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How Matter Emits Light: 1. the Blackbody Radiation

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<strong>How</strong> <strong>Matter</strong> <strong>Emits</strong><br />

<strong>Light</strong>:<br />

<strong>1.</strong> <strong>the</strong> <strong>Blackbody</strong><br />

<strong>Radiation</strong>


Announcements<br />

n Quiz # 3 will take place on Thursday, October<br />

20 th ; more infos in <strong>the</strong> link `quizzes’ of <strong>the</strong><br />

website:<br />

¨ Please, remember to bring a pencil.<br />

n Solutions for Exam # 1 are available from <strong>the</strong><br />

website, under `Exam<br />

n Looking ahead:<br />

¨ Homework # 3 is due on Thursday, Oct. 20 th<br />

¨ Homework # 4 starts on Thursday, Oct 20 th . It is due<br />

on Thursday, Oct. 27 th


Assigned Reading<br />

n Complete Unit 22;<br />

n Unit 23


Dimming with distance<br />

n As you move away from a light source (a<br />

light bulb, a street light, etc.) it becomes<br />

dimmer. Why?<br />

The energy emitted by<br />

<strong>the</strong> source is constant,<br />

but get spread over a<br />

larger surface at larger<br />

distance


Dimming with Distance<br />

n As distance R increases, <strong>the</strong> area over<br />

which <strong>the</strong> total light output L is distributed<br />

increases as 4πR 2<br />

n Thus:<br />

Brightness = ______ L<br />

4πR 2


<strong>How</strong> <strong>Matter</strong> and <strong>Light</strong> Interact


<strong>Matter</strong> interacts with light in four<br />

different ways:<br />

n Absorption – <strong>the</strong> energy in <strong>the</strong> photon is<br />

absorbed by <strong>the</strong> matter and turned into <strong>the</strong>rmal<br />

energy<br />

n E.g., Your hand feels warm in front of a fire.<br />

n Reflection – no energy is transferred and <strong>the</strong><br />

photon bounces off in a new (and predictable)<br />

direction<br />

n E.g., Your bathroom mirror<br />

n Transmission – no energy is transferred and <strong>the</strong><br />

photon passes through <strong>the</strong> matter unchanged.<br />

n Emission – matter gives off light. Can be done in<br />

two different ways, as we will see.


Absorption<br />

Photon deposits energy into material. Thermal energy is increased<br />

and <strong>the</strong> material gets warmer.


Transmission<br />

Photon passes through material without depositing energy. Everything<br />

remains unchanged.


Reflection<br />

Photon reflects off of material. No energy is lost but outgoing photon<br />

has a new direction.


These processes depend on both<br />

<strong>the</strong> material and <strong>the</strong> wavelength of<br />

<strong>the</strong> photon


Survey Question<br />

Our eyes work via <strong>the</strong> process of:<br />

1) absorption<br />

2) reflection<br />

3) transmission<br />

4) emission<br />

5) none of <strong>the</strong> above


Survey Question<br />

Leaves are green because:<br />

1) <strong>the</strong>y only emit frequencies corresponding to<br />

green<br />

2) <strong>the</strong>y only reflect frequencies corresponding to<br />

green<br />

3) <strong>the</strong>y only transmit frequencies corresponding<br />

to green<br />

4) <strong>the</strong>y only absorb frequencies corresponding<br />

to green


The Difference Between Black and<br />

White<br />

n White light – contains all <strong>the</strong> frequencies<br />

of <strong>the</strong> visible part of <strong>the</strong> spectrum.<br />

n White paint – reflects all frequencies of <strong>the</strong><br />

visible part of <strong>the</strong> spectrum equally.<br />

n Black paint – absorbs all frequencies of <strong>the</strong><br />

visible part of <strong>the</strong> spectrum equally.


Discussion Question<br />

Why does NASA paint spacecraft white?<br />

80%<br />

Absorption Spectrum<br />

of Black Paint<br />

Absorption<br />

40%<br />

0%<br />

Infrared<br />

Visible<br />

Absorption Spectrum<br />

of White Paint<br />

Frequency


Emission: <strong>How</strong> do objects make<br />

light in <strong>the</strong> first place?<br />

n There are two principal mechanisms for<br />

producing electromagnetic radiation<br />

¨ <strong>Blackbody</strong> radiation<br />

¨ Spectral line emission of atoms and<br />

molecules<br />

Both of <strong>the</strong>se mechanisms result from<br />

accelerating/decelerating electrons! I.e., you<br />

accelerate or decelerate an electric charge to<br />

create EM radiation


<strong>Light</strong> from Objects<br />

n We perceive this `acceleration or `deceleration of<br />

electrons as `light from objects<br />

n Imagine to heat up a piece of metal in a furnace:<br />

¨ It will first turn red (temperature raising)<br />

¨ <strong>the</strong>n orange<br />

¨ <strong>the</strong>n yellow<br />

¨ <strong>the</strong>n whitish-blue (highest temperature)<br />

The higher <strong>the</strong> temperature, <strong>the</strong> bluer <strong>the</strong><br />

