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Machine Dynamics Problems

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68 B. Dyniewicz, c.t. Bajer<br />

V(j,t)<br />

I .<br />

= fu(x,t)sin~<br />

o<br />

I<br />

(1)<br />

2 00 •<br />

u(x,t)=- L:V(j,t)sin J7lX<br />

I j=1<br />

I<br />

(2)<br />

We can present each of the functions as a infmite sum of sine functions (2) with<br />

respective coefficients (1). Then the expansion of the moving mass acceleration in<br />

a series has a form<br />

f;2u(vt,t) _ 2 L oo [V"(k ) . brut 2k1ru V '(k) brut e,,2v 2 V(k ) . k"vt]<br />

-~----'--- t sm--+-- t cos--- t Sill--<br />

8t2 [ k=1 ' l I , l [2 ' l<br />

The integral transformation (1) of the equation (9) with consideration of (3) can be<br />

performed<br />

/,,2 .. jnct a 2 u(vt t) I jttx<br />

N- 2<br />

-V(j,t) + pAV(j,t) =Psin-- m 2' fS(x - vt)sin-dx<br />

I I 8t 0 I<br />

(4)<br />

The integral with delta Dirac function in the above equation is as follows<br />

(3)<br />

I . .<br />

f S(x - vt) sin J 7lX dx = sin J "ut<br />

o I I<br />

(5)<br />

Let us consider now (3) and (5):<br />

/" 2 .. j "ut 2m 00 .. km» j mx<br />

N-<br />

I<br />

- 2<br />

-V(j,t) + pAV(j,t) = PSin- Z<br />

- --l-~V(k,t)sin-Z-sin-Z--<br />

2m ~ Zkstu V·(k) k"vt. j mx 2m ~ k 2,,2 v 2 V(k ) . kmx . j "vI<br />

--L,...-- ,t cos--sm--+-L,... 2 ,t sm--sm--<br />

I k=1 I I I I k=1 I I I<br />

(6)<br />

Finally, the motion equation after Fourier transformation<br />

can be written<br />

00 00<br />

pAV(j,t) + a L:V(k,t) sin liJktsin liJjt + 2a L:liJkV(k,t) COSliJkt sin liJjt +<br />

k=1 k=1<br />

00<br />

+ o'rt], t) - a L:liJ;V(k, t) sin liJktsin liJjt = Psin liJ}<br />

k=1<br />

(7)<br />

where

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