Units and Conventions Measurement Data Analysis ... - PEGSnet
Units and Conventions Measurement Data Analysis ... - PEGSnet
Units and Conventions Measurement Data Analysis ... - PEGSnet
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
Name:<br />
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
<strong>Units</strong> <strong>and</strong> <strong>Conventions</strong><br />
Fundamental <strong>Units</strong><br />
Derived <strong>Units</strong><br />
Prefixes<br />
St<strong>and</strong>ard Form<br />
Conversions of <strong>Units</strong><br />
<strong>Measurement</strong><br />
Significant Figures<br />
Uncertainties in <strong>Measurement</strong>s<br />
Uncertainties in Single <strong>Measurement</strong>s<br />
Absolute <strong>and</strong> percentage errors<br />
Showing Uncertainties on Graphs<br />
Advanced Error <strong>Analysis</strong><br />
Uncertainties when taking Repeat Samples<br />
<strong>Data</strong> <strong>Analysis</strong><br />
Experimental Design<br />
How to Write a Formal Practical Report!<br />
Doing Graphs <strong>and</strong> Tables on EXCEL<br />
Graphical <strong>Analysis</strong> of <strong>Data</strong><br />
Linear Graphs<br />
Non-linear Graphs<br />
Finding the relationship!s image may not be reproduced in any form or by any means<br />
without the prior written permission of the museum.<br />
This is an armillary sphere It is a medieval<br />
scientific instrument that st<strong>and</strong>s about 3 m tall –<br />
around double the height of the average person.<br />
It was constructed in Florence around 1590 <strong>and</strong><br />
took almost a decade to complete. It was used to<br />
chart the movement of the stars <strong>and</strong> planets.<br />
Today a simple computer program could do the<br />
same job with much greater precision.<br />
1
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
UNITS AND CONVENTIONS<br />
Physics is an experimental science dealing largely with measurements. In Physics, the data<br />
that you collect <strong>and</strong> the numbers that you work with in problems are not just numbers. They<br />
are measurements of physical quantities such as mass, time, temperature, etc.<br />
Fundamental <strong>Units</strong><br />
In 1960, the international authority on units <strong>and</strong> measures agreed to adopt a st<strong>and</strong>ardised<br />
system known as the International System (SI) of units. There are many different physical<br />
quantities, but in the SI system, seven are defined as fundamental or basic quantities. They<br />
are:<br />
Fundamental Quantity<br />
length<br />
mass<br />
time<br />
electric current<br />
temperature<br />
luminous intensity<br />
amount of substance<br />
Unit <strong>and</strong> Symbol<br />
metre (m)<br />
kilogram (kg)<br />
second (s)<br />
ampere (A)<br />
kelvin (K)<br />
c<strong>and</strong>ela (Cd)<br />
mole (mol)<br />
In Physics, we will be dealing with the first 5 of these quantities many, many times!<br />
Derived <strong>Units</strong><br />
Other physical quantities (e.g. speed) can be measured in units that are derived from these<br />
fundamental units.<br />
e.g. Speed is defined as:<br />
speed<br />
=<br />
distance<br />
travelled<br />
time taken<br />
The unit for speed is m/s or m s -1 . This is derived from the fundamental units for length <strong>and</strong><br />
time.<br />
e.g. The kinetic energy of an object is: E k = 1 2 mv2<br />
The unit for kinetic energy is: kg × (m/s) 2 = kg m 2 / s 2 or kg m 2 s -2 . Again, this is derived in<br />
terms of fundamental units. This unit of energy is more commonly known as a joule (J).<br />
e.g. the unit for area is square metres. Area unit = length unit × length unit = m × m = m 2<br />
Worked Example<br />
Newton’s 2 nd Law states that a net force applied to a body is equal to the product of its mass<br />
<strong>and</strong> acceleration i.e. ΣF = ma<br />
What is the derived unit for force?<br />
Unit of force =<br />
2
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Solution: This derived unit (kg m s -2 ) also has a special name. It is called a newton (N).<br />
Some derived units are shown in the table below.<br />
Derived Quantity Unit Symbol<br />
frequency hertz Hz<br />
force newton N<br />
energy or work joule J<br />
power watt W<br />
electric potential volt V<br />
resistance ohm Ω<br />
temperature degree Celsius °C<br />
Prefixes<br />
Often you will be measuring quantities that are very big (e.g. the resistance of your body) or<br />
very small (e.g. the thickness of a hair). When dealing with values such as these, it is<br />
necessary to use prefixes with the units. Prefixes represent decimal fractions or multiples of<br />
the original SI unit.<br />
Prefix Abbreviation Value<br />
tera T 10 12<br />
giga G 10 9<br />
mega M 10 6<br />
kilo k 10 3<br />
milli m 10 -3<br />
micro µ 10 -6<br />
nano n 10 -9<br />
pico p 10 -12<br />
Notice that these power values occur in multiples of three. This is consistent with the<br />
convention of organising large numbers in groups of three e.g 15,000,000,000.<br />
Other prefixes that you will encounter are: centi, c, 10 -2 ; hecto, h, 10 2 <strong>and</strong> deci, d, 10 -1<br />
Exercises: Complete these statements:-<br />
a) 6 MW = W<br />
b) 6,000 kW = W<br />
c) 500 ms = s<br />
d) 15,000 km = m<br />
e) 3 nm = m<br />
f) 25 GHz = Hz<br />
g) 5 µm = m<br />
h) 0.25 ms = s<br />
3
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
St<strong>and</strong>ard Form<br />
When working with big or small numbers, it is often time consuming or clumsy to write the<br />
number out in full. For example, the speed of light in a vacuum is 300,000,000 m s -1 . The<br />
convention is to express this in st<strong>and</strong>ard form or scientific notation as 3.00×10 8 m s -1 .<br />
In tests <strong>and</strong> exams, it is expected that numbers greater than 1000 or less than 0.01 will be<br />
written in st<strong>and</strong>ard form.<br />
On your calculator, the EXP button is used for writing values in st<strong>and</strong>ard form.<br />
Use your calculator to determine: 3.00×10 8 ×5.0×10 -6 =<br />
Conversion of <strong>Units</strong><br />
Often you will need to convert from one unit to another. For example, if you measure the<br />
length <strong>and</strong> width of your desk in centimetres, but you want to know its area in square metres.<br />
You will need to convert square centimetres into square metres. This involves working in 2<br />
dimensions.<br />
