Physics 590 Homework, Week 2

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0 m/s = v initial + (-9.0 m/s^2)(8.0 s) v initial = - (-9.0 m/s^2)(8.0 s) v initial = 72 m/s Now that I have v initial; I will use it in the formula: d = v i * t + 1/2 at 2 To solve for distance d = (72 m/s)(8.0 s) + 1/2(-9.0 m/s^2)(8.0 s)^2 d = 576 m + (-4.5 m/s^2)(64 s^2) d = 576m - 288 m d = 288 m d = 2.9 x 10^2 m
Prob. 2.1.8 A plane travels a distance of 5.0 × 102 m while being accelerated uniformly from rest at the rate of +5.0 m/s2. What final speed does it attain? v f 2 = v i 2 + 2ad v initial = 0 m/s a = +5.0 m/s^2 d = 5.0 x 10^2 m v f 2 = (0 m/s)^2 + 2(5.0 m/s^2)(5.0 x 10^2 m) v f 2 = (10.0 m/s^2)(5.0 x 10^2 m) v f 2 = 50.0 x 10^2 m^2/s^2 v final = 70.7107 m/s V final = 7.1 x 10^1m/s Prob. 2.1.9 A stone falls freely from rest for 8.0 s. (a) Calculate its final velocity. (b) What distance does the stone fall during this time? a) v f = v i + at v initial = 0 m/s a = 9.8 m/s^2 t = 8.0 s
Page 1 and 2: Physics 590 Homework, Week 2 Week 2
Page 3 and 4: Prob. 2.1.3 Find the uniform accele
Page 5 and 6: d = 77.5 m/s * 5.0 s d = 387.5 m d
Page 7: Use the acceleration that was solve
Page 11 and 12: v initial = 0 m/s v final = 73.5 m/

Physics 590 Homework, Week 2

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