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Name:<br />

Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

<strong>Units</strong> <strong>and</strong> <strong>Conventions</strong><br />

Fundamental <strong>Units</strong><br />

Derived <strong>Units</strong><br />

Prefixes<br />

St<strong>and</strong>ard Form<br />

Conversions of <strong>Units</strong><br />

<strong>Measurement</strong><br />

Significant Figures<br />

Uncertainties in <strong>Measurement</strong>s<br />

Uncertainties in Single <strong>Measurement</strong>s<br />

Absolute <strong>and</strong> percentage errors<br />

Showing Uncertainties on Graphs<br />

Advanced Error <strong>Analysis</strong><br />

Uncertainties when taking Repeat Samples<br />

<strong>Data</strong> <strong>Analysis</strong><br />

Experimental Design<br />

How to Write a Formal Practical Report!<br />

Doing Graphs <strong>and</strong> Tables on EXCEL<br />

Graphical <strong>Analysis</strong> of <strong>Data</strong><br />

Linear Graphs<br />

Non-linear Graphs<br />

Finding the relationship!s image may not be reproduced in any form or by any means<br />

without the prior written permission of the museum.<br />

This is an armillary sphere It is a medieval<br />

scientific instrument that st<strong>and</strong>s about 3 m tall –<br />

around double the height of the average person.<br />

It was constructed in Florence around 1590 <strong>and</strong><br />

took almost a decade to complete. It was used to<br />

chart the movement of the stars <strong>and</strong> planets.<br />

Today a simple computer program could do the<br />

same job with much greater precision.<br />

1


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

UNITS AND CONVENTIONS<br />

Physics is an experimental science dealing largely with measurements. In Physics, the data<br />

that you collect <strong>and</strong> the numbers that you work with in problems are not just numbers. They<br />

are measurements of physical quantities such as mass, time, temperature, etc.<br />

Fundamental <strong>Units</strong><br />

In 1960, the international authority on units <strong>and</strong> measures agreed to adopt a st<strong>and</strong>ardised<br />

system known as the International System (SI) of units. There are many different physical<br />

quantities, but in the SI system, seven are defined as fundamental or basic quantities. They<br />

are:<br />

Fundamental Quantity<br />

length<br />

mass<br />

time<br />

electric current<br />

temperature<br />

luminous intensity<br />

amount of substance<br />

Unit <strong>and</strong> Symbol<br />

metre (m)<br />

kilogram (kg)<br />

second (s)<br />

ampere (A)<br />

kelvin (K)<br />

c<strong>and</strong>ela (Cd)<br />

mole (mol)<br />

In Physics, we will be dealing with the first 5 of these quantities many, many times!<br />

Derived <strong>Units</strong><br />

Other physical quantities (e.g. speed) can be measured in units that are derived from these<br />

fundamental units.<br />

e.g. Speed is defined as:<br />

speed<br />

=<br />

distance<br />

travelled<br />

time taken<br />

The unit for speed is m/s or m s -1 . This is derived from the fundamental units for length <strong>and</strong><br />

time.<br />

e.g. The kinetic energy of an object is: E k = 1 2 mv2<br />

The unit for kinetic energy is: kg × (m/s) 2 = kg m 2 / s 2 or kg m 2 s -2 . Again, this is derived in<br />

terms of fundamental units. This unit of energy is more commonly known as a joule (J).<br />

e.g. the unit for area is square metres. Area unit = length unit × length unit = m × m = m 2<br />

Worked Example<br />

Newton’s 2 nd Law states that a net force applied to a body is equal to the product of its mass<br />

<strong>and</strong> acceleration i.e. ΣF = ma<br />

What is the derived unit for force?<br />

Unit of force =<br />

2


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Solution: This derived unit (kg m s -2 ) also has a special name. It is called a newton (N).<br />

