13.05.2014 Views

Ch 4 Notesheet Key

Ch 4 Notesheet Key

Ch 4 Notesheet Key

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

<strong>Ch</strong>apter 4:<br />

Discovering and Proving<br />

Triangle Properties<br />

Note Sheet<br />

S. Stirling Page 1 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

4.1 Triangles Sum Conjectures<br />

These notes replace pages 200 – 202 in the book. See step 4 of the Investigation.<br />

Rigidity is a property that triangles have. They cannot be shifted, like a quadrilateral can. They retain<br />

their shape.<br />

Triangulation is a procedure used by surveyors to locate a position by using triangles.<br />

Triangle Sum Conjecture<br />

The sum of the measures of the angles in every triangle is 180°.<br />

Numeric Example:<br />

Find x.<br />

A<br />

56<br />

B<br />

101<br />

101 + 56 + x = 180<br />

x = 180 – 157 = 23<br />

x<br />

C<br />

Find y.<br />

x + x + y = 180<br />

2x + y = 180<br />

y = 180 – 2x<br />

E<br />

x<br />

F<br />

x<br />

y<br />

D<br />

Third Angle Conjecture<br />

If two angles of one triangle are congruent to two angles of another triangle, then the third<br />

angles of the triangles are congruent.<br />

Numeric Example:<br />

If m∠ K = m∠Band m∠ I = m∠ C , find y. Give reasons for your answer!<br />

K<br />

101<br />

B<br />

A<br />

y<br />

56 23<br />

J<br />

I<br />

C<br />

y = 56 because the third angles are equal also.<br />

See <strong>Ch</strong> 4 Worksheet to prove these conjectures.<br />

S. Stirling Page 2 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

Lesson 4.2 Properties of Isosceles Triangles<br />

Read top of page 206. This vocabulary is review! Know it!!<br />

Remember! With If..then.. statements: If a, then b. The converse of the statement is If b, then a.<br />

Label and define the special vocabulary for the isosceles triangle Δ VBS .<br />

B<br />

A leg (of an isosceles triangle) is one of the congruent<br />

sides. VB and VS<br />

S<br />

The base (of an isosceles triangle) is the side that is not a<br />

leg. BS<br />

The vertex angle is the angle between the two legs.<br />

∠ V<br />

V<br />

The base angles are the pair of angles whose vertices are<br />

the endpoints of the base. ∠B<br />

and ∠ S<br />

Do group Investigation 1, Base angles of an Isosceles Triangle on page 207.<br />

Isosceles Triangle Conjecture<br />

If a triangle is isosceles, then its base angles are congruent.<br />

Given<br />

If VB<br />

ΔVBS<br />

with VB = VS , then ∠B ≅∠ S or<br />

≅ VS , then ∠B ≅ ∠ S .<br />

B<br />

V<br />

S<br />

***Note: Since equilateral triangles are a special case of isosceles triangles, any property<br />

that applies to isosceles triangles also apply to equilateral triangles.<br />

Do group Investigation 2, Is the Converse True? on page 208. Use a protractor.<br />

Converse of the Isosceles Triangle Conjecture<br />

If a triangle has two congruent angles, then it is an isosceles triangle.<br />

If ∠B ≅ ∠ S , then ΔVBS<br />

is isosceles or<br />

If ∠B ≅ ∠ S , then VB ≅ VS .<br />

V<br />

B<br />

S<br />

S. Stirling Page 3 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Lesson 4.3 Triangle Inequalities<br />

Read of page 215. Do group Investigation 1 on page 216.<br />

Name ___________________________<br />

Triangle Inequality Conjecture<br />

The sum of the lengths of any two sides of a triangle is greater than<br />

third side.<br />

Is a triangle measuring 5 cm, 4 cm and 2 cm<br />

possible? Construct it then explain!<br />

the length of the<br />

Is a triangle measuring 5 cm, 3 cm and 2 cm<br />

possible? Construct it then explain!<br />

Since 2 + 4 > 5, it makes a triangle.<br />

Since 2 + 3 = 5, it makes segment NOT<br />

a triangle.<br />

Do group Investigation 2, Largest and Smallest Angles in a Triangle? on page 217.<br />

