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Answers - Millersville University

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At the 0.01 significance level test the claim that the self-identified compulsive buyer<br />

population has a mean greater than 0.21, the mean for the entire population. Does<br />

the questionnaire seem to be effective in identifying compulsive buyers?<br />

In this example the important sample statistics are the sample size n = 32, the sample<br />

mean x = 0.83, and the sample standard deviation s = 0.24.<br />

The symbolic form of the claim made above is µ > 0.21 where µ represents the population<br />

mean score of compulsive buyers on the questionnaire. Since this claim does not<br />

contain a condition of equality, it must be the alternative hypothesis, H1 : µ > 0.21.<br />

Therefore the null hypothesis is H0 : µ = 0.21. The test to be performed is a righttailed<br />

test at the α = 0.01 significance level on a large sample (since n > 30). The<br />

population standard deviation is unknown so we will use the Student’s t-distribution to<br />

represent the distribution of the sample means. Thus from Table V, the critical value<br />

of CV : tα = 2.326. The test statistic is<br />

TS : t0 =<br />

x − µ<br />

s/ √ n<br />

= 0.83 − 0.21<br />

0.24/ √ 32<br />

= 14.61.<br />

The test statistic is much larger than the critical value and thus the test statistic lies<br />

in the critical region of this right-tailed test. Since the test statistic falls into the<br />

critical region, then the null hypothesis is rejected. Now since the original claim is the<br />

alternative hypothesis and the null hypothesis is rejected, the conclusion can be stated<br />

as,<br />

“The sample data support the claim at the 0.01 significance level that the<br />

score of compulsive buyers on the questionnaire is higher than the score of<br />

the entire population.”<br />

The questionnaire seems to be effective at identifying compulsive buyers.<br />

3. According to the Insurance Information Institute, the mean expenditure for auto insurance<br />

in the United States was $774 in 2002. An insurance salesman obtains a random<br />

sample of 35 auto insurance policies and determines the mean expenditure to be $735<br />

with a standard deviation of $48.31. Is there enough evidence to conclude that the<br />

mean expenditure for auto insurance is different from the 2002 amount at the α = 0.01<br />

level of significance?<br />

Here the important sample statistics are the sample size n = 35, the sample mean<br />

x = 735, and the sample standard deviation s = 48.31.<br />

The symbolic form of the claim made by the insurance salesman is µ = 774 where<br />

µ represents the population mean expenditure for auto insurance. This claim is the<br />

alternative hypothesis, H1 : µ = 774. Therefore the null hypothesis is H0 : µ = 774.<br />

The test to be performed is a two-tailed test at the α = 0.01 significance level on a<br />

population whose standard deviation σ is unknown. Thus we will use the Student’s

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