Some derived units are shown in the table below.<br />

Derived Quantity Unit Symbol<br />

frequency hertz Hz<br />

force newton N<br />

energy or work joule J<br />

power watt W<br />

electric potential volt V<br />

resistance ohm Ω<br />

temperature degree Celsius °C<br />

Prefixes<br />

Often you will be measuring quantities that are very big (e.g. the resistance of your body) or<br />

very small (e.g. the thickness of a hair). When dealing with values such as these, it is<br />

necessary to use prefixes with the units. Prefixes represent decimal fractions or multiples of<br />

the original SI unit.<br />

Prefix Abbreviation Value<br />

tera T 10 12<br />

giga G 10 9<br />

mega M 10 6<br />

kilo k 10 3<br />

milli m 10 -3<br />

micro µ 10 -6<br />

nano n 10 -9<br />

pico p 10 -12<br />

Notice that these power values occur in multiples of three. This is consistent with the<br />

convention of organising large numbers in groups of three e.g 15,000,000,000.<br />

Other prefixes that you will encounter are: centi, c, 10 -2 ; hecto, h, 10 2 <strong>and</strong> deci, d, 10 -1<br />

Exercises: Complete these statements:-<br />

a) 6 MW = W<br />

b) 6,000 kW = W<br />

c) 500 ms = s<br />

d) 15,000 km = m<br />

e) 3 nm = m<br />

f) 25 GHz = Hz<br />

g) 5 µm = m<br />

h) 0.25 ms = s<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

St<strong>and</strong>ard Form<br />

When working with big or small numbers, it is often time consuming or clumsy to write the<br />

number out in full. For example, the speed of light in a vacuum is 300,000,000 m s -1 . The<br />

convention is to express this in st<strong>and</strong>ard form or scientific notation as 3.00×10 8 m s -1 .<br />

In tests <strong>and</strong> exams, it is expected that numbers greater than 1000 or less than 0.01 will be<br />

written in st<strong>and</strong>ard form.<br />

On your calculator, the EXP button is used for writing values in st<strong>and</strong>ard form.<br />

Use your calculator to determine: 3.00×10 8 ×5.0×10 -6 =<br />

Conversion of <strong>Units</strong><br />

Often you will need to convert from one unit to another. For example, if you measure the<br />

length <strong>and</strong> width of your desk in centimetres, but you want to know its area in square metres.<br />

You will need to convert square centimetres into square metres. This involves working in 2<br />

dimensions.<br />

Area<br />

100 cm<br />

100 cm<br />

1 m 2 1 m 3 1 m 2 = 100 cm × 100 cm<br />

= 10,000 cm 2<br />

Similarly, if you measure the length, width <strong>and</strong> thickness of your textbook in millimetres but<br />

wish to find its volume in cubic metres. This will involve a 3 dimensional conversion from<br />