Area<br />
100 cm<br />
100 cm<br />
1 m 2 1 m 3 1 m 2 = 100 cm × 100 cm<br />
= 10,000 cm 2<br />
Similarly, if you measure the length, width <strong>and</strong> thickness of your textbook in millimetres but<br />
wish to find its volume in cubic metres. This will involve a 3 dimensional conversion from<br />
cubic centimetres into cubic metres.<br />
Volume<br />
100 cm<br />
100 cm<br />
1 m 3 = 100cm × 100cm × 100cm<br />
= 1,000,000 cm 3<br />
= 1.0×10 6 cm 3<br />
100 cm<br />
Exercises: Complete these conversions:<br />
(a) 1 cm 2 = mm 2<br />
(f) 1 cm 3 = mm 3<br />
(e) 1 m 2 = µm 2 (j) 1 mm 3 = m 3<br />
(b) 1 km 2 = m 2<br />
(g) 1m 3 = cm 3<br />
(c) 1 mm 2 = m 2<br />
(h) 1 µm 3 = m 3<br />
(d) 1m 2 = mm 2<br />
(i) 1 m 3 = km 3<br />
4
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
WORKSHEET: <strong>Units</strong> <strong>and</strong> Conversions<br />
Remember to express numbers greater than 1000 or less than 0.01 in<br />
st<strong>and</strong>ard form!<br />
1. Convert these lengths into metres (m):<br />
a) 25,000,000 µm =<br />
b) 33 nm =<br />
c) 360,000 mm =<br />
2. Convert these areas into square metres (m 2 ):<br />
a) 1500 cm 2 =<br />
b) 60,000 µm 2 =<br />
c) 0.42 km 2 =<br />
3. Convert these volumes into cubic centimetres (cm 3 ):<br />
a) 35,000 mm 3 =<br />
b) 3 m 3 =<br />
c) 56,000,000 µm 3 =<br />
4. Convert these current readings into amperes (A):<br />
a) 370 mA =<br />
b) 90,000 µA =<br />
c) 0.03 µA =<br />
5. Convert these mass measurements:<br />
a) 44 kg = g<br />
b) 64,000 mg = g<br />
c) 70,000,000,000 µg = kg<br />
6. Express these units in terms of the fundamental SI units.<br />
Name <strong>and</strong> Symbol Definition Unit Special Name<br />
force, F mass×acceleration kg m s -2 newton, N<br />
momentum, p<br />
mass×velocity<br />
work, W force×distance joule, J<br />
velocity, v<br />
acceleration, a<br />
impulse, I<br />
displacement/time<br />
velocity/time<br />
force×time<br />
charge, Q current×time coulomb, C<br />
voltage, V<br />
resistance, R<br />
work/charge<br />
voltage/current<br />
5
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
MEASUREMENT<br />
Expressing the Accuracy of a <strong>Measurement</strong><br />
When you obtain a measurement during an experiment or work with measurements when<br />
solving problems, you need to be mindful of a number of important conventions.<br />
Significant Figures<br />
When you obtain data during an experiment, the accuracy of a measurement will depend on<br />
the precision of the instrument or meter being used.<br />
For example, if you use a metre rule to measure the diameter of a ball bearing, you might<br />
obtain a result of 1.2 cm. However, if you used a micrometer to measure the diameter instead,<br />
the result might be 1.258 cm. The micrometer is far more precise <strong>and</strong> gives a much more<br />
accurate answer.<br />
The metre rule has given two figures or digits that we know about with some confidence. We<br />
say that the data (1.2 cm) has 2 significant figures. The data from the micrometer (1.258 cm)<br />
has allowed us to know the diameter of the ball bearing to 4 significant figures.<br />
The number of significant figures in a measurement can be found using 4 simple rules:<br />
• All non-zero figures are significant, e.g. 15.75 kg has 4 significant figures.<br />
• All zeros in between non-zero digits are also significant, e.g. 2.09 m has 3 sig figs.<br />
• All zeros that follow a non –zero digit <strong>and</strong> are to the right of the decimal point are<br />
significant.<br />
e.g. 21.40 g has 4 significant figures.<br />
0.5 mm has 1 significant figure.<br />
0.100 kg has 3 significant figures.<br />
• Zeros used for placing very small or very large numbers are not significant.<br />
e.g. 0.00000031 V has 2 significant figures<br />
4,550,000,000,000,000 m has 3 significant figures.<br />
It is often confusing when dealing with whole numbers ending with zero.<br />
For example; 6,600 mm could have 2, 3 or 4 significant figures.<br />
To overcome this confusion, it should be written in st<strong>and</strong>ard form as:<br />
6.6×10 3 mm if you wish to show 2 sig figs, or<br />
6.60×10 3 mm if you wish to show 3 sig figs <strong>and</strong> so on.<br />
6
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Addition <strong>and</strong> Subtraction of <strong>Measurement</strong>s<br />
When adding or subtracting data, the measurements must be rounded off to the least number of<br />
decimal places that are present in the data.<br />
e.g.<br />
13.305 mm<br />
10.24 mm<br />
+2.0522 mm<br />
25.5972 mm<br />
This must be rounded off to 2 decimal places (25.60 mm) because 10.24 has just 2 decimal places.<br />
The same applies for subtraction problems.<br />
Multiplication <strong>and</strong> Division of <strong>Measurement</strong>s<br />
When multiplying or dividing data, your answer must be rounded off to the least number of<br />
significant figures in your data.<br />
e.g. 0.50 cm × 26.84 cm = 13.42 cm 2 .<br />
This must be rounded off to 13 cm 2 because 0.50 cm has<br />
only 2 sig figs.<br />
2 sig figs 4 sig figs<br />
The same applies when dividing measurements.<br />
NB: These rules only apply when working with measurements. For example, if the mass of one<br />
marble is 26.7 g, then the mass of 5 identical marbles is:<br />
5×26.7 g = 133.5 = 134 g. The answer still has 3 significant figures. The ‘5’ is not a<br />
measurement! What are its units??<br />
Also take care when using pi!<br />
TAKE NOTE!!<br />
You must be mindful of significant figures when writing practical reports <strong>and</strong> when<br />
answering test questions. If you have too many or too few significant figures in your data or<br />
in your answers, you will lose marks!!!<br />
7
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
WORKSHEET: SIGNIFICANT FIGURES<br />
1. The length of an object is measured 3 times using 3 different measuring instruments.<br />
The results obtained were: a) 92.71 mm b) 93 mm c) 9 cm<br />
Which result was obtained using a blackboard ruler, a micrometer <strong>and</strong> a 30 cm ruler?<br />
2. For each of the measurements recorded below, write down its number of significant figures<br />
<strong>and</strong> express it in scientific notation with the correct SI unit. The first example has been<br />
completed for you.<br />
<strong>Measurement</strong> Significant figures St<strong>and</strong>ard Form, SI unit<br />
(a) 13.05 kg 4 13.05 kg<br />
