Chapter 23: Newton's Laws of Motion
Chapter 23: Newton's Laws of Motion
Chapter 23: Newton's Laws of Motion
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688 CHAPTER <strong>23</strong> Newton’s <strong>Laws</strong> <strong>of</strong> <strong>Motion</strong><br />
Calculating Acceleration If an object changes speed but<br />
not direction, you can use the following equation to calculate<br />
the object’s acceleration.<br />
Acceleration Equation<br />
acceleration (in m/s 2 ) <br />
final speed (in m/s) initial speed (in m/s)<br />
time (in s)<br />
sf si a <br />
t<br />
In the acceleration equation, the symbol s f stands for the final<br />
speed and s i stands for the initial speed. The SI unit for acceleration<br />
is m/s 2 , which means meters/(seconds seconds). The unit<br />
m/s 2 is the result when the unit m/s is divided by the unit s.<br />
Solve a Simple Equation<br />
SKATEBOARD ACCELERATION It takes a skateboarder 12.0 s to speed up from 2.0 m/s<br />
to 8.0 m/s. What is the skateboarder’s acceleration?<br />
Solution<br />
This is what you know:<br />
This is what you need to find:<br />
This is the procedure you need<br />
to use:<br />
● initial speed: s f = 2.0 m/s<br />
● final speed: s i = 8.0 m/s<br />
● time: t = 12.0 s<br />
acceleration: a<br />
Substitute the known values for initial speed<br />
and time into the acceleration equation, and<br />
calculate the acceleration:<br />
(s f s i ) (8.0 m/s 2.0 m/s)<br />
a 0.5 m/s 2<br />
t (12.0 s)<br />
Check your answer: Multiply your answer by the time 12.0 s and<br />
then add the initial speed. The result should<br />
be the given final speed, 8.0 m/s.<br />
1. A horse speeds up from a speed <strong>of</strong> 11 m/s to 17 m/s in 3 s. What is the horse’s acceleration?<br />
2. What is the acceleration <strong>of</strong> a sports car initially at<br />
rest that reaches a speed <strong>of</strong> 30.0 m/s in 5.0 s? For more practice, visit<br />
green.msscience.com/<br />
math_practice