Theoretical Computer Science Cheat Sheet Definitions Series ... - TUG
Theoretical Computer Science Cheat Sheet Definitions Series ... - TUG
Theoretical Computer Science Cheat Sheet Definitions Series ... - TUG
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Wallis’ identity:<br />
π = 2 · 2 · 2 · 4 · 4 · 6 · 6 · · ·<br />
1 · 3 · 3 · 5 · 5 · 7 · · ·<br />
π<br />
Brouncker’s continued fraction expansion:<br />
π<br />
4 = 1 + 1 2<br />
3<br />
2 + 2<br />
2+ 52<br />
2+<br />
2+···<br />
72<br />
Gregrory’s series:<br />
π<br />
4 = 1 − 1 3 + 1 5 − 1 7 + 1 9 − · · ·<br />
Newton’s series:<br />
π<br />
6 = 1 2 + 1<br />
2 · 3 · 2 3 + 1 · 3<br />
2 · 4 · 5 · 2 5 + · · ·<br />
Sharp’s series:<br />
π<br />
6 = √ 1 (<br />
1 − 1<br />
3 3 1 · 3 + 1<br />
3 2 · 5 − 1 )<br />
3 3 · 7 + · · ·<br />
Euler’s series:<br />
π 2<br />
6 = 1 1 2 + 1 2 2 + 1 3 2 + 1 4 2 + 1 5 2 + · · ·<br />
π 2<br />
8 = 1 1 2 + 1 3 2 + 1 5 2 + 1 7 2 + 1 9 2 + · · ·<br />
π 2<br />
12 = 1 1 2 − 1 2 2 + 1 3 2 − 1 4 2 + 1 5 2 − · · ·<br />
Partial Fractions<br />
Let N(x) and D(x) be polynomial functions<br />
of x. We can break down<br />
N(x)/D(x) using partial fraction expansion.<br />
First, if the degree of N is greater<br />
than or equal to the degree of D, divide<br />
N by D, obtaining<br />
N(x)<br />
D(x) = Q(x) + N ′ (x)<br />
D(x) ,<br />
where the degree of N ′ is less than that of<br />
D. Second, factor D(x). Use the following<br />
rules: For a non-repeated factor:<br />
N(x)<br />
(x − a)D(x) = A<br />
x − a + N ′ (x)<br />
D(x) ,<br />
where<br />
A =<br />
[ ] N(x)<br />
.<br />
D(x)<br />
x=a<br />
For a repeated factor:<br />
m−1<br />
N(x)<br />
(x − a) m D(x) = ∑ A k (x)<br />
(x − a) m−k +N′ D(x) ,<br />
where<br />
A k = 1 k!<br />
k=0<br />
[ ( )]<br />
d<br />
k N(x)<br />
dx k .<br />
D(x)<br />
x=a<br />
The reasonable man adapts himself to the<br />
world; the unreasonable persists in trying<br />
to adapt the world to himself. Therefore<br />
all progress depends on the unreasonable.<br />
– George Bernard Shaw<br />
<strong>Theoretical</strong> <strong>Computer</strong> <strong>Science</strong> <strong>Cheat</strong> <strong>Sheet</strong><br />
Derivatives:<br />
1. d(cu)<br />
dx<br />
4. d(un )<br />
dx<br />
7. d(cu )<br />
dx<br />
9.<br />
11.<br />
13.<br />
15.<br />
17.<br />
19.<br />
21.<br />
23.<br />
25.<br />
27.<br />
29.<br />
d(sin u)<br />
dx<br />
d(tan u)<br />
dx<br />
d(sec u)<br />
dx<br />
Calculus<br />
= cdu<br />
d(u + v)<br />