(b) 0.0000063 A<br />
(c) 27 kJ<br />
(d) 353,000,000 mm<br />
(e) 0.00607 mm<br />
(f) 0.250 µA<br />
(g) 150 kg<br />
3. How many significant figures are quoted in each of the following measurements?<br />
a) 783.9 kJ b) 0.035 cm c) 90.24 kg d) 86,400 s e) 0.0060 m f) 6.07×10 7 m<br />
4. What is the perimeter of a soccer field if its length <strong>and</strong> width were measured to be 95.82 m<br />
<strong>and</strong> 71.836 m respectively?<br />
5. What is the area (in m 2 ) of the soccer field discussed in Question 4?<br />
6. Use your 30 cm ruler to measure the length <strong>and</strong> width of this page.<br />
length = cm<br />
width = cm<br />
Use these results to determine: (a) the perimeter of the page (b) the area of the page<br />
7. Mary runs 25.3 m in 4.1 s. What was her average speed?<br />
8
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Uncertainties in <strong>Measurement</strong>s<br />
When we take measurements <strong>and</strong> readings with different analogue instruments, there is<br />
always a limit to how accurately we can obtain our results. If we use a metre ruler to measure<br />
the thickness of a 50 c coin, we can gain a result to the nearest millimetre i.e. 2 mm.<br />
However, if we use a more precise instrument such as a micrometer (which measures to the<br />
hundredth of a millimetre!), we could say that the thickness is 2.46 mm. If using a digital<br />
device that is giving a stable reading, there is an uncertainty of ±1 in the last digit. The<br />
accuracy with which we record all our measurements must reflect the type of device that was<br />
used to obtain the measurements. We should not record too many decimal places, nor should<br />
we record too few.<br />
This measurement would be recorded as 225 g. It is not<br />
possible to read it more precisely, as say 224.3 g. It would<br />
also be incorrect to write down 225.00 g.<br />
This measurement could be<br />
accurately recorded as 450.75 g.<br />
Exercise:.<br />
1. Record each of the analogue measurements below to the appropriate level of precision<br />
2. What is the uncertainty for these digital readings?<br />
(a) 16.3 g (b) 52 °C (c) 2.06 mA (d) 0.094 mm<br />
9
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Uncertainties in Single <strong>Measurement</strong>s<br />
When we take measurements <strong>and</strong> readings, there is always uncertainty involved. This<br />
uncertainty is related to the quality of the apparatus <strong>and</strong> the skill of the experimenter. It is not<br />
possible to obtain exact values! Most measurements will vary slightly from the actual value.<br />
The difference between the two is the error or uncertainty.<br />
NB: an error does not necessarily imply a mistake; just an imprecision!!<br />
Absolute errors<br />
The reading taken using the ruler shown above would be recorded as 55.6 cm. However, the<br />
actual length will in fact be slightly higher or lower than 55.6 cm. Using the ruler, we can<br />
distinguish between 55.5, 55.6, <strong>and</strong> 55.7 cm, but is unreasonable to say that the measurement<br />
is 55.63 cm. This ruler is only accurate to the nearest millimetre. To indicate that the length is<br />
somewhere between 55.5 <strong>and</strong> 55.7 cm, we can say that:<br />
length = 55.6±0.1 cm<br />
This ±0.1 cm is known as the absolute uncertainty associated with the reading. In general,<br />
the uncertainty associated with any measured value is taken to be half of the limit of the<br />
reading of the device, or half of the smallest division of the scale being used.<br />
The smallest division on the metre ruler above is 0.2 cm, hence the uncertainty is 0.1 cm.<br />
What absolute uncertainty would apply if you used your ruler?<br />
According to this convention, the reading on the force meter on the previous page should be<br />
recorded as 0.3±0.05 N. This reading, however, is not strictly correct. There are some other<br />
important rules <strong>and</strong> conventions that must be followed!<br />
• There must be the SAME NUMBER OF DECIMAL PLACES in both the<br />
MEASUREMENT <strong>and</strong> the ABSOLUTE UNCERTAINTY.<br />
e.g. 55.7±0.1 cm 30.35±0.05 kg 74±2 g<br />
e.g. 46.1±0.06 mm 85±0.5 kg 43.6±1 mA<br />
• An absolute uncertainty must only have ONE SIGNIFICANT FIGURE <strong>and</strong> will often<br />
need to be rounded off.<br />
10
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
For example, if a scale has a smallest division of 0.5 N, the absolute uncertainty will be ±0.25<br />
N which will need to be rounded off to ±0.3 N.<br />
If the scale of the instrument is very large, you can use your judgement to determine the<br />
uncertainty.<br />
In the example below, half of the smallest division is 0.25 which must be rounded off to 0.3.<br />
This would give a reading of 4.6±0.3 which suggests that the value could be anywhere<br />
between 4.3 <strong>and</strong> 4.9. We can obviously be more precise than that. In this case, the value<br />
could be recorded as 4.60±0.05.<br />
Percentage Errors<br />
An uncertainty could also be expressed as a percentage error.<br />
percentage<br />
absolute error 100<br />
error =<br />
!<br />
measurement 1<br />
0.05 100<br />
In this example, the percentage error is: % error = ! = 1.1%<br />
4.60 1<br />
Percentage errors are usually written with:<br />
• 1 significant figure when less than 1%<br />
• 2 significant figures when 1% or greater.<br />
For example, if you calculate an error to be 0.75%, you should round this off to 0.8%. Also,<br />
an error of 5.681% needs to be rounded off to 5.7%.<br />
Percentage errors give a better representation of the accuracy of the measurement than do<br />
absolute errors. Consider these 2 measurements:<br />
530±5 s <strong>and</strong> 10±5 s<br />
The absolute error is the same in each measurement (±5s) , but this error is far more<br />
significant in the second case.<br />
5 100<br />
The percentage error for the first result is: % error = ! = 0.94%<br />
. This is very<br />
530 1<br />
accurate; less than 1% error.<br />
In the second measurement, the error is 50%. Perhaps the experimental technique used needs<br />
to be improved in order to obtain more precise data!<br />
11
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Examples of correct <strong>and</strong> incorrect error readings are given below. Complete the ones that are<br />
missing.<br />
Incorrect Reading Correct Version Incorrect Reading Correct version<br />
