Deflection of an Electron in a Magnetic Field
Deflection of an Electron in a Magnetic Field
Deflection of an Electron in a Magnetic Field
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Us<strong>in</strong>g equations 4 <strong>an</strong>d 5, we f<strong>in</strong>d a prelim<strong>in</strong>ary expression for the deflection, x, <strong>in</strong> terms<br />
<strong>of</strong> the magnetic field strength:<br />
S 2<br />
2x " 1 B<br />
2mV acc<br />
e<br />
(6)<br />
We c<strong>an</strong>not measure the strength <strong>of</strong> the magnetic field directly, but we c<strong>an</strong> express it <strong>in</strong><br />
terms <strong>of</strong> the current that produces it. To simplify the math, we will make <strong>an</strong>other<br />
approximation. The extreme ! oblong rect<strong>an</strong>gular geometry <strong>of</strong> the coils used to generate<br />
the magnetic field, B, me<strong>an</strong>s that the two “far ends” contribute relatively little. As such,<br />
the coil c<strong>an</strong> be thought <strong>of</strong> as two sets <strong>of</strong> N long wires, where N is the number <strong>of</strong> turns <strong>in</strong><br />
the coil. The magnetic field generated by a s<strong>in</strong>gle long straight wire:<br />
B = µ o I<br />
2"a<br />
(7)<br />
where a is the dist<strong>an</strong>ce from the wire to the electron beam, I is the current which is<br />
generat<strong>in</strong>g B, <strong>an</strong>d µ 0<br />
= 4 π × 10 -7 Tesla·m/Amp.<br />
!<br />
The magnetic field produced by the current <strong>in</strong> the top wire adds to the magnetic field<br />
produced by the current <strong>in</strong> the bottom wire. The wires on the top are about the same<br />
dist<strong>an</strong>ce ! from the electron beam as the wires on the bottom. S<strong>in</strong>ce we are treat<strong>in</strong>g our<br />
coils as two sets <strong>of</strong> N wires, the magnetic field is:<br />
#<br />
B = B top<br />
+ B bottom<br />
= N %<br />
$<br />
µ oI<br />
2"a top<br />
&<br />
( + N # µ o<br />
I<br />
%<br />
' $<br />
2"a bottom<br />
&<br />
( = µ oNI<br />
' "a<br />
(8)<br />
Substitut<strong>in</strong>g this result <strong>in</strong>to Equation 6 <strong>an</strong>d simplify<strong>in</strong>g, you should be able to SHOW:<br />
!<br />
e m<br />
x = µ NS 2<br />
o<br />
2 2" a<br />
I<br />
V acc<br />
(9)<br />
Procedure<br />
!<br />
The apparatus will be pre-wired, as described below. Exam<strong>in</strong>e the wir<strong>in</strong>g, mak<strong>in</strong>g sure<br />
that it agrees with what is described below. Once you th<strong>in</strong>k it is correct, call the <strong>in</strong>structor<br />
or TA over to look at it before turn<strong>in</strong>g <strong>an</strong>y power supply on. The circuit diagram for the<br />
CRT control box (the alum<strong>in</strong>um box at your station) is seen below, <strong>in</strong> Figure 3.<br />
36