A Brief Introduction to Classical and Adelic Algebraic ... - William Stein
A Brief Introduction to Classical and Adelic Algebraic ... - William Stein
A Brief Introduction to Classical and Adelic Algebraic ... - William Stein
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162 CHAPTER 20. GLOBAL FIELDS AND ADELES<br />
As already remarked, A +<br />
K is a locally compact group, so it has an invariant<br />
Haar measure. In fact one choice of this Haar measure is the product of the Haar<br />
measures on the Kv, in the sense of Definition 20.2.5.<br />
Corollary 20.3.7. The quotient A +<br />
K /K+ has finite measure in the quotient measure<br />
induced by the Haar measure on A +<br />
K .<br />
Remark 20.3.8. This statement is independent of the particular choice of the multiplicative<br />
constant in the Haar measure on A +<br />
K . We do not here go in<strong>to</strong> the question<br />
of finding the measure A +<br />
K /K+ in terms of our explicitly given Haar measure. (See<br />
Tate’s thesis, [Cp86, Chapter XV].)<br />
Proof. This can be reduced similarly <strong>to</strong> the case of Q or F(t) which is immediate,<br />
e.g., the W defined above has measure 1 for our Haar measure.<br />
Alternatively, finite measure follows from compactness. To see this, cover AK/K +<br />
with the translates of U, where U is a nonempty open set with finite measure. The<br />
existence of a finite subcover implies finite measure.<br />
Remark 20.3.9. We give an alternative proof of the product formula |a| v = 1<br />
for nonzero a ∈ K. We have seen that if xv ∈ Kv, then multiplication by xv<br />
magnifies the Haar measure in K + v by a fac<strong>to</strong>r of |xv| v . Hence if x = {xv} ∈ AK,<br />
then multiplication by x magnifies the Haar measure in A +<br />
K by |xv| v . But now<br />
multiplication by a ∈ K takes K + ⊂ A +<br />
K in<strong>to</strong> K+ , so gives a well-defined bijection<br />
of A +<br />
K /K+ on<strong>to</strong> A +<br />
K /K+ which magnifies the measure by the fac<strong>to</strong>r <br />
|a| v . Hence<br />
|a|v = 1 Corollary 20.3.7. (The point is that if µ is the measure of A +<br />
K /K+ , then<br />
µ = |a| v · µ, so because µ is finite we must have |a| v = 1.)<br />
20.4 Strong Approximation<br />
We first prove a technical lemma <strong>and</strong> corollary, then use them <strong>to</strong> deduce the strong<br />
approximation theorem, which is an extreme generalization of the Chinese Remainder<br />
Theorem; it asserts that K + is dense in the analogue of the adeles with one<br />
valuation removed.<br />
The proof of Lemma 20.4.1 below will use in a crucial way the normalized Haar<br />
measure on AK <strong>and</strong> the induced measure on the compact quotient A +<br />
K /K+ . Since<br />
I am not formally developing Haar measure on locally compact groups, <strong>and</strong> since I<br />
didn’t explain induced measures on quotients well in the last chapter, hopefully the<br />
following discussion will help clarify what is going on.<br />
The real numbers R + under addition is a locally compact <strong>to</strong>pological group.<br />
Normalized Haar measure µ has the property that µ([a, b]) = b − a, where a ≤ b<br />
are real numbers <strong>and</strong> [a, b] is the closed interval from a <strong>to</strong> b. The subset Z + of R +<br />
is discrete, <strong>and</strong> the quotient S1 = R + /Z + is a compact <strong>to</strong>pological group, which<br />
thus has a Haar measure. Let µ be the Haar measure on S1 normalized so that the<br />
natural quotient π : R + → S1 preserves the measure, in the sense that if X ⊂ R +<br />
is a measurable set that maps injectively in<strong>to</strong> S1 , then µ(X) = µ(π(X)). This