20.876±0.2 s 20.9±0.2 s 7.5±0.62 m/s<br />
27±0.6 mm 27±1 mm 0.352±0.02 ms<br />
85.45±0.25 kg 85.5±0.3 kg 59±1.6 m 3<br />
28.6 K ± 0.87% 28.6 K± 0.9% 8.05 km± 4.71%<br />
WORKSHEET: UNCERTAINTY EXERCISES<br />
1. Fix up these incorrect measurements:<br />
(a) 57±0.5 mm<br />
(f) 10.4±0.065 mm<br />
(b) 112.3±1 m/s<br />
(g) 15±2.5 mA<br />
(c) 1.6±0.05 mg<br />
(h) 0.34±0.15 kg<br />
(d) 64.4±1.8 m<br />
(i) 27.03±0.1 kg<br />
(e) 0.085±0.0025 kV<br />
(j) 45.0±2 m<br />
2. Determine the percentage uncertainties for your answers in Question 1.<br />
3. Record the readings on these meters <strong>and</strong> scales as accurately as is appropriate. Indicate the associated<br />
uncertainties, being mindful of the conventions that you have just learnt.<br />
12
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Showing Uncertainties on Graphs<br />
Many experiments in Physics can be analysed using graphs. When drawing graphs, straight<br />
lines or curves of best fit must be plotted. There should be about the same number of data<br />
points above <strong>and</strong> below these lines of best fit.<br />
There is an uncertainty associated with each point that is plotted on a graph. Error bars are<br />
used to show this uncertainty.<br />
E.g. Consider the following data:<br />
length(cm)<br />
resistance (Ω)<br />
14.5±0.5 0.22±0.02<br />
Let us consider how the data should be shown on the graph. First, we plot the data value<br />
(14.5 cm, 0.22 Ω). Then we must indicate the uncertainty of this point using error bars.<br />
For the resistance data, the value could range from a minimum of 0.22 – 0.02 = 0.20 up to a<br />
maximum of 0.22 + 0.02 = 0.24. We indicate this range by drawing a line between 0.20 <strong>and</strong><br />
0.24 Ω as shown on the graph. This line is called an error bar.<br />
Similarly, the error bar for length should be drawn between 14.0 <strong>and</strong> 15.0 cm.<br />
• It is important to remember that your line of best fit should pass through or touch ALL of<br />
the error bars that you have drawn.<br />
• Often, error bars will be too small to be shown on a graph. If this is the case, include a<br />
statement to that effect underneath the graph. However, the uncertainties must always<br />
be shown in your tables of results.<br />
• When doing graphical analysis, it is usually only necessary to show error bars on your<br />
first graph.<br />
Worksheet: Error bars!<br />
13
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Advanced Error <strong>Analysis</strong><br />
Sometimes you may wish to use your data to obtain a different physical quantity. For<br />
example, you have measured the length <strong>and</strong> width of a classroom as 5.85±0.05 m <strong>and</strong> 4.2±0.1<br />
m respectively. Now want to calculate the perimeter <strong>and</strong> area of the room. You can do this by<br />
performing a simple calculation. It is also possible to determine the uncertainty for these<br />
derived quantities.<br />
Adding <strong>and</strong> Subtracting <strong>Measurement</strong>s<br />
The room has: length = 5.85±0.05 m<br />
width = 4.2±0.1 m<br />
4.2±0.1 m<br />
5.85±0.05 m<br />
To calculate the perimeter value, you will need to perform the following addition:<br />
5.85 m<br />
4.2 m<br />
5.85 m<br />
+ 4.2 m___<br />
20.10 m_<br />
Recall that the answer is limited by the least number of decimal places for addition <strong>and</strong><br />
subtraction problems. In this case, that is 1 decimal place. The answer must therefore be<br />
given as:<br />
Perimeter = 20.1 m.<br />
When adding or subtracting<br />
measurements, the total absolute error<br />
is found by ADDING the individual<br />
absolute errors.<br />
The uncertainty is therefore: 0.1+0.05+0.1+0.05 = 0.30 m.<br />
Recall that absolute errors can only have 1 significant figure, so the measurement must be<br />
written as:<br />
Perimeter = 20.1±0.3 m<br />
The technique for subtraction is the same i.e the absolute errors are ADDED! This would<br />
be useful when finding the error associated with the change in a quantity.<br />
14
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Multiplying <strong>and</strong> Dividing <strong>Measurement</strong>s<br />
If you wished to calculate the area of the classroom, you would simply multiply the length<br />
<strong>and</strong> width measurements.<br />
4.2±0.1 m<br />
5.85±0.05 m<br />
Area = 4.2×5.85 = 24.57 m 2<br />
Recall that when measurements are multiplied or divided, the answer is limited by the least<br />
number of significant figures in the measurements. In this example, the least number is two<br />
(in 4.2 m), so this answer must be written as:<br />
Area = 25 m 2<br />
To calculate the absolute error for this value, you must add the percentage errors of the<br />
measurements.<br />
% error for length = 0.05<br />
5.85 " 100<br />
1 = 0.85%<br />
% error for width = 0.1<br />
4.2 "100 1 = 2.4%<br />
The percentage error for area is:0.85 + 2.4 = 3.25%. This would be rounded off to:<br />
Area = 25 m 2 ±3.3%<br />
The absolute error for area is found simply calculating 3.3% of 25 m 2 = ±0.83m 2 . So the<br />
area value can be stated as: Area = 25 ±0.83 m 2<br />
However, the absolute error can only have 1 significant figure, so the final result must be<br />
given as:<br />
Area = 25 ±1 m 2<br />
When multiplying or dividing measurements, the individual<br />
percentage errors must be ADDED to find the total percentage<br />
error.<br />
15
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
ERROR ANALYSIS EXERCISE<br />
1. Consider the following dimensions of a room in an art gallery. Calculate, giving both<br />
percentage <strong>and</strong> absolute errors, the following quantities.<br />
h = 4.1±0.1 m<br />
(a) the floor perimeter.<br />
l = 27.4±0.3 m<br />
w = 3.45±0.02 m<br />
(b) perimeter of the large wall.<br />
(c) the floor area.<br />
(d) the large wall area.<br />
(e) the difference between the length <strong>and</strong> width of the floor.<br />
(f) the volume of the space.<br />
16
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Uncertainties when taking Repeat Samples<br />
When performing experiments in class, time constraints usually mean that only one<br />
measurement is taken for each data point. This measurement is quite unreliable because there<br />
may have been inaccuracies with the equipment or in the way in which the result was<br />
obtained for that particular result. As you will be aware, if you repeat the same experiment 4<br />