cubic centimetres into cubic metres.<br />

Volume<br />

100 cm<br />

100 cm<br />

1 m 3 = 100cm × 100cm × 100cm<br />

= 1,000,000 cm 3<br />

= 1.0×10 6 cm 3<br />

100 cm<br />

Exercises: Complete these conversions:<br />

(a) 1 cm 2 = mm 2<br />

(f) 1 cm 3 = mm 3<br />

(e) 1 m 2 = µm 2 (j) 1 mm 3 = m 3<br />

(b) 1 km 2 = m 2<br />

(g) 1m 3 = cm 3<br />

(c) 1 mm 2 = m 2<br />

(h) 1 µm 3 = m 3<br />

(d) 1m 2 = mm 2<br />

(i) 1 m 3 = km 3<br />

4


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

WORKSHEET: <strong>Units</strong> <strong>and</strong> Conversions<br />

Remember to express numbers greater than 1000 or less than 0.01 in<br />

st<strong>and</strong>ard form!<br />

1. Convert these lengths into metres (m):<br />

a) 25,000,000 µm =<br />

b) 33 nm =<br />

c) 360,000 mm =<br />

2. Convert these areas into square metres (m 2 ):<br />

a) 1500 cm 2 =<br />

b) 60,000 µm 2 =<br />

c) 0.42 km 2 =<br />

3. Convert these volumes into cubic centimetres (cm 3 ):<br />

a) 35,000 mm 3 =<br />

b) 3 m 3 =<br />

c) 56,000,000 µm 3 =<br />

4. Convert these current readings into amperes (A):<br />

a) 370 mA =<br />

b) 90,000 µA =<br />

c) 0.03 µA =<br />

5. Convert these mass measurements:<br />

a) 44 kg = g<br />

b) 64,000 mg = g<br />

c) 70,000,000,000 µg = kg<br />

6. Express these units in terms of the fundamental SI units.<br />

Name <strong>and</strong> Symbol Definition Unit Special Name<br />

force, F mass×acceleration kg m s -2 newton, N<br />

momentum, p<br />

mass×velocity<br />

work, W force×distance joule, J<br />

velocity, v<br />

acceleration, a<br />

impulse, I<br />

displacement/time<br />

velocity/time<br />

force×time<br />

charge, Q current×time coulomb, C<br />

voltage, V<br />

resistance, R<br />

work/charge<br />

voltage/current<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

MEASUREMENT<br />

Expressing the Accuracy of a <strong>Measurement</strong><br />

When you obtain a measurement during an experiment or work with measurements when<br />

solving problems, you need to be mindful of a number of important conventions.<br />

Significant Figures<br />

When you obtain data during an experiment, the accuracy of a measurement will depend on<br />

the precision of the instrument or meter being used.<br />

For example, if you use a metre rule to measure the diameter of a ball bearing, you might<br />

obtain a result of 1.2 cm. However, if you used a micrometer to measure the diameter instead,<br />

the result might be 1.258 cm. The micrometer is far more precise <strong>and</strong> gives a much more<br />

accurate answer.<br />

The metre rule has given two figures or digits that we know about with some confidence. We<br />

say that the data (1.2 cm) has 2 significant figures. The data from the micrometer (1.258 cm)<br />

has allowed us to know the diameter of the ball bearing to 4 significant figures.<br />

The number of significant figures in a measurement can be found using 4 simple rules:<br />

• All non-zero figures are significant, e.g. 15.75 kg has 4 significant figures.<br />

• All zeros in between non-zero digits are also significant, e.g. 2.09 m has 3 sig figs.<br />

• All zeros that follow a non –zero digit <strong>and</strong> are to the right of the decimal point are<br />

significant.<br />

e.g. 21.40 g has 4 significant figures.<br />

0.5 mm has 1 significant figure.<br />

0.100 kg has 3 significant figures.<br />

• Zeros used for placing very small or very large numbers are not significant.<br />

e.g. 0.00000031 V has 2 significant figures<br />

4,550,000,000,000,000 m has 3 significant figures.<br />

It is often confusing when dealing with whole numbers ending with zero.<br />

For example; 6,600 mm could have 2, 3 or 4 significant figures.<br />

To overcome this confusion, it should be written in st<strong>and</strong>ard form as:<br />

6.6×10 3 mm if you wish to show 2 sig figs, or<br />

6.60×10 3 mm if you wish to show 3 sig figs <strong>and</strong> so on.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Addition <strong>and</strong> Subtraction of <strong>Measurement</strong>s<br />

When adding or subtracting data, the measurements must be rounded off to the least number of<br />

decimal places that are present in the data.<br />

e.g.<br />

13.305 mm<br />

10.24 mm<br />

+2.0522 mm<br />

25.5972 mm<br />

This must be rounded off to 2 decimal places (25.60 mm) because 10.24 has just 2 decimal places.<br />

The same applies for subtraction problems.<br />

Multiplication <strong>and</strong> Division of <strong>Measurement</strong>s<br />