Side-Angle Inequality Conjecture (Only applies to triangles!)<br />

In a triangle, if one side is the longest side, then the angle opposite the longest side is the<br />

largest angle.<br />

Likewise, if one side is the shortest side, then the angle opposite the shortest side is the<br />

smallest angle.<br />

Which is the largest angle? The smallest<br />

angle? Why?<br />

K<br />

J<br />

2.48<br />

6.3<br />

5.34<br />

I<br />

Which is the largest side? Why?<br />

∠D<br />

largest, so AQ<br />

largest in Δ ADQ ,<br />

But, m∠ QAU = 100<br />

D<br />

A<br />

90<br />

54<br />

23<br />

Q<br />

∠ K largest, its opposite the longest<br />

side, JI .<br />

∠I<br />

smallest, its opposite the shortest<br />

side, JK .<br />

which makes UQ the<br />

largest in ΔQAU<br />

and<br />

AQ < UQ.<br />

Overall, UQ is the longest.<br />

57<br />

U<br />

S. Stirling Page 4 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

Do group Investigation 3, Exterior Angle of a Triangle on page 217 – 218 .<br />

Label the drawing with the following terms and define the terms:<br />

Exterior angle is an angle that forms a linear pair<br />

with one of the interior angles of a polygon.<br />

Adjacent interior angle is the angle of a polygon<br />

that forms a linear pair with a given exterior angle of<br />

a polygon.<br />

The remote interior angles (of a triangle) are the<br />

interior angles of a triangle that do not share a vertex<br />

with a given exterior angle.<br />

Triangle Exterior Angle Conjecture<br />

The measure of an exterior angle of a triangle is equal to the sum of the measures of the<br />

remote interior angles.<br />

Given ΔABC<br />

above. If a = 50 and b = 60, what<br />

is the measure of ∠ BCD ? Explain.<br />

50 + 60 = 110<br />

The exterior angle equals the sum of the<br />

two remote interior angles.<br />

Given ΔABC<br />

above. If x = 80 and b = 30, what<br />

is the measure of ∠ A ? Explain.<br />

80 – 30 = 50<br />

The exterior angle equals the sum of the<br />

two remote interior angles.<br />

Before starting Lesson 4.4:<br />

Vocab for triangles Triangles have 6 “parts”.<br />

∠A<br />

is opposite BC and AC is opposite ∠ B<br />

∠A<br />

is between BA and AC (angles are between sides)<br />

BC is between<br />

∠ B and ∠ C (sides are between angles)<br />

included angle is an angle formed between two consecutive<br />

sides of a polygon.<br />

B<br />

A<br />

C<br />

included side is a side of a polygon between two consecutive angles.<br />

S. Stirling Page 5 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

Read the top of page 221, then complete the Triangle Congruence Shortcut Investigation, page 1 – 3.<br />

SSS Congruence Conjecture<br />

If the three sides of one triangle are congruent to the three sides of another triangle, then<br />

the triangles are congruent.<br />

A<br />

D<br />

O<br />

A<br />

G<br />

C<br />

T<br />

ΔCAT<br />

≅ Δ _______<br />

By SSS Congruence Conjecture.<br />

C<br />

T<br />

O<br />

ΔCAT<br />

≅Δ _______<br />

By SSS Congruence Conjecture.<br />

SAS Congruence Conjecture<br />

If two sides and the included angle of one triangle are congruent to two sides and the<br />

included angle of another triangle, then the triangles are congruent.<br />

A<br />

I<br />

P<br />

I<br />

Z<br />

C<br />

T Z P<br />

ΔPIZ<br />

≅ Δ _______<br />

By SAS Congruence Conjecture.<br />

E<br />

D<br />

ΔZED<br />

≅Δ _______<br />

By SAS Congruence Conjecture.<br />

ASA Congruence Conjecture<br />

If two angles and the included side of one triangle are congruent to two angles and the<br />

included side of another triangle, then the triangles are congruent.<br />

D<br />

O<br />

I<br />

O<br />

G<br />

Z<br />

P<br />

ΔDOG<br />

≅ Δ _______<br />

By ASA Congruence Conjecture.<br />

C<br />

P<br />

A<br />

ΔCOP<br />

≅Δ _______<br />

By ASA Congruence Conjecture.<br />

S. Stirling Page 6 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

SAA or AAS Congruence Conjecture<br />

If two angles and a non-included side of one triangle are congruent to the corresponding<br />

angles and side of another triangle, then the triangles are congruent.<br />

D<br />

O I<br />

G<br />

Z<br />

P<br />

ΔPIZ<br />

≅ Δ _______<br />

By SAS Congruence Conjecture.<br />

ΔCAP<br />

≅Δ _______<br />

P<br />

A<br />

T<br />

C<br />

By SAS Congruence Conjecture.<br />

Special Case: Hypotenuse Leg Congruence Conjecture<br />

If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one<br />

leg of another right triangle, then the two triangles are congruent.<br />

D<br />

O<br />

I<br />

O<br />

G<br />

Z<br />

P<br />

ΔDOG<br />

≅ Δ _______<br />

By HL Congruence Conjecture.<br />

C<br />

P<br />

A<br />

ΔCOP<br />

≅Δ _______<br />

By HL Congruence Conjecture.<br />

SSA or ASS Congruence?<br />

If two sides and the non-included angle of one triangle are congruent to two sides and the<br />

non-included angle of another triangle, then the triangles are NOT necessarily congruent.<br />