object will appear<br />

[you are linking temperature to color!]


What happens?<br />

n The higher <strong>the</strong> temperature, <strong>the</strong> faster <strong>the</strong> atoms/<br />

molecules in <strong>the</strong> object are (T ~ v 2 ), thus more energetic<br />

collisions<br />

n More energetic collisions cause more sudden<br />

accelerations/decelerations of <strong>the</strong> electrons in <strong>the</strong><br />

matter, thus light with shorter wavelength (higher energy)


What does it mean?<br />

n Higher Temperature = faster atoms<br />

n Faster atoms = more frequent and<br />

energetic collisions<br />

n more frequent and energetic collisions =<br />

more sudden electron accelerations/decel<br />

n more sudden electron accelerations/decel<br />

= higher photon energy<br />

n Higher photon energy = bluer light<br />

(E=hc/λ)


The color of light emitted is<br />

connected to <strong>the</strong> Temperature


<strong>How</strong> to Measure Temperature<br />

n<br />

n<br />

n<br />

<br />

¨ <br />

<br />

¨ <br />

<br />

¨ <br />

¨ <br />

<br />

¨ <br />

¨ <br />

<br />

¨ <br />

¨


Do not confuse Heat and<br />

Temperature!<br />

n<br />

n<br />

Temperature refers to <strong>the</strong><br />

degree of motion of <strong>the</strong><br />

particles in a material, i.e.<br />

<strong>the</strong> speed with which <strong>the</strong><br />

particles move (T~kinetic<br />

energy~v 2 ). <br />

Heat refers to <strong>the</strong> amount of<br />

energy stored in a body as<br />

motion among its particles<br />

and depends on density as<br />

well as temperature.


Survey Question:<br />

n You heat an oven to 450 F, and you also, separately,<br />

boil some water in a pot (boiling point is 212 F). What<br />

happens if you stick your hand first in <strong>the</strong> oven and <strong>the</strong>n<br />

in <strong>the</strong> boiling water [dont do that!]? Why?<br />

I get burned in both<br />

I only get burned in <strong>the</strong> oven, because of <strong>the</strong> higher<br />

temperature<br />

I only get burned in <strong>the</strong> water, because of <strong>the</strong> higher<br />

heat


Survey Question:<br />

n You heat an oven to 450 F, and you also, separately,<br />

boil some water in a pot (boiling point is 212 F). What<br />

happens if you stick your hand first in <strong>the</strong> oven and <strong>the</strong>n<br />

in <strong>the</strong> boiling water [dont do that!]? Why?<br />

I get burned in both<br />

I only get burned in <strong>the</strong> oven, because of <strong>the</strong> higher<br />

temperature<br />

I only get burned in <strong>the</strong> water, because of <strong>the</strong> higher<br />

heat


What is a <strong>Blackbody</strong>?<br />

n An object that can absorb all <strong>the</strong> radiation falling on it<br />

(light at all wavelengths), so it appears black when cold<br />

n When it gets heated up, it can also emit radiation at all<br />

wavelengths (think of <strong>the</strong> heated piece of metal).<br />

n A stove burner (conducting material), a furnace, planets<br />

(radiating solids), and stars (dense gas) are excellent<br />

examples of close-to-blackbodies<br />

n Materials that are insulating, non-burning, or liquid are<br />

usually not good blackbodies


<strong>Blackbody</strong> <strong>Radiation</strong><br />

n<br />

n<br />

n<br />

n<br />

n<br />

Take a blackbody (e.g., a piece of metal)<br />

and heat it up.<br />

After it becomes hot, keep <strong>the</strong> temperature<br />

constant (this is called <strong>the</strong>rmal equilibrium)<br />

Then plot, on a graph, <strong>the</strong> intensity of <strong>the</strong><br />

radiation (light) emitted as a function of<br />

wavelength: this is called a spectrum<br />

The shape of <strong>the</strong> spectrum and <strong>the</strong> maximum intensity of a<br />

