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Square Roots - Beau Chene High School Home Page

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7<br />

In part (d) of Example 1, the square root in the denominator of was<br />

2<br />

eliminated by multiplying both the numerator and the denominator by 2.<br />

This process is called rationalizing the denominator.<br />

You can use square roots to solve some types of quadratic equations. For instance,<br />

if s > 0, then the quadratic equation x 2 = s has two real-number solutions: x = s<br />

and x = ºs. These solutions are often written in condensed form as x = ±s.<br />

The symbol ±s is read as “plus or minus the square root of s.”<br />

EXAMPLE 2<br />

Solving a Quadratic Equation<br />

Solve 2x 2 + 1 = 17.<br />

SOLUTION<br />

Begin by writing the equation in the form x 2 = s.<br />

2x 2 + 1 = 17<br />

Write original equation.<br />

2x 2 = 16<br />

Subtract 1 from each side.<br />

x 2 = 8 Divide each side by 2.<br />

x = ±8<br />

x = ±22<br />

Take square roots of each side.<br />

Simplify.<br />

The solutions are 22 and º22.<br />

✓CHECK You can check the solutions algebraically<br />

by substituting them into the original equation. Since<br />

this equation is equivalent to 2x 2 º 16 = 0, you can<br />

also check the solutions by graphing y = 2x 2 º16<br />

and observing that the graph’s x-intercepts appear to<br />

be about 2.8 ≈ 22 and º2.8 ≈ º22.<br />

EXAMPLE 3<br />

Solving a Quadratic Equation<br />

STUDENT HELP<br />

HOMEWORK HELP<br />

Visit our Web site<br />

www.mcdougallittell.com<br />

for extra examples.<br />

INTERNET<br />

Solve 1 3 (x +5)2 = 7.<br />

SOLUTION<br />

1 3 (x +5)2 = 7<br />

Write original equation.<br />

(x +5) 2 = 21 Multiply each side by 3.<br />

x + 5 = ±21<br />

Take square roots of each side.<br />

x = º5 ± 21 Subtract 5 from each side.<br />

The solutions are º5 + 21 and º5 º 21.<br />

✓CHECK Check the solutions either by substituting them into the original equation<br />

or by graphing y = 1 3 (x +5)2 º 7 and observing the x-intercepts.<br />

5.3 Solving Quadratic Equations by Finding <strong>Square</strong> <strong>Roots</strong> 265

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