When multiplying or dividing data, your answer must be rounded off to the least number of<br />

significant figures in your data.<br />

e.g. 0.50 cm × 26.84 cm = 13.42 cm 2 .<br />

This must be rounded off to 13 cm 2 because 0.50 cm has<br />

only 2 sig figs.<br />

2 sig figs 4 sig figs<br />

The same applies when dividing measurements.<br />

NB: These rules only apply when working with measurements. For example, if the mass of one<br />

marble is 26.7 g, then the mass of 5 identical marbles is:<br />

5×26.7 g = 133.5 = 134 g. The answer still has 3 significant figures. The ‘5’ is not a<br />

measurement! What are its units??<br />

Also take care when using pi!<br />

TAKE NOTE!!<br />

You must be mindful of significant figures when writing practical reports <strong>and</strong> when<br />

answering test questions. If you have too many or too few significant figures in your data or<br />

in your answers, you will lose marks!!!<br />

7


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

WORKSHEET: SIGNIFICANT FIGURES<br />

1. The length of an object is measured 3 times using 3 different measuring instruments.<br />

The results obtained were: a) 92.71 mm b) 93 mm c) 9 cm<br />

Which result was obtained using a blackboard ruler, a micrometer <strong>and</strong> a 30 cm ruler?<br />

2. For each of the measurements recorded below, write down its number of significant figures<br />

<strong>and</strong> express it in scientific notation with the correct SI unit. The first example has been<br />

completed for you.<br />

<strong>Measurement</strong> Significant figures St<strong>and</strong>ard Form, SI unit<br />

(a) 13.05 kg 4 13.05 kg<br />

(b) 0.0000063 A<br />

(c) 27 kJ<br />

(d) 353,000,000 mm<br />

(e) 0.00607 mm<br />

(f) 0.250 µA<br />

(g) 150 kg<br />

3. How many significant figures are quoted in each of the following measurements?<br />

a) 783.9 kJ b) 0.035 cm c) 90.24 kg d) 86,400 s e) 0.0060 m f) 6.07×10 7 m<br />

4. What is the perimeter of a soccer field if its length <strong>and</strong> width were measured to be 95.82 m<br />

<strong>and</strong> 71.836 m respectively?<br />

5. What is the area (in m 2 ) of the soccer field discussed in Question 4?<br />

6. Use your 30 cm ruler to measure the length <strong>and</strong> width of this page.<br />

length = cm<br />

width = cm<br />

Use these results to determine: (a) the perimeter of the page (b) the area of the page<br />

7. Mary runs 25.3 m in 4.1 s. What was her average speed?<br />

8


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Uncertainties in <strong>Measurement</strong>s<br />

When we take measurements <strong>and</strong> readings with different analogue instruments, there is<br />

always a limit to how accurately we can obtain our results. If we use a metre ruler to measure<br />

the thickness of a 50 c coin, we can gain a result to the nearest millimetre i.e. 2 mm.<br />

However, if we use a more precise instrument such as a micrometer (which measures to the<br />

hundredth of a millimetre!), we could say that the thickness is 2.46 mm. If using a digital<br />

device that is giving a stable reading, there is an uncertainty of ±1 in the last digit. The<br />

accuracy with which we record all our measurements must reflect the type of device that was<br />

used to obtain the measurements. We should not record too many decimal places, nor should<br />

we record too few.<br />

This measurement would be recorded as 225 g. It is not<br />

possible to read it more precisely, as say 224.3 g. It would<br />

also be incorrect to write down 225.00 g.<br />

This measurement could be<br />

accurately recorded as 450.75 g.<br />

Exercise:.<br />

1. Record each of the analogue measurements below to the appropriate level of precision<br />

2. What is the uncertainty for these digital readings?<br />

(a) 16.3 g (b) 52 °C (c) 2.06 mA (d) 0.094 mm<br />

9


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Uncertainties in Single <strong>Measurement</strong>s<br />

