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1 Continuous Time Processes - IPM

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that the Brownian motion has at least one 0 in the interval (t1, t2) can be<br />

written as<br />

P =<br />

<br />

1 ∞<br />

a2<br />

−<br />

√ P [Ta < t1 − t◦]e 2t◦σ<br />

2πtσ −∞<br />

2 da. (1.5.12)<br />

Let us explain the validity of this assertion. At time t◦, Zt◦ can be at any<br />

a2<br />

1 −<br />

point a ∈ R. The Gaussian exponential factor √ e 2t◦σ<br />

2πtσ 2 is the density<br />

function for Zt◦. The factor P [Ta < t1 − t◦] is equal to the probability<br />

that starting at a, the Brownian motion will assume value 0 in the ensuing<br />

time interval (t1 − t◦). The validity of the assertion follows from these facts<br />

put together. In view of the symmetry between a and −a, and the density<br />

function for Ta which we obtained in example 1.5.3, (1.5.12) becomes<br />

∞<br />

a2<br />

2 P = √<br />

2πt◦σ ◦ e− 2t◦σ √2πσ a ( t1−t◦<br />

a2<br />

− 1<br />

◦ e 2u<br />

u √ udu)da 1 = πσ2√ t1−t◦<br />

3<br />

−<br />

t◦ ◦ u 2 ( a2 1 1<br />

∞<br />

◦ ae− 2σ2 ( + u t◦ ) da)du<br />

= √ t◦ t1−t◦ du<br />

π ◦ (u+t◦) √ u<br />

The substitution √ u = x yields<br />

P = 2<br />

π tan−1<br />

<br />

t1 − t◦<br />

t◦<br />

= 2<br />

π cos−1<br />

<br />

t1<br />

t◦<br />

, (1.5.13)<br />

for the probability of at least one crossing of 0 betwen times t◦ and t1. It<br />

follows that the probability of no crossing in the time interval (t◦, t1) is<br />

2<br />

π sin−1<br />

<br />

t1<br />

which is the arc-sine law for Brownian motion. ♠<br />

So far we have only considered Brownian motion in dimension one. By<br />

looking at m copies of independent Brownian motions Zt = (Zt;1, · · · , Zt;m)<br />

we obtain Brownian motion in R m . While m-dimensional Brownian motion<br />

is defined in terms of coordinates, there is no preference for any direction in<br />

space. To see this more clearly, let A = (Ajk) be an m×m orthogonal matrix.<br />

This means that AA ′ = I where superscript ′ denotes the transposition of<br />

the matrix, and geometrically it means that the linear transformation A<br />

preserves lengths and therefore necessarily angles too. Let<br />

Yt;j =<br />

t◦<br />

m<br />

AjkZt;k.<br />

k=1<br />

41

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