Solution2 - Technische Informatik

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Storage Capacity The storage capacity of a mass storage media (BV) BV = NoH * NoT * NoS * NBS NOTE : NBS is by default 512 bytes ! Universität Duisburg-Essen Institut für Medientechnik and Software Engineering Exercise Operating Systems and Computer Networks & Datenverarbeitung 2
Storage Capacity Given a standard format 8-inch floppy disk with 2 heads, 80 tracks, 18 sectors per track, four 128byte units per sector (512 B), what is ist storage capacity in kilobytes [KB]? • BV = 2 * 80 * 18 * (4*128) [B] • BV = 2 * 80 * 18 * 512 [B] • BV = 1474560 [B] • BV = 1440 [KB] Universität Duisburg-Essen Institut für Medientechnik and Software Engineering Exercise Operating Systems and Computer Networks & Datenverarbeitung 2
Page 1 and 2: Folie a: Name Operating Systems and
Page 3 and 4: File System Concepts What are Files
Page 5 and 6: Mass Storage Refers to various tech
Page 7 and 8: Physical Concept (1/3) Hard-disk dr
Page 9: Physical Concept (3/3) Storing the
Page 13 and 14: File Allocation Table The FAT file
Page 15 and 16: Max Disk Partition (1) • Given Cl
Page 17 and 18: Unix File System i-node Universitä
Page 19 and 20: Unix File System b) Single indirect
Page 21 and 22: Free Space Management The beginning
Page 23: Next Week: Memory Management .. C

Solution2 - Technische Informatik

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