A<br />

I<br />

Draw a counterexample.<br />

I<br />

C<br />

T Z<br />

P<br />

ΔZIP<br />

≅ Δ _______<br />

By NOT necessarily congruent.<br />

Z<br />

P<br />

S. Stirling Page 7 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

AAA Congruence Conjecture<br />

If three angles of one triangle are congruent to the corresponding angles of another<br />

triangle, then the triangles are NOT necessarily congruent.<br />

A<br />

I<br />

Draw a counterexample.<br />

I<br />

C<br />

T Z<br />

P<br />

ΔZIP<br />

≅ Δ _______<br />

By NOT necessarily congruent.<br />

Z<br />

P<br />

How do you get equal parts in order to get congruent triangles?<br />

To see if you have congruent triangles, you will be checking for a SSS, SAS, ASA or AAS marked on the matching pair of<br />

triangles that you be given (as shown above). Sometimes the parts will be marked equal in the diagram. That’s the easy stuff.<br />

Other times, you will be given information that you will “translate” into equal sides and angles in order to get your<br />

congruence. You will need to deduce this information from definitions or conjectures that you already know to be true.<br />

Complete the following to help you review these statements. Remember, to mark your diagrams with the equal parts. Also<br />

never assume things are congruent! You must have a definitions or conjecture to back you up!!<br />