or 5 times, you will get 4 or 5 slightly different values. This does not mean that you have<br />
done something wrong; it simply indicates the r<strong>and</strong>om nature of uncertainties. (If your<br />
results are vastly different, however, you might want to have a look at your experimental<br />
technique!).<br />
In order to obtain results that are more reliable, it is necessary to take repeat samples for<br />
each particular data point <strong>and</strong> use this to obtain an average value. It is always better,<br />
although not always possible, to obtain 3, 4 or more results for each value.<br />
For example, some students are testing the rebound height of a golfball dropped from 1.00 m<br />
onto a concrete floor. In order to obtain reliable data, they repeat the experiment 7 times.<br />
Their results were:<br />
Rebound height (cm) 81 88 84 49 85 84 87<br />
It is clear that something went wrong with the 4 th result! This outlier can be disregarded.<br />
81+ 88 + 84 + 85 + 84 + 87<br />
The average rebound height is : = 84.8 cm<br />
6<br />
The data had 2 significant figures, so this answer must be rounded off to 85 cm.<br />
Note that if you had stopped after taking only one result, it would have given 81 cm.<br />
To find the absolute error for the average value:<br />
( highest value ! lowest value)<br />
absolute error =<br />
2<br />
In this example, the absolute error is:<br />
88 " 81<br />
= ±3.5 cm<br />
2<br />
This must be rounded off to 1 significant figure, i.e.±4, so the average rebound height <strong>and</strong><br />
its absolute error is:<br />
85±4 cm.<br />
Remember, absolute errors should be:<br />
• recorded to 1 significant figure<br />
• have the same level of precision as the data value<br />
17
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Repeat Samples worksheet<br />
A group of students took the following measurements of the length, width <strong>and</strong> depth of a<br />
swimming pool.<br />
Depth (m) Width (m) Length (m)<br />
3.01 8.75 50.03<br />
3.04 8.70 50.10<br />
2.98 8.63 50.07<br />
2.97 8.68 50.01<br />
3.00 8.71 49.98<br />
3.02 8.72 49.97<br />
3.03 8.67 50.00<br />
(a) Calculate the average depth, width <strong>and</strong> length of the pool. Include absolute errors with<br />
your answers.<br />
(b) Use your answers to determine these quantities. Include both absolute <strong>and</strong> percentage<br />
errors with your answers.<br />
(i) The top surface area of the pool.<br />
(ii) The volume of the pool.<br />
(iii) The perimeter of the pool bottom.<br />
18
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
HOMEWORK EXERCISE: MARBLES!<br />
Name:<br />
In an experiment, Lyn had to measure the time taken for a marble to drop through a tube<br />
filled with water. She made two marks on the tube; one near the top <strong>and</strong> one near the bottom.<br />
She started the stopwatch just as the marble passed the top mark <strong>and</strong> stopped timing as the<br />
marble passed the bottom mark.<br />
She repeated the experiment 5 times.<br />
Trial number time(s)<br />
1 3.2<br />
2 2.7<br />
3 2.9<br />
4 3.5<br />
5 3.3<br />
water<br />
Lyn then filled the tube with cooking oil <strong>and</strong> repeated the experiment. Her results were:<br />
Trial number time(s)<br />
1 6.7<br />
2 6.5<br />
3 6.7<br />
4 6.7<br />
5 6.8<br />
oil<br />
1. In which experiment does the data seem to be more accurate? Discuss.<br />
2. For each of the experiments above, calculate the average time that the marble took to<br />
travel between the marks. Include the absolute error in your answer.<br />
3. If the distance between the marks was 1.05±0.01 m, determine the average speed of the<br />
marble as it fell through each liquid. Include absolute errors <strong>and</strong> units in your answers.<br />
19
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
DATA ANALYSIS<br />
Experimental Design<br />
The SCIENTIFIC METHOD is an objective, unbiased <strong>and</strong> powerful way of investigating<br />
phenomena. This scientific approach has only been developed over the past few centuries <strong>and</strong><br />
it has led to the explosion in knowledge <strong>and</strong> technological advances during that time.<br />
First, observed facts or data are sorted into some logical order. Then a hypothesis or<br />
explanation is put forward. This hypothesis is used to make predictions that can be tested to<br />
either support or disprove the hypothesis. From the results of these tests, conclusions can be<br />
drawn. If enough data has been collected, it may be possible to propose a law that predicts<br />
future outcomes. A theory (explanation of why the law works) could then be proposed <strong>and</strong><br />
subjected to further testing.<br />
When designing an experiment to investigate the relationship between two variables, it is<br />
important that you control the variables in the experiment to ensure that the experiment is<br />
fair.<br />
• The variable that you are controlling <strong>and</strong> making changes to is called the<br />
INDEPENDENT VARIABLE.<br />
• The variable that responds to the changes in the independent variable is called the<br />
DEPENDENT VARIABLE.<br />
• The factors that remained the same throughout the experiment are called CONTROLLED<br />
VARIABLES.<br />
EXAMPLES: For each of these experiments, identify the independent, dependent <strong>and</strong> what<br />
could act as controlled variables.<br />
Experiment 1: Ten seeds were planted in each of 5 pots (A-E) containing Budget Potting<br />
Mix. The pots were given the following amounts of water each day for 40 days: A: 50 mL, B:<br />
100 mL, C: 150 mL, D: 200 mL, E: 250 mL.<br />
Experiment 2: Jenny wanted to see if the colour of food influenced whether kindergarten<br />
children would choose it for lunch. She put food colouring into 4 identical bowls of mashed<br />
potato <strong>and</strong> counted how many children chose each colour. The colours were red, green,<br />
yellow <strong>and</strong> blue.<br />
Experiment 3: James wished to investigate the relationship between the angle of a Hot<br />
Wheels track <strong>and</strong> the time that a car takes to travel down the track. He used 1.50 m of track,<br />
placed it at an angle of 10° to the horizontal <strong>and</strong> timed how long the toy car took to travel<br />
down it. He repeated this with angles of 20°, 30°, 40° <strong>and</strong> 50°.<br />
20
