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Chapter 10 - An Introduction to Chemistry: Chemical Calculations ...

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<strong>Chapter</strong> Problems 397<br />

24. The bond between nitrogen a<strong>to</strong>ms in N 2 molecules is very strong, making N 2<br />

very unreactive. Because of this, magnesium is one of the few metals that react<br />

with nitrogen gas directly. This reaction yields solid magnesium nitride.<br />

a. Write a complete balanced equation, without including states, for the<br />

reaction between magnesium and nitrogen <strong>to</strong> form magnesium nitride.<br />

b. Write a conversion fac<strong>to</strong>r that could be used <strong>to</strong> convert between moles of<br />

magnesium and moles of magnesium nitride.<br />

c. How many moles of magnesium nitride form when 1.0 mole of magnesium<br />

reacts completely?<br />

d. Write a conversion fac<strong>to</strong>r that could be used <strong>to</strong> convert between moles of<br />

nitrogen and moles of magnesium nitride.<br />

e. How many moles of nitrogen react <strong>to</strong> yield 3.452 moles of magnesium<br />

nitride?<br />

25. Fluorine gas is an important chemical because it is used <strong>to</strong> add fluorine a<strong>to</strong>ms <strong>to</strong><br />

many different compounds. As mentioned in Problem 22, it is difficult <strong>to</strong> make,<br />

but the following two-step process produces fairly high yields of F 2 .<br />

Objective 2<br />

Objective 3<br />

Objective 2<br />

Objective 3<br />

2KMnO 4 + 2KF + <strong>10</strong>HF + 3H 2 O 2 → 2K 2 MnF 6 + 8H 2 O + 3O 2<br />

2K 2 MnF 6 + 4SbF 5 → 4KSbF 6 + 2MnF 3 + F 2<br />

For the second of these two reactions:<br />

a. Write a conversion fac<strong>to</strong>r that could be used <strong>to</strong> convert between moles of<br />

antimony pentafluoride, SbF 5 , and moles of fluorine, F 2 .<br />

b. How many moles of F 2 form when 8 moles of SbF 5 react completely?<br />

c. What is the maximum number of moles of F 2 that could form in the<br />

combination of 2.00 moles of K 2 MnF 6 and 5.00 moles of SbF 5 ?<br />

d. What is the maximum number of moles of F 2 that could form in the<br />

combination of 2 moles of K 2 MnF 6 and 5000 moles of SbF 5 ?<br />

e. Write a conversion fac<strong>to</strong>r that could be used <strong>to</strong> convert between moles of<br />

manganese(III) fluoride, MnF 3 , and moles of F 2 .<br />

f. How many moles of F 2 form along with 0.802 mole of MnF 3 ?<br />

26. For many years, it was thought that no reaction could produce sodium<br />

perbromate, but the discovery of a reaction producing the equally elusive xenon<br />

difluoride, XeF 2 , led <strong>to</strong> the discovery of the following reaction that yields<br />

sodium perbromate.<br />

NaBrO 3 + XeF 2 + H 2 O<br />

→ NaBrO 4 + 2HF + Xe<br />

a. Write a conversion fac<strong>to</strong>r that could be used <strong>to</strong> convert between moles of<br />

xenon difluoride, XeF 2 , and moles of hydrogen fluoride, HF.<br />

b. How many moles of XeF 2 are necessary <strong>to</strong> form 16 moles of hydrogen<br />

fluoride?<br />

c. What is the maximum number of moles of NaBrO 4 that could form in the<br />

combination of 2 moles of NaBrO 3 and 3 moles of XeF 2 ?<br />

d. What is the maximum number of moles of NaBrO 4 that could form in the<br />

combination of 2 moles of NaBrO 3 and 3 million moles of XeF 2 ?<br />

e. Write a conversion fac<strong>to</strong>r that could be used <strong>to</strong> convert between moles of<br />

sodium perbromate, NaBrO 4 , and moles of hydrogen fluoride, HF.<br />

f. How many moles of HF form along with 5.822 moles of sodium<br />

perbromate, NaBrO 4 ?<br />

Objective 2<br />

Objective 3

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