Ways to Get Equal Segments<br />

Converse of the Isosceles Triangle Conj.<br />

If a triangle has two congruent angles,<br />

then it is an isosceles triangle. V S<br />

Def. Isosceles Triangle<br />

If a triangle is isosceles,<br />

then its legs are congruent.<br />

V<br />

S<br />

If ∠B ≅ ∠ S ,<br />

≅ VS<br />

then VB<br />

B<br />

ΔVBS<br />

If isosceles<br />

then VB ≅ VS .<br />

B<br />

Def. Midpoint<br />

If a point is a midpoint,<br />

then it divides the segment into<br />

two equal segments.<br />

If M is the midpoint of SG ,<br />

then SM ≅ MG .<br />

S<br />

M<br />

G<br />

Def. segment bisector<br />

If a line (or part of a line) is a bisector,<br />

then it passes through the<br />

midpoint of the segment.<br />

If CM bisects AB ,<br />

≅ MB .<br />

then AM<br />

A<br />

C<br />

M<br />

B<br />

“Same Segment”<br />

When two triangles share<br />

the exact same segment, you get<br />

a pair of equal segments.<br />

ΔBET<br />

and ΔWTE<br />

ET ≅ TE<br />

share<br />

B<br />

E<br />

O<br />

T<br />

W<br />

Def. Median<br />

If a segment is a median,<br />

then it connects the vertex to the<br />

midpoint of the opposite side.<br />

If AM is median in Δ ABC ,<br />

then BM ≅ MC .<br />

A<br />

B<br />

M<br />

C<br />

S. Stirling Page 8 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Isosceles Triangle Conjecture<br />

If a triangle is isosceles,<br />

then its base angles are congruent.<br />

ΔVBS<br />

If isosceles<br />

or VB ≅ VS ,<br />

then ∠B ≅ ∠ S .<br />

Definition of Angle Bisector<br />

If you have an angle bisector,<br />

then the ray cuts the angle<br />

into two equal angles.<br />

<br />

If BD bisects ∠ ABC<br />

then ∠ABD ≅ ∠ DBC .<br />

Def. Altitude<br />

If a segment is an altitude,<br />

then it goes from a vertex<br />

perpendicular to the line that<br />

contains the opposite side.<br />

Δ TRI<br />

∠ = ∠ = °.<br />

If RA is an altitude of<br />

then m RAT m RAI 90<br />

“Same Angle”<br />

When two triangles share<br />

the exact same angle, you get<br />

a pair of equal angles.<br />

ΔTIA<br />

and ΔNIR<br />

∠TIA<br />

≅ ∠ RIN .<br />

T<br />

share<br />

T<br />

B<br />

V<br />

B<br />

R<br />

Name ___________________________<br />

Ways to Get Equal Angles<br />

I<br />

G<br />

R<br />

A<br />

S<br />

C<br />

A<br />

A<br />

D<br />

I<br />

N<br />

Vertical Angle Conjecture<br />

If two angles are vertical,<br />

then they are congruent.<br />

If ∠VET<br />

and ∠CER<br />

then ∠VET ≅∠ CER .<br />

Def. perpendicular lines<br />

If two lines are perpendicular,<br />

then they intersect to form equal<br />

90° angles.<br />

If CD<br />

V<br />

C<br />

E<br />

are vertical,<br />

⊥ AB , then<br />

m∠ CMA= m∠ CMB = 90°.<br />

Corresponding Angles Conjecture<br />

If two parallel lines are cut by a transversal,<br />

then corresponding angles are congruent.<br />

<br />

<br />

If AB DC ,<br />

then ∠EFA ≅∠ FGD .<br />

Alternate Interior Angles Conjecture<br />

If two parallel lines are cut by a transversal,<br />

then alternate interior angles are congruent.<br />

<br />

If LK NJ ,<br />

then ∠KHM ≅∠ HMN .<br />

A<br />

D<br />

C<br />

N<br />

A<br />

L<br />

M<br />

G<br />

E<br />

M<br />

T<br />

F<br />

H<br />

R<br />

B<br />

D<br />

B<br />

C<br />

K<br />

J<br />

Ways to Get equal Angles and Sides<br />

Complete the Triangle<br />

Congruence Shortcut<br />

Investigation, page 4 – 5.<br />

Def. perpendicular bisector<br />

A line (or part of a line) that passes through<br />

the midpoint of a segment and<br />

is perpendicular to the segment.<br />

If CD is the perp. bisector of AB ,<br />

then AM ≅ MB<br />

∠ CMA =∠ CMB = °.<br />

and 90<br />

C<br />

A<br />

M<br />

B<br />

D<br />

S. Stirling Page 9 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

4.6 Corresponding Parts of Congruent Triangles<br />

Note: Once you can prove that two triangles are congruent, by using the conjectures above, then any of<br />

the corresponding parts will be equal.<br />

Definition of Congruent Triangles:<br />

If two triangles are congruent, then all of their corresponding parts (sides and angles) are<br />

congruent.<br />

Can also be stated “Corresponding Parts of Congruent Triangles are Congruent” or<br />

CPCTC.<br />

When you write congruent triangles you must match the corresponding vertices. (To show how the match up.)<br />

So if you know that ΔCAT<br />

≅ ΔDOG<br />

then you can say any of the following:<br />

∠C<br />

≅ ∠ D CA ≅ DO<br />

∠A<br />

≅ ∠ O AT ≅ OG<br />

∠T<br />

≅ ∠ G CT ≅ DG<br />

Examples: How to prove (show deductively) that parts are equal.<br />

First example, informal paragraph :<br />

P<br />

Know: ∠PAC ≅ ∠TAC<br />

and PA AT<br />

Is ∠PCA ≅ ∠ TCA ?<br />

≅ .<br />

A<br />

T<br />

The triangles share a side, so CA<br />

So…<br />

= CA of course.<br />

C<br />

ΔPAC<br />

≅ ΔTAC<br />

by SAS Congruence<br />

and ∠PCA ≅ ∠ TCA because CPCTC or Corresponding Parts of Congruent Triangles are<br />

Congruent.<br />

A bit more formal paragraph:<br />

Given: Z is midpoint of DI and EP .<br />

Z<br />

Prove: PI ≅ DE ?<br />

Z is midpoint of DI and EP was given, so<br />

IZ = ZD and PZ = ZE by Definition of Midpoint<br />

D<br />

E<br />

∠PZI<br />

≅ ∠ EZD by the Vertical Angles Conjecture (or vertical angles are congruent.)<br />

Therefore, ΔZIP ≅ ΔZDE<br />

by SAS Congruence and<br />

PI DE<br />

≅ because CPCTC or Corresponding Parts of Congruent Triangles are Congruent.<br />