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
How to write up a Formal Practical Report!<br />
The main reason that scientists report on the results of their experiments is so that others can<br />
read <strong>and</strong> underst<strong>and</strong> what was done <strong>and</strong> what the results may tell us. Obviously, for this<br />
purpose to be achieved, a lot of care needs to taken when writing up experiments <strong>and</strong><br />
communicating your findings. When writing up a practical report, your expression should be<br />
clear, concise <strong>and</strong> unambiguous.<br />
Each formal experiment report that you write should contain the following headings:-<br />
AIM: Every experiment must have an aim (or aims) otherwise there is no point doing it!<br />
The aim could be to investigate the nature of the relationship between two (or more)<br />
variables. This investigation could be qualitative (describe the general nature of the<br />
relationship) or quantitative (define a precise mathematical relationship).<br />
You should discuss the variables involved. Identify:-<br />
the independent variable (the one you were manipulating),<br />
the dependent variable (the one that changes when the independent variable is changed) <strong>and</strong><br />
controlled variables (things that you have kept unchanged).<br />
APPARATUS: list the laboratory equipment that was used. It is not necessary to include<br />
items such as pens <strong>and</strong> calculators.<br />
METHOD: This is a description of how you <strong>and</strong> your partner performed the experiment.<br />
This should be written in past tense <strong>and</strong> in the third person (i.e. no names!).<br />
✘ We recorded the temperature every 10 seconds.<br />
✓ The temperature was recorded every 10 seconds.<br />
Explain clearly what you did. Include descriptions of any modifications that you had to make<br />
or any problems that you encountered. Describe steps that you undertook to ensure that the<br />
data that you collected was accurate.<br />
It is important to include a scientific diagram of how the apparatus was set up.<br />
RESULTS: These are usually placed in tables <strong>and</strong> graphs.<br />
Tables should include the names <strong>and</strong> abbreviated units of the quantities that you measured.<br />
Record an appropriate number of significant figures in your table.<br />
Table 1: time for car to travel down ramp at different angles<br />
Length of ramp = 2.35±0.05 m<br />
Angle (±0.5º) Time (±0.1 s)<br />
5.3 6.4<br />
6.4 5.2<br />
Underneath the table, explain how you decided on the uncertainty values that you used.<br />
Include sample calculations with your explanations.<br />
21
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Graphs should include the same information as the tables, but marked on the axes:<br />
Time(s)<br />
Graph 1: Time vs Angle for car travelling down ramp<br />
×<br />
×<br />
×<br />
×<br />
Angle (º)<br />
Graphs can be done on computer or by h<strong>and</strong>. If on computer, show the grid lines. If by h<strong>and</strong>,<br />
use pencil <strong>and</strong> do on graph paper.<br />
Give your graph a detailed heading. Make sure that the scale is marked along each axis.<br />
Mark in the main numerical values (not the data points) <strong>and</strong> make sure that each scale is<br />
even! Most graphs will start from the origin.<br />
Mark points as small crosses <strong>and</strong> show the line of best fit. If this is straight, use a ruler. If it is<br />
a curved, carefully sketch one smooth curved definite line that travels as close to as many<br />
points as possible. Don’t play join the dots!<br />
ANALYSIS: This usually consists of a series of directed questions relating to the data. This<br />
is the most important part of the report. Make sure that you explain your findings clearly<br />
giving full responses.<br />
In the analysis sections of Student Designed Investigations, you should begin by having a<br />
general discussion of the data. Refer to your tables <strong>and</strong> graphs. Then try to identify any<br />
patterns or trends that seem evident. Ensure that your discussion is detailed.<br />
Can you find the relationship between the variables? You can use graphical analysis to<br />
establish a quantitative relationship. Make sure that you fully explain the process that you<br />
have undertaken, showing gradient calculations, etc.<br />
What do current theories say about the relationship between your variables? Discuss how<br />
your findings compare with theory. You will be assessed on the depth of your analysis. A full<br />
<strong>and</strong> detailed analysis will be rewarded; a brief <strong>and</strong> superficial analysis will not.<br />
CONCLUSION: This is a response to the Aim. Briefly state your main findings from doing<br />
the experiment. If you have found a relationship, state what it is.<br />
DISCUSSION OF UNCERTAINTIES: In any experiment involving measurements,<br />
uncertainties will arise. In point form, you should discuss where these uncertainties occurred.<br />
Don’t explain how you arrived at the actual values again. For example:<br />
During this experiment, uncertainties occurred for the following reasons:<br />
As the car was released, it may have been pushed or retarded slightly.<br />
Stopwatches were used to measure the time taken by the car. Allowing for reaction times, this<br />
led to an uncertainty in these measurements.<br />
On some occasions, the car did not travel directly along the ramp, leading to an uncertainty in<br />
the distance measurements.<br />
There was an uncertainty associated with drawing a line of best fit.<br />
22
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Doing Graphs <strong>and</strong> Tables on EXCEL<br />
Open EXCEL <strong>and</strong> enter your data in the spreadsheet. Put the x co-ordinate data in column 1<br />
<strong>and</strong> the y co-ordinate data in column 2. Include the units that were used in brackets. For<br />
example, if you wished to plot a speed vs time graph:<br />
time ( 0.2s) speed ( 0.4 m s -1 )<br />
0.0 0.6<br />
1.0 2.5<br />
2.0 3.8<br />
3.0 5.9<br />
4.0 7.4<br />
5.0 9.3<br />
NB: EXCEL cannot do ± signs, so you will need to enter the ±’s by h<strong>and</strong> after printing out<br />
the table.<br />
Producing a Graph<br />
Highlight the table, including the headings, <strong>and</strong> then click on the “chart wizard” icon.<br />
STEP 1: Select x-y scatter (without plotted lines).<br />
