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Continuous Truth I Non-constructive Objects

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176 M.P. FOURMAN<br />

Proof. If Uik f: pt )# + pt W then f is represented by 5: X x U + Y in (c. For<br />

VE()(Y) a basic open of W, w: W + U and x: W + X we have<br />

Wlk (t;lw)(x) E<br />

iff [S 0 l-l(v) = w<br />

-1 -1<br />

iff 5 (V) = w<br />

w It- x E<br />

iff<br />

c5-1(v)lwl<br />

1<br />

regarding 5- V E O(Xx U) as an open of )# defined at U.<br />

1<br />

Thus Ulk 5- (V) is open. 0<br />

v<br />

55 Iteration<br />

We return for a while to consideration of a general Grothendieck topos B = Sh(O,J).<br />

We consider the internal category (I in E given by<br />

(E(U)<br />

with restrictions given by pulling back.<br />

[For those who worry about coherence (one should worry), we remark that a concrete<br />

category in E with an equivalent category of sections over U is given by<br />

considering V/f to be represented as the element S of (PV)(U) determined by<br />

W / ~ V E S iff ~ ~ f o v = g .<br />

So & is an internal small full subcategory of E whose objects are subfunctors of<br />

representables.]<br />

We give C_ a topology by letting<br />

xi<br />

\/<br />

-x<br />

cover<br />

Now for A E IEI we define A, E ShE(C,J) by<br />

with restrictions for g: V<br />

(c/u<br />

X/f in & if Xi + X cover X in c.<br />

UkA_(X/f)<br />

A(X)<br />

+ U given by restriction along f*g<br />

and for 5: Y/h + X/g in a/U, by restriction along 5<br />

Y A X<br />

Any morphism A + B in E induces<br />

U<br />

+,B in ShE($,J).

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