P<br />

I<br />

S. Stirling Page 10 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

This one is tricky:<br />

Know: RE<br />

Is RE ≅<br />

EC<br />

TC and TR CE .<br />

? What is congruent?<br />

Name ___________________________<br />

RE TC given so ∠RET ≅ ∠ETC<br />

and<br />

TR CE given so ∠RTE ≅ ∠CET<br />

because parallel lines make equal alternate interior angles.<br />

TE = TE the triangles share a side,<br />

ΔTRE<br />

≅ ΔECT<br />

by ASA Congruence. So any of the corresponding sides are congruent.<br />

RE and EC are NOT corresponding sides. So, probably not equal.<br />

Note: you could say any of the following though: RE<br />

T<br />

R<br />

C<br />

≅ TC , RT ≅ EC or ∠R ≅ ∠ C .<br />

E<br />

This one is trickier! Start by un-overlapping possible pairs of congruent triangles:<br />

Given: LE = EP and LV = OP<br />

Prove: ∠ALP ≅ ∠ APL<br />

O<br />

A<br />

V<br />

E<br />

L<br />

P<br />

LE = EP so ∠ELP ≅ ∠ EPL If isosceles, then base angles are equal.<br />

LP = PL Same segment<br />

LV = OP Given information<br />

∠LOP<br />

≅ ∠PVL<br />

by SAS Congruence<br />

∠ALP<br />

≅ ∠ APL CPCTC<br />

Try Example A and Example B on <strong>Ch</strong> 4 Worksheet.<br />

S. Stirling Page 11 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

4.7 Flowchart Thinking<br />

4.7 Page 238 Example B Flowchart Proof<br />

Given: EC AC<br />

≅ and ER ≅ AR<br />

Prove: ∠A ≅ ∠ E<br />

Name ___________________________<br />

E<br />

R<br />

C<br />

EC<br />

Given<br />

≅<br />

AC<br />

A<br />

ER ≅ AR<br />

Given<br />

RC≅<br />

RC<br />

Same segment<br />

ΔREC<br />

≅ ΔRAC<br />

SSS Cong. Conj.<br />

∠A<br />

≅∠E<br />

CPCTC<br />

4.7 Page 239 Top. Explain why the angle bisector construction works. Flowchart Proof<br />

Given:<br />

∠ABC<br />

with BA ≅ BC and CD ≅ AD<br />

ABC<br />

Prove: BD is the angle bisector of<br />

∠ .<br />

BA ≅<br />

BC<br />

Given<br />

CD ≅ AD<br />

Given<br />

BD≅<br />

BD<br />

Same segment<br />

ΔBAD<br />

≅ ΔBCD<br />

SSS Cong. Conj.<br />

∠1≅∠2<br />

CPCTC<br />

BD is the angle bisector of<br />

∠ ABC .<br />

Def. of angle bisector<br />

S. Stirling Page 12 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

What do you need to know to get…<br />

You’ll need Equal Segments to get…<br />

Def. Isosceles Triangle<br />

If a triangle’s legs are congruent,<br />

then it is isosceles.<br />

If VB<br />

then<br />

≅ VS<br />

ΔVBS<br />

isosceles.<br />

B<br />

V<br />

S<br />

Def. Median<br />

If a segment connects the vertex to the<br />

midpoint of the opposite side,<br />

then it is a median.<br />

If BM ≅ MC ,<br />

then AM is median in<br />

A<br />

Δ ABC .<br />

B<br />

M<br />

C<br />

Def. Midpoint<br />

S<br />

If a point divides the segment into<br />

two equal segments,<br />

then it is a midpoint.<br />

If SM ≅ MG ,<br />

then M is the midpoint of SG .<br />

M<br />

G<br />

Def. segment bisector<br />

C<br />

If a line (or part of a line) passes through the<br />

midpoint of the segment,<br />

then it is a bisector.<br />

M<br />

If AM ≅ MB,<br />

A<br />

then CM bisects AB .<br />

B<br />

You’ll need Equal Angles to get…<br />

Converse of the Isosceles Triangle Conj.<br />

If a triangle has two congruent angles,<br />

then it is an isosceles triangle. V S<br />

If ∠B ≅ ∠ S ,<br />

ΔVBS<br />

then<br />

isosceles.<br />

B<br />

Def. perpendicular lines<br />

If two lines intersect to form equal<br />

adjacent angles,<br />

then they are perpendicular.<br />

If m∠ CMA= m∠ CMB ,<br />

⊥ AB .<br />

then CD<br />

C<br />

A<br />

M<br />

B<br />

D<br />

Definition of Angle Bisector<br />

If a ray cuts the angle into two<br />

equal angles, then you have<br />

an angle bisector.<br />

If ∠ABD ≅ ∠ DBC ,<br />

ABC<br />

then BD bisects ∠ .<br />

B<br />

C<br />

A<br />

D<br />

Corresponding Angles Conjecture<br />

