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Topics in Classical Electrodynamics

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and, therefore,<br />

⎛<br />

F µν = η µσ η νρ F σρ<br />

⎜<br />

⎝<br />

0 −E x −E y −E z<br />

E x 0 −H z H y<br />

E y H z 0 −H x<br />

E z −H y H x 0<br />

⎞<br />

⎟<br />

⎠ , (38)<br />

where we have def<strong>in</strong>ed the F 0i components to be the electric fields and the<br />

F ij components to the magnetic fields. From the electric and magnetic fields<br />

one can make <strong>in</strong>variants, i.e. objects that rema<strong>in</strong> unchanged under Lorentz<br />

transformations. In terms of the tensor of th electromagnetic field two such<br />

<strong>in</strong>variants are<br />

F µν F µν = <strong>in</strong>v ; (39)<br />

ε µνρσ F µν F ρσ = <strong>in</strong>v . (40)<br />

Let us <strong>in</strong>spect the gauge <strong>in</strong>variance of the electric and magnetic fields ⃗ E and<br />

⃗H, which from the form and their <strong>in</strong> terms of the electromagnetic field tensor<br />

components can be expressed <strong>in</strong> terms of the vector potential as<br />

⃗E = − ⃗ ∇ϕ − 1 c<br />

∂ ⃗ A<br />

∂t<br />

and ⃗ H = rot ⃗ A . (41)<br />

One can easily see that <strong>in</strong> the first case an extra ϕ term cancels with an extra<br />

⃗A term and <strong>in</strong> the second case we have the gauge transformation contribution<br />

vanish<strong>in</strong>g due to the fact that rot gradχ = 0. We look back at the expression<br />

for the Lorentz force and try to write it <strong>in</strong> terms of electric and magnetic<br />

fields. Rearrang<strong>in</strong>g (33), we get<br />

dp i<br />

dt<br />

=<br />

=<br />

( e<br />

c F i0 U 0 + e ) ds<br />

c F ij U j<br />

dt =<br />

⎛<br />

⎞<br />

⎝ e 1<br />

c Ei √ + e √<br />

1 −<br />

c F ij ⃗v<br />

√ ⎠ c 1 − ⃗v2<br />

⃗v2 c 1 −<br />

c . (42)<br />

2 ⃗v2<br />

c 2 c 2<br />

We can thus rewrite the expression for the Lorentz force as<br />

dp i<br />

dt = eEi + e [<br />

⃗v, H<br />

c<br />

⃗ ]<br />

. (43)<br />

26

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