, 2. = du<br />
dx dx<br />
du<br />
= nun−1<br />
dx ,<br />
du<br />
= (ln c)cu<br />
dx<br />
d(arcsin u)<br />
dx<br />
d(arctan u)<br />
dx<br />
d(arcsec u)<br />
dx<br />
d(sinh u)<br />
dx<br />
d(tanh u)<br />
dx<br />
d(sech u)<br />
dx<br />
d(arcsinh u)<br />
dx<br />
d(arctanh u)<br />
dx<br />
dx + dv<br />
dx ,<br />
d(u/v)<br />
5. = v( du<br />
dx<br />
dx<br />
d(uv)<br />
3.<br />
dx<br />
= u dv<br />
dx + v du<br />
dx ,<br />
) (<br />
− u<br />
dv<br />
)<br />
dx<br />
v 2 , 6. d(ecu )<br />
dx<br />
, 8.<br />
d(ln u)<br />
dx<br />
cu du<br />
= ce<br />
dx ,<br />
= 1 du<br />
u dx ,<br />
= cos u du<br />
d(cos u)<br />
, 10. = − sin u du<br />
dx dx<br />
dx ,<br />
= sec 2 u du<br />
d(cot u)<br />
, 12. = csc 2 u du<br />
dx dx<br />
dx ,<br />
= tan u sec u du<br />
d(csc u)<br />
, 14. = − cot u csc u du<br />
dx dx<br />
dx ,<br />
=<br />
1 du<br />
d(arccos u)<br />
√ , 16. = −1 du<br />
√<br />
1 − u<br />
2 dx dx 1 − u<br />
2 dx ,<br />
= 1 du<br />
1 + u 2 dx<br />
1<br />
=<br />
u √ du<br />
1 − u 2 dx<br />
, 18.<br />
d(arccot u)<br />
dx<br />
, 20.<br />
d(arccsc u)<br />
dx<br />
=<br />
= −1<br />
1 + u 2 du<br />
dx ,<br />
−1<br />
u √ du<br />
1 − u 2 dx ,<br />
= cosh u du<br />
d(cosh u)<br />
, 22. = sinh u du<br />
dx dx<br />
dx ,<br />
= sech 2 u du<br />
d(coth u)<br />
, 24. = − csch 2 u du<br />
dx dx<br />
dx ,<br />
= − sech u tanh u du<br />
d(csch u)<br />
, 26. = − csch u coth u du<br />
dx dx<br />
dx ,<br />
1 du<br />
d(arccosh u) 1 du<br />
= √ , 28. = √<br />
1 + u<br />
2 dx dx u2 − 1 dx ,<br />
= 1 du<br />
d(arccoth u)<br />
1 − u 2 , 30. = 1 du<br />
dx dx u 2 − 1 dx ,<br />
d(arcsech u) −1<br />
31. =<br />
dx u √ du<br />
d(arccsch u)<br />
, 32. =<br />
1 − u 2 dx dx<br />
Integrals:<br />
∫ ∫<br />
∫<br />
∫<br />
1. cu dx = c u dx, 2. (u + v) dx =<br />
3.<br />
6.<br />
8.<br />
10.<br />
12.<br />
14.<br />
−1<br />
|u| √ du<br />
1 + u 2 dx .<br />
∫<br />
u dx +<br />
v dx,<br />
∫<br />
x n dx = 1<br />
∫ ∫<br />
1<br />
n + 1 xn+1 , n ≠ −1, 4.<br />
x dx = ln x, 5. e x dx = e x ,<br />
∫<br />
∫<br />
dx<br />
1 + x 2 = arctan x, 7. u dv ∫<br />
dx dx = uv − v du<br />
dx dx,<br />
∫<br />
∫<br />
sin x dx = − cos x, 9. cos x dx = sin x,<br />
∫<br />
∫<br />
∫<br />
tan x dx = − ln | cos x|, 11.<br />
sec x dx = ln | sec x + tan x|, 13.<br />
arcsin x a dx = arcsin x a + √ a 2 − x 2 , a > 0,<br />
∫<br />
∫<br />
cot x dx = ln | cos x|,<br />
csc x dx = ln | csc x + cot x|,