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Lab 1 Calibration of a Thermistor

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Pre- <strong>Lab</strong> for <strong>Calibration</strong><br />

<strong>of</strong> a <strong>Thermistor</strong><br />

A thermistor is made <strong>of</strong> a disc <strong>of</strong> semiconductor material. A semiconductor is composed <strong>of</strong> atoms that<br />

have 4 outer electrons. The 4 outer electrons <strong>of</strong> the atoms form covalent bonds with its nearest neighbors to<br />

form a diamond crystalline pattern. A two-dimensional representation <strong>of</strong> the crystal is shown in Fig. 1. For an<br />

electrical current to flow in the material, the covalent bond must be broken so that the electron is free to jump<br />

from atom to atom. In an insulator, that requires a lot <strong>of</strong> energy. In a conductor, very little energy is needed.<br />

However, a semiconductor requires more energy that a conductor, but not as much as an insulator. An energy<br />

level diagram can represent this (Fig. 2). The lower level is called the valence band and represents the electrons<br />

in the atoms that are bound to the atom. The upper level is called the conduction band and represents electrons<br />

that can move from atom to atom and can cause electrical current to flow. The distance between the valence<br />

band and the conduction band represents the energy (E g = energy gap) needed for current to start to flow.<br />

S<br />

i<br />

S<br />

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S<br />

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Conduction Band<br />

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E g<br />

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Valance Band<br />

Fig. 1<br />

Fig. 2<br />

Adding a tiny amount <strong>of</strong> impurities to the crystal can radically change the electrical characteristic <strong>of</strong> a<br />

semiconductor. For example, if a few phosphorus atoms are added to the silicon crystal, then the crystal pattern<br />

is preserved (Fig. 3). Phosphorus atoms have five outer electrons. Four <strong>of</strong> the electrons bond to its nearest<br />

neighbors, but the fifth electron is only slightly bonded with the phosphorus atom and a small amount <strong>of</strong> energy<br />

can cause the electron to jump from the energy level that is located in the energy gap to the conduction band<br />

(Fig. 4). That small amount <strong>of</strong> energy can be supplied by the thermal energy <strong>of</strong> the semiconductor’s<br />

surroundings. When the surroundings become warmer, more electrons then jump to the conduction band and<br />

material becomes a better electrical conductor. Hence, the electrical resistant <strong>of</strong> the material will drop with a<br />

temperature rise.<br />

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P<br />

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Conduction band<br />

E g<br />

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Valance Band<br />

Fig. 3<br />

Fig. 4<br />

3


The relationship between resistance and temperature for a thermistor is given by the Steinhart-Hart equation:<br />

1<br />

= A + Bln(R) + Cln(R)3<br />

T<br />

where T is measured in Kelvin and R is the resistance in ohms. The coefficients A, B, and C are the Steinhart-<br />

Hart coefficients and vary depending on the thermistor.<br />

€<br />

If A = 8.267 x 10 -4 K -1 , B = 2.089 x 10 -4 K -1 , and C= 8.033 x 10 -8 K -1 , write an Excel spread sheet to complete<br />

the following table.<br />

Save the program on your computer for lab.<br />

R(Ω) ln(R) 1/T<br />

(in K -1 )<br />

T<br />

(in K)<br />

T<br />

(In C o )<br />

T<br />

(in F o )<br />

269,080 12.503 0.003595 278.1 4.96 40.9<br />

207,850<br />

126,740<br />

100,000<br />

51,048<br />

27,475<br />

16,689<br />

10,110<br />

7,707<br />

5569<br />

4


<strong>Calibration</strong> <strong>of</strong> a <strong>Thermistor</strong><br />

Object: <strong>Thermistor</strong>s are temperature-sensitive resistive devices used in a wide range <strong>of</strong> temperature<br />

measurement applications. In this experiment you will calibrate a thermistor over a temperature range <strong>of</strong><br />

0°C to 100°C and use this data to determine the coefficients <strong>of</strong> an equation relating resistance to<br />

temperature.<br />

Apparatus:<br />

1. <strong>Thermistor</strong> probe<br />

2. Digital Multimeter<br />

3. Beaker<br />

4. Ice<br />

5. Hot Plate<br />

6. Thermometer<br />

Procedure:<br />

1. Assemble the apparatus as demonstrated by your instructor. Beginning with ice water in the container,<br />

take an initial reading as close to 0°C as possible. Stir the water before the reading to maintain the<br />

thermistor and thermometer at the same steady temperature.<br />

2. Once a good initial reading has been taken, remove the ice and begin heating the bath. Approximately<br />

every 5 C° remove the heat and take a resistance/ temperature reading, again being certain to stir the<br />

bath. Continue taking readings up to near 100°C.<br />

3. When you are finished collecting data, turn <strong>of</strong>f the hot plate and allow the water to cool while you<br />

analyze the data. As the water cools, record 4 readings <strong>of</strong> temperature and resistance. These data points<br />

will be used to check the curve fit <strong>of</strong> the data.<br />

4. Plot the data as a scatter graph on the computer with resistance on the<br />

x-axis and temperature along the y-axis.<br />

5. Plot the data with inverse Kelvin temperature on the y-axis and the natural log <strong>of</strong> the resistance on the x-<br />

axis Draw a straight line through your data points. Use the curve-fitting option in the graphing program<br />

to make a cubic fit to your data. The formula displayed will have the approximate values <strong>of</strong> A, B, C and<br />

D for the equation below. Use these values to check your answers in the next step.<br />

6. The manufacture <strong>of</strong> the thermister claims the empirical equation is given by the following equation.<br />

1<br />

= A + Bln(R) + Cln(R)3<br />

T<br />

where temperature T is in degrees Kelvin and ln(R) is the natural log <strong>of</strong> the<br />

resistance, R. How well the curve fits is given by the correlation factor R term at the end <strong>of</strong> the<br />

equation. R<br />

€<br />

= 1 would indicate a perfect fit. (Note: The curve fit gives a value for R and for R 2 .)<br />

However, the Excel program does not allow the data to be fitted to any arbitrary function. Plot (1/T)<br />

versus ln(R). Fit the graph to a polynomial <strong>of</strong> degree 3. That is, the equation we are going to use is as<br />

following:<br />

5


1<br />

T = A + Bln(R) + (1)<br />

Cln(R)2 + Dln(R) 3<br />

7. Use the graph and the equation to determine the temperatures <strong>of</strong> the water bath at those points taken<br />

while the bath was cooling. Compare these values with those read from the mercury thermometer. The<br />

calculations<br />

€<br />

can be done using a calculator or an excel spreadsheet can be used.<br />

Data: (An Excel spreadsheet can be used. Print out the spreadsheet instead <strong>of</strong> using the table below.)<br />

1<br />

2<br />

3<br />

4<br />

5<br />

6<br />

7<br />

8<br />

9<br />

10<br />

11<br />

12<br />

13<br />

14<br />

15<br />

16<br />

17<br />

18<br />

19<br />

20<br />

Temperature<br />

(in C o )<br />

Temperature<br />

( in K)<br />

Resistance<br />

(in Ω)<br />

1/T<br />

(in K -1 )<br />

ln(R)<br />

Graph fitting equation:<br />

A = _________ B = ____________ C = ____________ D = _______________<br />

Comparison <strong>of</strong> four data points while the water is cooling.<br />

T (Measured) R (Measured) T (From Graph) T(From Equation 1)<br />

1<br />

2<br />

3<br />

4<br />

Questions<br />

1) How does resistance relate to temperature in your thermistor?<br />

6

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