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Simplified Nyquist Criterion

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5.6 Stability test and controller setting with the frequency response of the<br />

open control loop 153<br />

frequency response is relatively easy to assess. In these cases, p = 0,<br />

and the number of revolutions of the <strong>Nyquist</strong> plot of G 0 (jω) must be<br />

zero. It is therefore possible to check the stability with more simple<br />

versions of the <strong>Nyquist</strong> criterion, e.g. with:<br />

If the open control loop is stable or has integrating behaviour,<br />

then the following applies:<br />

If point −1 is in the area on the left of the <strong>Nyquist</strong> plot of<br />

the frequency response G 0 (jω) traversed in the direction of<br />

increasing frequency, then the closed control loop is stable.<br />

Otherwise it is not stable.<br />

Figure 5-22 shows the <strong>Nyquist</strong> plot of an open control loop with a PIDcontroller.<br />

The open control loop satisfies the conditions for application<br />

of a simplified version of the <strong>Nyquist</strong> criterion. We recognize that<br />

the closed control loop for K R = 10 will be unstable because point −1<br />

is to the right of the <strong>Nyquist</strong> plot. We can also see that for substantially<br />

larger and smaller K R (e.g. K R > 120 or K R < 0, 15) the closed control<br />

loop is stable because point −1 is then to the left of the <strong>Nyquist</strong> plot.<br />

Control systems with a <strong>Nyquist</strong> plot which intersects the real axis a<br />

number of times as those illustrated in figure 5-22 occur very rarely; a<br />

further, substantially simplified version of the <strong>Nyquist</strong> criterion, which<br />

does not consider such systems but is very easy to use appears therefore<br />

very expedient and becomes the “<strong>Simplified</strong> <strong>Nyquist</strong> <strong>Criterion</strong>” :<br />

If the open control loop is stable or has integrating behaviour<br />

and the <strong>Nyquist</strong> plot of the frequency response G 0 (jω) only<br />

intersects the real axis such that the frequency increases during<br />

the transition from the third to the second quadrant,<br />

then the following applies:<br />

If the <strong>Nyquist</strong> plot of the frequency response G 0 (jω) only<br />

intersects the real axis to the right of point −1, then the<br />

closed control loop is stable. Otherwise it is not stable.<br />

If the nyquist plot ends on the real axis in the third quadrant, it can be<br />

interpreted as an intersection for infinit values of ω. In this case the<br />

“<strong>Simplified</strong> <strong>Nyquist</strong> <strong>Criterion</strong>” can be applied.


160 Controller setting and stability of control loops<br />

5.6.3 Controller design in the Bode diagram<br />

For the practical treatment of linear control systems the representation<br />

of frequency responses in the Bode diagram is preferred above that by<br />

the <strong>Nyquist</strong> plots because the former method is simpler by far. The<br />

statements on the stability of a closed loop provided by the <strong>Nyquist</strong><br />

criterion can be transferred to the representation of the frequency response<br />

of the open control loop in the Bode diagram. This shall only<br />

be dealt with in the following text within the context of the “<strong>Simplified</strong><br />

<strong>Nyquist</strong> <strong>Criterion</strong>”.<br />

As illustrated in figure 5-26, we can, for stability testing with the “<strong>Simplified</strong><br />

<strong>Nyquist</strong> <strong>Criterion</strong>” determine the frequency ω π from the phase<br />

response with the definition ϕ 0 (ω π ) =−π and check whether the amplitude<br />

of the frequency response |G 0 (jω π )| is less than one. Alternatively,<br />

with the definition |G 0 (jω d )|=1 we can obtain from the amplitude<br />

response the frequency ω d and check whether the phase angle<br />

ϕ 0 (ω d ) is greater than −π.<br />

We must ensure in every case that the “<strong>Simplified</strong> <strong>Nyquist</strong> <strong>Criterion</strong>” is<br />

applicable.<br />

Summarizing, the “<strong>Simplified</strong> <strong>Nyquist</strong> <strong>Criterion</strong>” for the application in<br />

the Bode diagram gives:<br />

If the open control loop is stable or has integrating behaviour<br />

and the phase response of its frequency response in the Bode<br />

diagram intersects the lines −180 ◦ − n · 360 ◦ with a negative<br />

slope only, then the following applies:<br />

If the amplitude of the frequency response |G 0 (jω π )| is less<br />

than one at frequency values for which the phase response<br />

gives ϕ 0 (ω π ) =−180 ◦ − n · 360 ◦ , then the closed control<br />

loop is stable. Otherwise it is not stable.<br />

For the “<strong>Simplified</strong> <strong>Nyquist</strong> <strong>Criterion</strong>” the point where the phase response<br />

is just tangent to the line −180 ◦ − n · 360 ◦ for infinit values of<br />

ω has to be considered.<br />

Figure 5-26 also shows that it is possible to obtain the gain margin<br />

from the amplitude response |G 0 (jω π )| and the phase margin from<br />

the phase response ϕ 0 (ω d ).

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