When we take measurements <strong>and</strong> readings, there is always uncertainty involved. This<br />

uncertainty is related to the quality of the apparatus <strong>and</strong> the skill of the experimenter. It is not<br />

possible to obtain exact values! Most measurements will vary slightly from the actual value.<br />

The difference between the two is the error or uncertainty.<br />

NB: an error does not necessarily imply a mistake; just an imprecision!!<br />

Absolute errors<br />

The reading taken using the ruler shown above would be recorded as 55.6 cm. However, the<br />

actual length will in fact be slightly higher or lower than 55.6 cm. Using the ruler, we can<br />

distinguish between 55.5, 55.6, <strong>and</strong> 55.7 cm, but is unreasonable to say that the measurement<br />

is 55.63 cm. This ruler is only accurate to the nearest millimetre. To indicate that the length is<br />

somewhere between 55.5 <strong>and</strong> 55.7 cm, we can say that:<br />

length = 55.6±0.1 cm<br />

This ±0.1 cm is known as the absolute uncertainty associated with the reading. In general,<br />

the uncertainty associated with any measured value is taken to be half of the limit of the<br />

reading of the device, or half of the smallest division of the scale being used.<br />

The smallest division on the metre ruler above is 0.2 cm, hence the uncertainty is 0.1 cm.<br />

What absolute uncertainty would apply if you used your ruler?<br />

According to this convention, the reading on the force meter on the previous page should be<br />

recorded as 0.3±0.05 N. This reading, however, is not strictly correct. There are some other<br />

important rules <strong>and</strong> conventions that must be followed!<br />

• There must be the SAME NUMBER OF DECIMAL PLACES in both the<br />

MEASUREMENT <strong>and</strong> the ABSOLUTE UNCERTAINTY.<br />

e.g. 55.7±0.1 cm 30.35±0.05 kg 74±2 g<br />

e.g. 46.1±0.06 mm 85±0.5 kg 43.6±1 mA<br />

• An absolute uncertainty must only have ONE SIGNIFICANT FIGURE <strong>and</strong> will often<br />

need to be rounded off.<br />

10


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

For example, if a scale has a smallest division of 0.5 N, the absolute uncertainty will be ±0.25<br />

N which will need to be rounded off to ±0.3 N.<br />

If the scale of the instrument is very large, you can use your judgement to determine the<br />

uncertainty.<br />

In the example below, half of the smallest division is 0.25 which must be rounded off to 0.3.<br />

This would give a reading of 4.6±0.3 which suggests that the value could be anywhere<br />

between 4.3 <strong>and</strong> 4.9. We can obviously be more precise than that. In this case, the value<br />

could be recorded as 4.60±0.05.<br />

Percentage Errors<br />

An uncertainty could also be expressed as a percentage error.<br />

percentage<br />

absolute error 100<br />

error =<br />

!<br />

measurement 1<br />

0.05 100<br />

In this example, the percentage error is: % error = ! = 1.1%<br />

4.60 1<br />

Percentage errors are usually written with:<br />

• 1 significant figure when less than 1%<br />

• 2 significant figures when 1% or greater.<br />

For example, if you calculate an error to be 0.75%, you should round this off to 0.8%. Also,<br />

an error of 5.681% needs to be rounded off to 5.7%.<br />

Percentage errors give a better representation of the accuracy of the measurement than do<br />

absolute errors. Consider these 2 measurements:<br />

530±5 s <strong>and</strong> 10±5 s<br />

The absolute error is the same in each measurement (±5s) , but this error is far more<br />

significant in the second case.<br />

5 100<br />

The percentage error for the first result is: % error = ! = 0.94%<br />

. This is very<br />

530 1<br />

accurate; less than 1% error.<br />

In the second measurement, the error is 50%. Perhaps the experimental technique used needs<br />

to be improved in order to obtain more precise data!<br />

11


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Examples of correct <strong>and</strong> incorrect error readings are given below. Complete the ones that are<br />

