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Deflection of an Electron in a Magnetic Field

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Us<strong>in</strong>g equations 4 <strong>an</strong>d 5, we f<strong>in</strong>d a prelim<strong>in</strong>ary expression for the deflection, x, <strong>in</strong> terms<br />

<strong>of</strong> the magnetic field strength:<br />

S 2<br />

2x " 1 B<br />

2mV acc<br />

e<br />

(6)<br />

We c<strong>an</strong>not measure the strength <strong>of</strong> the magnetic field directly, but we c<strong>an</strong> express it <strong>in</strong><br />

terms <strong>of</strong> the current that produces it. To simplify the math, we will make <strong>an</strong>other<br />

approximation. The extreme ! oblong rect<strong>an</strong>gular geometry <strong>of</strong> the coils used to generate<br />

the magnetic field, B, me<strong>an</strong>s that the two “far ends” contribute relatively little. As such,<br />

the coil c<strong>an</strong> be thought <strong>of</strong> as two sets <strong>of</strong> N long wires, where N is the number <strong>of</strong> turns <strong>in</strong><br />

the coil. The magnetic field generated by a s<strong>in</strong>gle long straight wire:<br />

B = µ o I<br />

2"a<br />

(7)<br />

where a is the dist<strong>an</strong>ce from the wire to the electron beam, I is the current which is<br />

generat<strong>in</strong>g B, <strong>an</strong>d µ 0<br />

= 4 π × 10 -7 Tesla·m/Amp.<br />

!<br />

The magnetic field produced by the current <strong>in</strong> the top wire adds to the magnetic field<br />

produced by the current <strong>in</strong> the bottom wire. The wires on the top are about the same<br />

dist<strong>an</strong>ce ! from the electron beam as the wires on the bottom. S<strong>in</strong>ce we are treat<strong>in</strong>g our<br />

coils as two sets <strong>of</strong> N wires, the magnetic field is:<br />

#<br />

B = B top<br />

+ B bottom<br />

= N %<br />

$<br />

µ oI<br />

2"a top<br />

&<br />

( + N # µ o<br />

I<br />

%<br />

' $<br />

2"a bottom<br />

&<br />

( = µ oNI<br />

' "a<br />

(8)<br />

Substitut<strong>in</strong>g this result <strong>in</strong>to Equation 6 <strong>an</strong>d simplify<strong>in</strong>g, you should be able to SHOW:<br />

!<br />

e m<br />

x = µ NS 2<br />

o<br />

2 2" a<br />

I<br />

V acc<br />

(9)<br />

Procedure<br />

!<br />

The apparatus will be pre-wired, as described below. Exam<strong>in</strong>e the wir<strong>in</strong>g, mak<strong>in</strong>g sure<br />

that it agrees with what is described below. Once you th<strong>in</strong>k it is correct, call the <strong>in</strong>structor<br />

or TA over to look at it before turn<strong>in</strong>g <strong>an</strong>y power supply on. The circuit diagram for the<br />

CRT control box (the alum<strong>in</strong>um box at your station) is seen below, <strong>in</strong> Figure 3.<br />

36

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