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1 Upper-Lower Solution Method for Differential Riccati Equations ...

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8<br />

aEßGßKb Ä aE FOßG HO, ZaObb. (20)<br />

There<strong>for</strong>e, a representation <strong>for</strong> N O follows from (17) under replacement (20); that is,<br />

NO<br />

œ D X T ab =D€I( B X aT € Z aO b€ _ aOàTbbB.><br />

, (21)<br />

where _aOàT b is L aT<br />

b defined (5) under replacement (20), namely,<br />

=<br />

><br />

"<br />

w<br />

X<br />

X<br />

_aOàTbœ aE FOb T€TaE FO b€ aG HOb TaG HObÞ<br />

(22)<br />

Propositions 4 and 5 below reveal some important structural properties of LQaT b.<br />

Proposition 4. Suppose T­P "ß_ a 8<br />

Mß b _ 5‚8<br />

’ is feasible and O ­ P aMß‘<br />

b. Let LQ a T b , Z a O b and<br />

_aOàT b be defined in (5), (19) and (22), respectively. Then<br />

(i) LQ aT b€ a^aTb Ob X e aTba^aTb<br />

Ob<br />

œ Z aO b€ _ aOàTb,<br />

(23)<br />

(ii)<br />

Ú LQaTb Ÿ Z aO b€ _ aOàTb if eaT b !à (24.1)<br />

Û LQaT b Z aO b€ _ aOàTb if eaTb<br />

Ÿ!à (24.2)<br />

Ü LQaTb œ Z a^aTbb€ _ a^aT bàTb.<br />

(24.3)<br />

(24)<br />

Remark 1. From the proof below, it follows that identities (23) and (24.3) hold with ^aT b replaced by<br />

any O­ s ŠaTb. Identity (24.3) has been verified directly in [26, Proof of Thm 7.2, Ch. 6]. Here it<br />

follows from (23) with Oœ^aT<br />

b.<br />

Inequalities (24.1) and (24.2) follow directly from (23) and the<br />

assumptions eaT b ! and eaTb<br />

Ÿ! . So we only need to verify (23), which could be done directly.<br />

Our derivation of (23) is based the fact that both sides of (23) represent the cost N a?<br />

b in (2) with<br />

RœT a> " b and ?œ OB.<br />

Proof of (23). For a=ßDb<br />

­M‚V 8 "ß_ 8<br />

and a given T­P aM ß’ b, consider the cost N a?<br />

b in (2) with<br />

RœT a> " b and ?œ OB. Then N a? b is precisely NO<br />

in (18), which is represented in (21). On the other<br />

hand, by (15) with RœT a> b, Oœ s aT b and ?œ OB, we have<br />

" ^<br />

X X w<br />

X<br />

N œD T ab =D€I( ˜ B ˆ T € LQaT b€ a^aTb Ob e aTba^aTb<br />

Ob<br />

‰ B .>Þ (25)<br />

O<br />

=<br />

><br />

"<br />

So the two integrals in (25) and (21) are identical <strong>for</strong> the solution<br />

a=ßDb<br />

­M‚‘ 8 . By Proposition 3, (23) must hold. ¨<br />

B<br />

to equation (18.1) <strong>for</strong> each

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