missing.<br />

Incorrect Reading Correct Version Incorrect Reading Correct version<br />

20.876±0.2 s 20.9±0.2 s 7.5±0.62 m/s<br />

27±0.6 mm 27±1 mm 0.352±0.02 ms<br />

85.45±0.25 kg 85.5±0.3 kg 59±1.6 m 3<br />

28.6 K ± 0.87% 28.6 K± 0.9% 8.05 km± 4.71%<br />

WORKSHEET: UNCERTAINTY EXERCISES<br />

1. Fix up these incorrect measurements:<br />

(a) 57±0.5 mm<br />

(f) 10.4±0.065 mm<br />

(b) 112.3±1 m/s<br />

(g) 15±2.5 mA<br />

(c) 1.6±0.05 mg<br />

(h) 0.34±0.15 kg<br />

(d) 64.4±1.8 m<br />

(i) 27.03±0.1 kg<br />

(e) 0.085±0.0025 kV<br />

(j) 45.0±2 m<br />

2. Determine the percentage uncertainties for your answers in Question 1.<br />

3. Record the readings on these meters <strong>and</strong> scales as accurately as is appropriate. Indicate the associated<br />

uncertainties, being mindful of the conventions that you have just learnt.<br />

12


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Showing Uncertainties on Graphs<br />

Many experiments in Physics can be analysed using graphs. When drawing graphs, straight<br />

lines or curves of best fit must be plotted. There should be about the same number of data<br />

points above <strong>and</strong> below these lines of best fit.<br />

There is an uncertainty associated with each point that is plotted on a graph. Error bars are<br />

used to show this uncertainty.<br />

E.g. Consider the following data:<br />

length(cm)<br />

resistance (Ω)<br />

14.5±0.5 0.22±0.02<br />

Let us consider how the data should be shown on the graph. First, we plot the data value<br />

(14.5 cm, 0.22 Ω). Then we must indicate the uncertainty of this point using error bars.<br />

For the resistance data, the value could range from a minimum of 0.22 – 0.02 = 0.20 up to a<br />

maximum of 0.22 + 0.02 = 0.24. We indicate this range by drawing a line between 0.20 <strong>and</strong><br />

0.24 Ω as shown on the graph. This line is called an error bar.<br />

Similarly, the error bar for length should be drawn between 14.0 <strong>and</strong> 15.0 cm.<br />

• It is important to remember that your line of best fit should pass through or touch ALL of<br />

the error bars that you have drawn.<br />

• Often, error bars will be too small to be shown on a graph. If this is the case, include a<br />

statement to that effect underneath the graph. However, the uncertainties must always<br />

be shown in your tables of results.<br />

• When doing graphical analysis, it is usually only necessary to show error bars on your<br />

first graph.<br />

Worksheet: Error bars!<br />

13


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Advanced Error <strong>Analysis</strong><br />

Sometimes you may wish to use your data to obtain a different physical quantity. For<br />

example, you have measured the length <strong>and</strong> width of a classroom as 5.85±0.05 m <strong>and</strong> 4.2±0.1<br />

m respectively. Now want to calculate the perimeter <strong>and</strong> area of the room. You can do this by<br />

performing a simple calculation. It is also possible to determine the uncertainty for these<br />

derived quantities.<br />

Adding <strong>and</strong> Subtracting <strong>Measurement</strong>s<br />

The room has: length = 5.85±0.05 m<br />

width = 4.2±0.1 m<br />

4.2±0.1 m<br />

5.85±0.05 m<br />

To calculate the perimeter value, you will need to perform the following addition:<br />