STEP 2:<br />
<strong>Data</strong> range: series in: columns.<br />
STEP 3: Titles –<br />
Chart title: Graph 1: speed vs time for parachute (You can<br />
also type your name here)<br />
Value X axis: time(s)<br />
Value Y axis: speed (m/s)<br />
Gridlines – show MAJOR gridlines<br />
Legend – untick ‘show legend’<br />
<strong>Data</strong> labels: none<br />
STEP 4:<br />
Chart location – as new sheet → FINISH<br />
Plotting a line of best fit<br />
In physics, we would like you to rule or sketch your own line of best fit so that your<br />
graphing skills improve!<br />
For your own purposes, you may wish to use EXCEL to do this:<br />
In the toolbar, click on CHART – ADD TRENDLINE.<br />
TYPE: select the line that best matches the data. For straight lines, choose LINEAR.<br />
OPTIONS: If you want the line to pass through the origin; set intercept = 0<br />
NB: don’t display the equation on the chart.<br />
23
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Plotting Error Bars<br />
Click on one of the points on your graph. This should highlight all of the points.<br />
Click FORMAT – SELECTED DATA SERIES<br />
To set the error bars, choose the X ERROR BARS <strong>and</strong> Y ERROR BARS folders. In each<br />
folder, you should:<br />
Display: BOTH<br />
Error amount: FIXED VALUE – insert your absolute error for each variable.<br />
NB: you cannot enter different uncertainty values for one particular variable. These would<br />
need to be done manually if required.<br />
The graph below has uncertainties of ±0.2s for the time values <strong>and</strong> ±0.4m/s for the speed<br />
values.<br />
Graph 1: speed vs time for car rolling down ramp A Einstein 11RCH<br />
12<br />
10<br />
8<br />
Speed (m/s)<br />
6<br />
4<br />
2<br />
0<br />
-1 0 1 2 3 4 5 6<br />
Time (s)<br />
Your chart is now ready to PRINT!<br />
Use this data to do your own table <strong>and</strong> graph. H<strong>and</strong> this in for HOMEWORK!!<br />
24
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Graphical <strong>Analysis</strong> of <strong>Data</strong><br />
In many experiments, the goal is to determine a relationship between two variables. This can<br />
be done by plotting a graph with the independent variable on the horizontal-axis <strong>and</strong> the<br />
dependent variable on the vertical-axis.<br />
The shape of the graph can then be used to establish the nature of the relationship!<br />
Linear graphs<br />
When you get a linear or straight-line graph, you can easily determine the relationship<br />
between the variables. Let us consider a simple straight line graph:<br />
v (m/s)<br />
v (m/s)<br />
gradient , m =<br />
t (s)<br />
rise<br />
run<br />
This graph shows a linear relationship between v <strong>and</strong><br />
t. The mathematical relationship is: v ∝ t.<br />
The mathematical equation is: v = mt + c<br />
gradient , m =<br />
rise<br />
run<br />
This graph shows a direct relationship between v<br />
<strong>and</strong> t. The mathematical relationship is: v ∝ t.<br />
The mathematical equation is: v = mt<br />
t (s)<br />
The unit associated with the gradient can be determined by finding the ratio of the rise/run<br />
units. In the examples above, the units of the gradient quantity are:<br />
riseunit<br />
rununit<br />
m s<br />
= = m s or m s<br />
s<br />
2 !2<br />
Examples:<br />
1. If the vertical axis is force(N) <strong>and</strong> the horizontal axis is distance(m), what will the units of<br />
the gradient be?<br />
2. If the horizontal axis is time (s) <strong>and</strong> the vertical axis is distance(m), what will the units of<br />
the gradient be?<br />
3. If the vertical axis is degrees (°) <strong>and</strong> the horizontal axis is degrees (°), what will the units<br />
of the gradient be?<br />
25
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Non-linear Graphs<br />
If your graph does not show a direct or linear relationship, it will probably look like one of<br />
the lines shown below:<br />
A B C<br />
D E F<br />
These are lines obtained for common relationships other than direct or linear relationships.<br />
All of the above may be expressed mathematically as: y ∝ x n<br />
<strong>and</strong> hence by a simple equation:<br />
y = kx n<br />
where y is the dependent variable, x is the independent variable, <strong>and</strong> k <strong>and</strong> n are both<br />
constants.<br />
n is usually one of –2, -1, -½, 0, ½, 1, 2 or 3. The coefficient k has a unit, but n is<br />
dimensionless!<br />
Exercise<br />
1. For each graph shown above, write down:<br />
the type of relationship that it shows (in words).<br />
the mathematical relationship that exists between x <strong>and</strong> y.<br />
the mathematical equation between x <strong>and</strong> y.<br />
2. What is the value of n for: A? B? C? D? E? F?<br />
3. What is the value of n for a linear relationship?<br />
26
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Finding the quantitative relationship!<br />
If the graph that you plot looks like one of those just discussed, you can determine the correct<br />
nature of the relationship by plotting additional graphs.<br />
• First, plot the original data.<br />
• Second, decide what the relationship could be i.e. it may look like a square relationship.<br />
• Third, plot a graph of your guess i.e. a vs b 2 . (You will need to calculate b 2 values to do<br />
this.)<br />
• Then, if this graph is a straight line, you can work out the equation.<br />
F<br />
Plot data <strong>and</strong> identify relationship.<br />
parabola ⇒ square relationship F ∝ t 2<br />
t<br />
F<br />
If this graph is linear, you can calculate the<br />
gradient <strong>and</strong> work out the equation.<br />
i.e. F = gradient × t 2<br />
t 2<br />
If your first guess was incorrect, i.e. you guessed y ∝ x 3 , your graph of y vs x 3 will not give<br />
a straight line <strong>and</strong> you will need to have another go!<br />
NB: a relationship <strong>and</strong> hence an equation can only be determined if a straight line graph<br />
has been obtained.<br />
It is important that you follow the graphical analysis process <strong>and</strong> are not influenced by<br />
your knowledge of what the relationship might be. For example, if you are investigating<br />
the relationship between light intensity I <strong>and</strong> distance d, you could find that I ∝ 1/d 2 from<br />
a text book. As a scientist, however, you must not let this affect the way that you analyse<br />
