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Compounds - Mark Rosengarten

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Determining the % Of Water In A Hydrate Experimentally:<br />

(given mass of water in hydrate / given mass of hydrate) X 100%<br />

To determine the mass of the water that was driven out of the hydrate:<br />

Take the mass of the original hydrate and subtract from it the mass of the anhydride.<br />

To determine the percent of water in the hydrate:<br />

Divide the mass of the water driven off from the hydrate by the total mass of the hydrate and multiply by 100.<br />

2) A 10.40 gram sample of hydrated crystal is heated to a constant mass of 8.72 grams. This means all of the water<br />

has been driven out by the heat.<br />

a) Calculate the mass of water that was driven out:<br />

(mass of hydrate – mass of anhydride) = 10.40 grams – 8.72 grams = 1.68 grams of water driven off by the heat<br />

b) Calculate the percent, by mass, of water in this hydrate:<br />

(given mass of water in hydrate / given mass of hydrate) X 100 = (1.68 grams / 10.40 grams) X 100 = 0.162 X 100 =<br />

16.2% water by mass<br />

3) An empty evaporating dish is found to have a mass of 29.993 grams. A sample of hydrated crystal is placed into<br />

the evaporating dish, the combined mass is 39.486 grams. The evaporating dish is placed on a ringstand and heated<br />

gently over a Bunsen burner flame, stirring constantly so that the water does not cause the drying crystal to clump<br />

together. The dish is removed from the flame, and weighed, then reheated, then weighed again, until the mass<br />

remains a constant 38.378 grams.<br />

a) What was the mass of hydrated crystal that was put into the dish?<br />

Mass of hydrated crystal = (mass of crystal + dish) – (mass of dish) = 39.486 g – 29.993 g = 9.493 grams of hydrate<br />

b) What was the mass of water that was driven out of the hydrate?<br />

The total mass was 39.486 grams before heating, and 38.387 g after heating. The difference is the mass of water:<br />

39.486 g – 38.387 g = 1.099 grams of water driven off by the heat<br />

c) Calculate the percent, by mass, of water in the hydrate:<br />

(given mass of water in hydrate / given mass of hydrate) X 100 = (1.099 g / 9.493 g) X 100 = 0.116 X 100 =<br />

11.6% water by mass<br />

© 2011, <strong>Mark</strong> <strong>Rosengarten</strong> AE 18

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