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Chapter 7: Quantum Theory of the Atom

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56 <strong>Chapter</strong> 7<br />

Solution<br />

Wavelength and frequency are inversely related. Moreover, ultraviolet light is at higher<br />

frequency than yellow light. Doubling <strong>the</strong> frequency <strong>of</strong> a beam <strong>of</strong> light would give that beam<br />

a higher frequency than yellow light, whereas doubling <strong>the</strong> wavelength would give that beam<br />

a lower frequency than yellow light. Consequently, <strong>the</strong> beam with frequency doubled must be<br />

<strong>the</strong> one in <strong>the</strong> ultraviolet region.<br />

Here is ano<strong>the</strong>r way to look at <strong>the</strong> problem. Energy is directly related to <strong>the</strong> frequency<br />

and inversely related to <strong>the</strong> wavelength. Thus, <strong>the</strong> beam whose frequency is doubled will<br />

increase in energy, whereas <strong>the</strong> beam whose wavelength is doubled will decrease in energy.<br />

Since yellow light is in <strong>the</strong> visible region <strong>of</strong> <strong>the</strong> spectrum, which is lower in energy than <strong>the</strong><br />

ultraviolet region (Figure 7.5), <strong>the</strong> beam whose frequency is doubled will be higher in energy<br />

and thus in <strong>the</strong> UV region <strong>of</strong> <strong>the</strong> spectrum.<br />

Conceptual Problem 7.20<br />

Some infrared radiation has a wavelength that is 1000 times larger than that <strong>of</strong> a certain<br />

visible light. This visible light has a frequency that is 1000 times smaller than that <strong>of</strong> some X<br />

radiation. How many times more energy is <strong>the</strong>re in a photon <strong>of</strong> this X radiation than <strong>the</strong>re is<br />

in a photon <strong>of</strong> <strong>the</strong> infrared radiation?<br />

Solution<br />

Frequency is inversely related to <strong>the</strong> wavelength. Thus, <strong>the</strong> infrared radiation with a<br />

wavelength that is one thousand times larger than <strong>the</strong> visible light would have a frequency<br />

one thousand times smaller than <strong>the</strong> visible light. But, <strong>the</strong> visible light has a frequency one<br />

thousand times smaller than that <strong>of</strong> <strong>the</strong> X radiation. This makes <strong>the</strong> frequency <strong>of</strong> <strong>the</strong> X<br />

radiation one million times larger than <strong>the</strong> frequency <strong>of</strong> <strong>the</strong> infrared radiation. Therefore,<br />

since energy is directly related to <strong>the</strong> frequency, <strong>the</strong> energy <strong>of</strong> <strong>the</strong> X radiation would be one<br />

million times as large as <strong>the</strong> energy <strong>of</strong> <strong>the</strong> infrared radiation.<br />

Conceptual Problem 7.21<br />

One photon <strong>of</strong> green light has less than twice <strong>the</strong> energy <strong>of</strong> two photons <strong>of</strong> red light. Consider<br />

two hypo<strong>the</strong>tical experiments. In one experiment, potassium metal is exposed to one photon<br />

<strong>of</strong> green light; in ano<strong>the</strong>r experiment, potassium metal is exposed to two photons <strong>of</strong> red light.<br />

In one <strong>of</strong> <strong>the</strong>se experiments, no electrons are ejected by <strong>the</strong> photoelectric effect (no matter<br />

how many times this experiment is repeated), whereas in <strong>the</strong> o<strong>the</strong>r experiment at least one<br />

electron is ejected. What is <strong>the</strong> maximum number <strong>of</strong> electrons that could be ejected during<br />

this experiment, one or two?

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