br />
F<br />
F<br />
=<br />
=<br />
X + XY =<br />
P<br />
1<br />
P<br />
2<br />
1<br />
5<br />
5<br />
2<br />
4<br />
6<br />
+ P P PP<br />
+ PP<br />
P P<br />
+<br />
+<br />
P<br />
4<br />
P<br />
3<br />
+<br />
+<br />
6<br />
P<br />
P<br />
3<br />
X<br />
6<br />
2<br />
2<br />
3<br />
3<br />
2<br />
4<br />
4<br />
4<br />
3<br />
5<br />
+ P PP<br />
+ P PP<br />
P<br />
5<br />
6<br />
5<br />
4<br />
P<br />
6<br />
2<br />
1<br />
3<br />
3<br />
5<br />
2<br />
4<br />
4<br />
3<br />
6<br />
+ P PP<br />
+ PP<br />
P P<br />
= a′<br />
b′<br />
+ bc′<br />
+ ac<br />
= a′<br />
c′<br />
+ b′<br />
c +<br />
6<br />
ab<br />
6<br />
+ P PP<br />
2<br />
3<br />
6<br />
3<br />
Unit 06 26
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