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Chapter 20: Metals and Their Compounds

Chapter 20: Metals and Their Compounds

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of the valence electrons by putting them lower in energy<br />

wells. The filled shells of the noble gases (helium,<br />

neon, argon, etc.) are particularly low energy arrangements<br />

of the electrons. These elements do not react<br />

with other elements because the reaction does not provide<br />

a means to an overall lowering of the electron energies.<br />

The effective oxidation state of the noble gases is<br />

identically zero. Many ions achieve this “noble gas<br />

electron configuration,” but of course no change has<br />

been made to the nucleus.<br />

In general, metallic elements near the left of the<br />

Periodic Table assume positive oxidation states in<br />

chemical reactions. Nonmetallic elements near the right<br />

side of the Periodic Table assume negative oxidation<br />

states. Near the middle of the Periodic Table things are<br />

somewhat ambiguous. Will an element like carbon<br />

(which has four valence electrons) lose its four valence<br />

electrons (like a metal), or gain four to fill its shell (like<br />

a nonmetal)? The answer depends on the specific compound<br />

that is being formed. An element in the middle,<br />

such as carbon, will do whichever best lowers its electron<br />

energy. Thus, for elements near the middle of the<br />

chart there is a tendency for atoms to assume different<br />

oxidation states in different chemical reactions, depending<br />

on the particular compound which is being formed.<br />

Although many elements can have more than one<br />

oxidation state (depending on the compound), the primary<br />

(likely) oxidation state is related to the atom’s position<br />

in the Periodic Table. All of the elements in column<br />

1 (labeled IA in the Periodic Table) will have an oxidation<br />

state of +1 in ionic compounds. Elements in IIA<br />

have +2 oxidation states. What would you predict for<br />

column IIIA? Check your answer in Figure <strong>20</strong>.4.<br />

Elements in columns VIA <strong>and</strong> VIIA of the Periodic<br />

Table tend to gain electrons to fill their valence shells<br />

<strong>and</strong> can be predicted with confidence to have primary<br />

oxidation states of –2 <strong>and</strong> –1, respectively. Elements in<br />

these columns sometimes have additional possible oxidation<br />

states in compounds. See sulfur <strong>and</strong> chlorine in<br />

Figure <strong>20</strong>.4, for example.<br />

Elements in the B columns of the Periodic Table are<br />

also prone to having more than one possible oxidation<br />

state. However, we can use the additional information<br />

that these elements are all metals (<strong>and</strong>, therefore, tend to<br />

be electron donors) to predict that at least in some compounds<br />

these elements will have positive oxidation<br />

states that correspond directly to the number of valence<br />

electrons indicated by their column number. For example,<br />

chromium ( 24 Cr) in column VIB will in at least<br />

some cases have an oxidation state of +6. The rule is<br />

even less precise for the elements in the centermost<br />

columns of the Periodic Table (labeled VIII [neither A<br />

nor B]). Here we can only predict that, as metals, the<br />

elements will have positive oxidation states, but we<br />

must rely on experimental analysis of the individual<br />

compounds to determine the precise oxidation states of<br />

the constituent elements.<br />

Why do the regularities exist among the elements?<br />

They are based on ionization energies whose precise values<br />

can be traced back to the Wave Model <strong>and</strong> the<br />

Exclusion Principle. If only one electron in an atom has<br />

a low ionization energy, the oxidation state will be +1. If<br />

two electrons have low ionization energies, the oxidation<br />

state will be +2, <strong>and</strong> so on. If there are no electrons with<br />

low ionization energies, but there is a vacancy in an<br />

orbital deep in the well, the atom will try to fill the vacancy<br />

with an electron. This results in a –1 oxidation state.<br />

<strong>Compounds</strong> Between <strong>Metals</strong> <strong>and</strong> Nonmetals<br />

Imagine a metallic sodium ion, Na + , <strong>and</strong> a nonmetallic<br />

chloride ion, Cl – , that could form an ionic bond. But<br />

why should the pairing stop there? Could the Na + attract<br />

another negative ion <strong>and</strong> the Cl – attract another positive<br />

ion? Yes. Long chains of alternating Na + <strong>and</strong> Cl – ions<br />

form a sheet like a checkerboard (Fig. <strong>20</strong>.5), <strong>and</strong> finally<br />

the checkerboards stack so that positive ions are always<br />

above negative ions <strong>and</strong> vice versa. The result is a crystal<br />

of salt based on the electrical attraction of the ions.<br />

Figure <strong>20</strong>.5. Drawing of a small part of a single layer<br />

of a NaCl (sodium chloride) crystal.<br />

A salt is much different than a metal. Ionic bonding<br />

accounts for the characteristics of salts discussed<br />

below.<br />

1. Electrically nonconducting. The electrons in<br />

both ions of a salt are all in stable, closed<br />

shells, <strong>and</strong> are difficult to remove from their<br />

respective ions. Because there are no mobile<br />

electrons, solid salts have no way to conduct<br />

electricity. However, if the salt is melted,<br />

whole ions may move about <strong>and</strong> conduct electricity,<br />

but they are so big <strong>and</strong> awkward they<br />

are not nearly as conductive as the electrons in<br />

a metal. Also, if the salt is dissolved in a liquid<br />

like water, the ions separate <strong>and</strong> are able to<br />

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