the data. You must act as though you do not know the outcome <strong>and</strong> first plot a graph of I<br />
vs d. This should be hyperbolic, so you would next plot I vs 1/d. If this is linear, you<br />
would have to conclude that your relationship was inverse in nature <strong>and</strong> be prepared to<br />
discuss why your results differed from the known value. You might find that this graph is<br />
parabolic <strong>and</strong> so would plot I vs 1/d 2 . If this graph was linear, you could conclude that<br />
there was an inverse square relationship between I <strong>and</strong> d <strong>and</strong> you would be able to say<br />
that your findings agreed with the theoretical relationship.<br />
27
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Graphical <strong>Analysis</strong> Exercises<br />
1. Beneath each graph, indicate the most likely relationship that exists <strong>and</strong> state the<br />
equation expressing this relationship.<br />
P B L<br />
(a) (b) (c)<br />
Q A M<br />
2. What graph would you plot to check your answer to 1(a)?<br />
3. What graph would you plot to check your answer to 1(b)?<br />
4. What graph would you plot to check your answer to 1(c)?<br />
5. Using graphical analysis, work out the equation that defines the relationship between the<br />
pairs of variables below. Also indicate the value of k <strong>and</strong> give its unit.<br />
(a) (b) (c)<br />
mass<br />
(kg)<br />
acceleration<br />
(m s -2 )<br />
velocity<br />
(m s -1 )<br />
kinetic energy<br />
(J)<br />
diameter<br />
(cm)<br />
resistance,<br />
(Ω)<br />
1.00 98 0.00 0.00 0.60×10 -2 51.3<br />
2.00 52 1.00 2.05 1.0×10 -2 16.0<br />
4.00 24.1 2.00 7.90 1.3×10 -2 10.2<br />
5.00 20.4 3.00 17.6 1.7×10 -2 5.9<br />
10.0 9.7 4.00 32.5 3.5×10 -2 1.42<br />
In each case, the first variable is the independent variable. This must be plotted on the<br />
horizontal axis.<br />
Show your graphs <strong>and</strong> calculations on the graph paper following!<br />
28
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
mass,<br />
(kg)<br />
acceleration,<br />
(m s -2 )<br />
1.00 98<br />
2.00 52<br />
4.00 24.1<br />
5.00 20.4<br />
10.0 9.7<br />
29
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Answers to Worksheets <strong>and</strong> Exercises<br />
velocity<br />
(m s -1 )<br />
kinetic<br />
energy (J)<br />
0.00 0.00<br />
1.00 2.05<br />
2.00 7.90<br />
3.00 17.6<br />
4.00 32.5<br />
30
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
diameter, resistance (Ω)<br />
(cm)<br />
0.60×10 -2 51.3<br />
1.0×10 -2 16.0<br />
1.3×10 -2 10.2<br />
1.7×10 -2 5.9<br />
3.5×10 -2 1.42<br />
31
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
32
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Answers to Exercises<br />
Prefixes<br />
(a) 6,000,000 W<br />
(b) 6,000,000 W<br />
(c) 0.5 s<br />
(d) 15,000,000 m<br />
(e) 0.000000003 m<br />
(f) 25,000,000,000 Hz<br />
(g) 0.000005 m<br />
(h) 0.00025 s<br />
Conversion of <strong>Units</strong><br />
(a) 100 mm 2<br />
(b) 1.0×10 6 m 2<br />
(c) 1.0×10 -6 m 2<br />
(d) 1.0×10 6 mm 2<br />
(e) 1.0×10 12 µm 2<br />
(f) 1.0×10 3 mm 3<br />
(g) 1.0×10 6 cm 3<br />
(h) 1.0×10 -18 m 3<br />
(i) 1.0×10 -9 km 3<br />
(j) 1.0×10 -9 m 3<br />
Worksheet: <strong>Units</strong> <strong>and</strong> Conversions<br />
1(a) 25 m<br />
(b) 3.3×10 -8 m<br />
(c) 360 m<br />
2(a) 0.15 m 2<br />
(b) 6.0×10 -8 m 2<br />
(c) 4.2×10 5 m 2<br />
3(a) 35 cm 3<br />
(b) 3.0×10 6 cm 3<br />
(c) 5.6×10 -5 cm 3<br />
4(a) 0.37 A<br />
(b) 0.09 A<br />
(c) 3.0×10 -8 A<br />
5(a) 4.4×10 4 g<br />
(b) 64 g<br />
(c) 70 kg<br />
6. kg m s -1<br />
N m<br />
m s -1<br />
m s -2<br />
N s<br />
A s<br />
J C -1<br />
V A -1<br />
Significant Figures<br />
1(a) micrometer<br />
(b) 30 cm ruler<br />
(c) metre ruler<br />
2(b) 2, 6.3×10 -6 A<br />
(c) 2,<br />
(d) 3,<br />
(e) 3,<br />
(f) 3,<br />
(g) 2 or 3,<br />
3(a) 4<br />
(b) 2<br />
(c) 4<br />
(d) 3<br />
(e) 2<br />
(f) 3<br />
4. 335.31 m<br />
5. 6883 m 2<br />
7. 6.2 m s -1<br />
2.7×10 4 J<br />
3.53×10 5 m<br />
6.07×10 -6 m<br />
2.50×10 -7 A<br />
150 kg<br />
Uncertainties in <strong>Measurement</strong>s<br />
1. 5.4 mm 3<br />
0.5 N<br />
360 K<br />
30°C<br />
55 cm<br />
740 g<br />
0.3 N<br />
2 (a) ±0.1 g (b) ±1°C (c) ±0.01 mA (d) ±0.001 mm<br />
Uncertainty Exercises<br />
1(a) 57±1 cm<br />
(b) 112±1 m s -1<br />
(c) 1.6±0.1 mg<br />
(d) 64±2 m<br />
(e) 0.085±0.003 kV<br />
(f) 10.4±0.1 mm<br />
(g) 15±3 mA<br />
(h) 0.3±0.2 kg<br />
(i) 27.0±0.1 kg<br />
(j) 45±2 m<br />
2(a) 1.8%<br />
(b) 0.9%<br />
(c) 6.3%<br />
(d) 3.1%<br />
(e) 3.5%<br />
(f) 1%<br />
(g) 20%<br />
(h) 67%<br />
(i) 0.4%<br />
(j) 4.4%<br />
3(a) 2.6±0.1<br />
(b) 0.5±0.1<br />
(c) 1.90±0.01<br />
(d) 30±1<br />
(e) 0.017±0.001A<br />
(f) 110±5V<br />
(g) 2.7±0.1V<br />
(h) 25±5mA<br />
(i) 3.9±0.1V<br />
33
Penleigh <strong>and</strong> Essendon Grammar School<br />
<strong>Data</strong> <strong>Analysis</strong> Booklet<br />
Error <strong>Analysis</strong> Exercises<br />
1(a) 61.7±0.6 m; 61.7 m ±1.0%<br />
(b) 63.0±0.8 m; 63.0 m ±1.3%<br />
(c) 94.5 m 2 ±1.7%; 95±2 m 2<br />
(d) 110 m 2 ±3.5%; 110±4 m 2<br />
(e) 24.0±0.3 m; 24.0 m ±1.3%<br />
(f) 390 m 3 ±4.1%; 390±20 m 3<br />
Repeat samples worksheet<br />
(a) D = 3.01±0.04 m<br />
W = 8.69±0.06 m<br />
L = 50.02±0.07 m<br />
(b) (i) 435 m 2 ±0.8%; 435±3 m 2<br />
(ii) 1310 m 3 ± 2.1%; 1310±30 m 3<br />
(iii) 117.4 ± 0.3 m; 117.4 m ± 0.3%<br />
Graphical <strong>Analysis</strong> Exercises<br />
1(a) square; P = kQ 2<br />
(b) inverse; B = k/A<br />
(c) square root; L = k√A<br />
2. P vs Q 2<br />
3. B vs 1/A<br />
4. L vs √M<br />
5(a) k = 100 kg m s -2 ; a = 100/m<br />
(b) k = 2.0 J m -2 s 2 ; E K = 2.0 v 2<br />
(c) k = 0.0018 Ω cm 2 ; R = 0.0018/d 2<br />
Homework Exercise: Marbles!<br />
1 The percentage error for oil is much lower.<br />
The times for oil are more accurate because the<br />
marble would be moving more slowly making it<br />
easier to time precisely.<br />
2 water: 3.1±0.4 s; oil; 6.7±0.2 s<br />
3 water: 0.34±0.05 m s -1 ; oil: 0.16±0.01 m s -1<br />
Non-linear Graphs Exercise<br />
1(a) independent; y is independent of x; no<br />
equation<br />
(b) square; y ∝ x 2 ; y = kx 2<br />
(c) cubic; y ∝ x 3 ; y = kx 3<br />
(d) square root; y ∝ √x; y = k√x<br />
(e) inverse; y ∝ 1/x; y = k/x<br />
(f) inverse square; y ∝ 1/x 2 ; y = k/x 2<br />
2(a) 0<br />
(b) 2<br />
(c) 3<br />
(d) 0.5<br />
(e) –1<br />
(f) –2<br />
3. one<br />
34