<strong>Blackbody</strong> will only depend on <strong>the</strong> Temperature<br />

Think of Temperature as motion of <strong>the</strong> atoms/molecules in <strong>the</strong><br />

blackbody; if T=constant, <strong>the</strong> motion does not change, and <strong>the</strong><br />

acceleration/deceleration of <strong>the</strong> electrons also does not change. The<br />

`color of <strong>the</strong> B.B. will not change.<br />

Black Body radiation is <strong>the</strong> e.m. emission of matter at<br />

<strong>the</strong>rmal equilibrium (constant T)


One Temperature=one spectrum<br />

Blackbodies are excellent <strong>the</strong>rmometers


Wien’s Law<br />

n Hotter objects emit photons with a<br />

higher average energy = shorter<br />

wavelength.<br />

¨ The peak of <strong>the</strong> blackbody emission spectrum is<br />

given by<br />

" max<br />

=<br />

2.9 #106<br />

T(Kelvin) nm


Stefan-Boltzmann Law:<br />

n Hotter objects emit more total radiation per<br />

unit surface area.<br />

n The luminosity of a hot body rises rapidly<br />

with Temperature: L=A σT 4


Survey Question<br />

The graph below shows <strong>the</strong> blackbody spectra of three different<br />

o<strong>the</strong>rwise identical stars. Which of <strong>the</strong> stars is at <strong>the</strong> highest<br />

temperature?<br />

1) Star A<br />

2) Star B<br />

3) Star C A<br />

Relative<br />

Intensity<br />

B<br />

C<br />

Wavelength


Survey Question:<br />

Emitted power = σ A T 4<br />

You are gradually heating two rocks (one larger than <strong>the</strong><br />

o<strong>the</strong>r) in an oven to an extremely high temperature. As<br />

<strong>the</strong>y heat up, <strong>the</strong> rocks emits nearly perfect <strong>the</strong>oretical<br />

blackbody radiation – meaning that<br />

1) <strong>the</strong> larger rock is bluer and brighter.<br />

2) <strong>the</strong> larger rock is redder and brighter.<br />

3) <strong>the</strong> larger rock is bluer but <strong>the</strong> same brightness.<br />

4) <strong>the</strong> larger rock is <strong>the</strong> same color but brighter.<br />

5) <strong>the</strong> larger rock is <strong>the</strong> same color and brightness.


Survey Question:<br />

Emitted power = σ A T 4<br />

You are gradually heating two rocks (one larger than <strong>the</strong><br />

o<strong>the</strong>r) in an oven to an extremely high temperature. As<br />

<strong>the</strong>y heat up, <strong>the</strong> rocks emits nearly perfect <strong>the</strong>oretical<br />

blackbody radiation – meaning that<br />

1) <strong>the</strong> larger rock is bluer and brighter.<br />

2) <strong>the</strong> larger rock is redder and brighter.<br />

3) <strong>the</strong> larger rock is bluer but <strong>the</strong> same brightness.<br />

4) <strong>the</strong> larger rock is <strong>the</strong> same color but brighter.<br />

5) <strong>the</strong> larger rock is <strong>the</strong> same color and brightness.


Survey Question<br />

The graph below shows <strong>the</strong> blackbody spectra of two totally<br />

different stars. What can you conclude from <strong>the</strong> plot about<br />

<strong>the</strong> two stars?<br />

1) Star A is hotter but smaller than Star B<br />

2) Star A is hotter and larger than Star B<br />

3) Star A is cooler and larger than Star B<br />

4) Star A is cooler and smaller than Star B<br />

Relative<br />

Intensity<br />

A<br />

B<br />

Wavelength


Summary<br />

n <strong>Blackbody</strong> <strong>Radiation</strong> (a.k.a. Thermal<br />

<strong>Radiation</strong>)<br />

¨ Many objects with a temperature greater than<br />

absolute zero (0 K) emit blackbody radiation.<br />

¨ Hotter objects emit more total radiation per<br />

unit surface area.<br />

¨ Hotter objects emit photons with a higher<br />

average energy.


Survey Question<br />

n You emit radiation:<br />

¨<br />

¨<br />

True<br />

False


Survey Question<br />

n You emit radiation:<br />

¨<br />

¨<br />

True<br />

False<br />

Your skin feels warm, you emit infrared<br />

radiation

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