If two lines are cut by a transversal and<br />

the corresponding angles are congruent,<br />

then the lines are parallel.<br />

If ∠EFA ≅∠ FGD ,<br />

<br />

DC<br />

then AB .<br />

A<br />

D<br />

G<br />

E<br />

F<br />

B<br />

C<br />

Def. Altitude<br />

If a segment goes from a vertex<br />

perpendicular to the line that<br />

contains the opposite side,<br />

then it is an altitude.<br />

If m∠ RAT = m∠ RAI = 90°,<br />

TRI<br />

then RA is an altitude of<br />

T<br />

R<br />

A<br />

Δ .<br />

I<br />

Alternate Interior Angles Conjecture<br />

If two lines are cut by a transversal and<br />

the alternate interior angles are congruent,<br />

then the lines are parallel.<br />

If ∠KHM ≅∠ HMN ,<br />

<br />

NJ<br />

then LK<br />

.<br />

L<br />

N<br />

M<br />

H<br />

K<br />

J<br />

S. Stirling Page 13 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

Name ___________________________<br />

You’ll need Equal Angles and Sides to get…<br />

Def. perpendicular bisector<br />

If a line (or part of a line) that passes through the midpoint of<br />

a segment and is perpendicular to the segment,<br />

then it is the perpendicular bisector.<br />

C<br />

If AM<br />

≅ MB and ∠ CMA = 90°,<br />

then CD is the perp. bisector of AB .<br />

A<br />

M<br />

B<br />

D<br />

Summary<br />

Basic Procedure for Proofs<br />

“parts” refers to sides and/or angles.<br />

1. Get equal parts by using given info. and known definitions and conjectures.<br />

2. State the triangles are congruent by SSS, SAS, ASA or AAS.<br />

3. Use CPCTC to get more equal parts.<br />

4. Connect that info. to what you were trying to prove .<br />

Hints [if you get stuck]:<br />

Mark the diagram with what you have stated as congruent in your proof.<br />

( If given M is the midpoint of AB , convert it to AM = MB by def. of<br />

midpoint before marking the diagram!)<br />

Look at the diagram to find equal parts.<br />

Brainstorm and then apply previous conjectures and definitions.<br />

Work (or think) backwards!<br />

Draw overlapping triangles separately.<br />

Re-draw figures without all of the “extra segments” in there.<br />

Draw an auxillary line.<br />

Break a problem into smaller parts.<br />

S. Stirling Page 14 of 15


<strong>Ch</strong> 4 Note Sheet L1 <strong>Key</strong><br />

4.8 Proving Special Triangle Conjectures<br />

Name ___________________________<br />

Equilateral/Equiangular Triangle Conjecture<br />

Every equilateral triangle is equiangular.<br />

Conversely, every equiangular triangle is equilateral.<br />

Vertex Angle Bisector Conjecture<br />

In an isosceles triangle, the bisector of the vertex angle is also the altitude and the median<br />

to the base and the perpendicular bisector of the base.<br />

Isosceles Triangle with vertex angle A, AB = AC.<br />

Median BM<br />

A<br />

Altitude BL<br />

L<br />

Angle Bisector BS<br />

AB = 3.36 in.<br />

AC = 3.36 in.<br />

CB = 4.34 in.<br />

C<br />

M<br />

S<br />

B<br />

Isosceles Triangle with Vertex Angle B<br />

B<br />

A<br />

EMD<br />

C<br />

Median BM<br />

AM = 1.64 in.<br />

MC = 1.64 in.<br />

Altitude BE<br />

m∠AEB = 90°<br />

Angle Bistector BD<br />

m∠ABD = 27°<br />

m∠DBC = 27°<br />

Medians to the Congruent Sides Theorem<br />

In an isosceles triangle, the medians to the congruent sides are congruent.<br />

Angle Bisectors to the Congruent Sides Theorem<br />

In an isosceles triangle, the angle bisectors to the congruent sides are congruent.<br />

Altitudes to the Congruent Sides Theorem<br />

In an isosceles triangle, the altitudes to the congruent sides are congruent.<br />

A<br />

A<br />

A<br />

N<br />

M<br />

S<br />

P<br />

T<br />

L<br />

C<br />

C<br />

C<br />

B<br />

B<br />

B<br />

Medians MC = BN Angle Bisectors PC = BS Altitudes BT = LC<br />

S. Stirling Page 15 of 15

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!