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Paragraph Proofs - mdk12

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6. Quadrilateral ABCD is inscribed in circle O. There are<br />

360º in a circle, so m ABC + m CDA = 360º and the<br />

m BCD + m DAB = 360º. By the division property of<br />

1 1<br />

equality, m ABC + m CDA = 180º and<br />

2 2<br />

1 1 m BCD + m DAB = 180º.<br />

2 2<br />

1 1<br />

The m ∠ D = m ABC, m ∠ B = m CDA,<br />

2 2<br />

1 1<br />

m∠ A = m BCD, and m ∠ C = m DAB because the<br />

2 2<br />

measure of an inscribed angle is one-half the measure of its<br />

intercepted arc. m ∠ D + m ∠ B = 180º and m ∠ A + m ∠ C<br />

= 180º by substitution. Therefore, ∠ A is supplementary to<br />

∠C<br />

and ∠ B is supplementary to ∠D<br />

by definition of<br />

supplementary angles.<br />

7. AB is parallel to CD . Draw AD . ∠ BAD ≅ ∠CDA<br />

because if two parallel lines are cut by a transversal, the<br />

alternate interior angles are congruent. ∠ BAD = ∠CDA<br />

1<br />

by the definition of congruent angles. m ∠ BAD = m BD 2<br />

1<br />

and m ∠ CDA = m AC because the measure of an<br />

2<br />

inscribed angle is one-half the measure of its intercepted<br />

arc. 2<br />

1 m BD = 2<br />

1 m AC by substitution. The measure of<br />

BD = m AC by the multiplication property of equality.<br />

Therefore, AC ≅ BD by the definition of congruent arcs.<br />

Lesson Plan: Different Methods of Proof<br />

Page 4

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