5.85 m<br />

4.2 m<br />

5.85 m<br />

+ 4.2 m___<br />

20.10 m_<br />

Recall that the answer is limited by the least number of decimal places for addition <strong>and</strong><br />

subtraction problems. In this case, that is 1 decimal place. The answer must therefore be<br />

given as:<br />

Perimeter = 20.1 m.<br />

When adding or subtracting<br />

measurements, the total absolute error<br />

is found by ADDING the individual<br />

absolute errors.<br />

The uncertainty is therefore: 0.1+0.05+0.1+0.05 = 0.30 m.<br />

Recall that absolute errors can only have 1 significant figure, so the measurement must be<br />

written as:<br />

Perimeter = 20.1±0.3 m<br />

The technique for subtraction is the same i.e the absolute errors are ADDED! This would<br />

be useful when finding the error associated with the change in a quantity.<br />

14


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Multiplying <strong>and</strong> Dividing <strong>Measurement</strong>s<br />

If you wished to calculate the area of the classroom, you would simply multiply the length<br />

<strong>and</strong> width measurements.<br />

4.2±0.1 m<br />

5.85±0.05 m<br />

Area = 4.2×5.85 = 24.57 m 2<br />

Recall that when measurements are multiplied or divided, the answer is limited by the least<br />

number of significant figures in the measurements. In this example, the least number is two<br />

(in 4.2 m), so this answer must be written as:<br />

Area = 25 m 2<br />

To calculate the absolute error for this value, you must add the percentage errors of the<br />

measurements.<br />

% error for length = 0.05<br />

5.85 " 100<br />

1 = 0.85%<br />

% error for width = 0.1<br />

4.2 "100 1 = 2.4%<br />

The percentage error for area is:0.85 + 2.4 = 3.25%. This would be rounded off to:<br />

Area = 25 m 2 ±3.3%<br />

The absolute error for area is found simply calculating 3.3% of 25 m 2 = ±0.83m 2 . So the<br />

area value can be stated as: Area = 25 ±0.83 m 2<br />

However, the absolute error can only have 1 significant figure, so the final result must be<br />

given as:<br />

Area = 25 ±1 m 2<br />

When multiplying or dividing measurements, the individual<br />

percentage errors must be ADDED to find the total percentage<br />

error.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

ERROR ANALYSIS EXERCISE<br />

1. Consider the following dimensions of a room in an art gallery. Calculate, giving both<br />

percentage <strong>and</strong> absolute errors, the following quantities.<br />

h = 4.1±0.1 m<br />

(a) the floor perimeter.<br />

l = 27.4±0.3 m<br />

w = 3.45±0.02 m<br />

(b) perimeter of the large wall.<br />

(c) the floor area.<br />

(d) the large wall area.<br />

(e) the difference between the length <strong>and</strong> width of the floor.<br />

(f) the volume of the space.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Uncertainties when taking Repeat Samples<br />

When performing experiments in class, time constraints usually mean that only one<br />

measurement is taken for each data point. This measurement is quite unreliable because there<br />

may have been inaccuracies with the equipment or in the way in which the result was<br />

obtained for that particular result. As you will be aware, if you repeat the same experiment 4<br />

or 5 times, you will get 4 or 5 slightly different values. This does not mean that you have<br />

done something wrong; it simply indicates the r<strong>and</strong>om nature of uncertainties. (If your<br />

results are vastly different, however, you might want to have a look at your experimental<br />

technique!).<br />

In order to obtain results that are more reliable, it is necessary to take repeat samples for<br />

each particular data point <strong>and</strong> use this to obtain an average value. It is always better,<br />

although not always possible, to obtain 3, 4 or more results for each value.<br />

For example, some students are testing the rebound height of a golfball dropped from 1.00 m<br />

onto a concrete floor. In order to obtain reliable data, they repeat the experiment 7 times.<br />

Their results were:<br />

Rebound height (cm) 81 88 84 49 85 84 87<br />

It is clear that something went wrong with the 4 th result! This outlier can be disregarded.<br />

81+ 88 + 84 + 85 + 84 + 87<br />

The average rebound height is : = 84.8 cm<br />

6<br />

The data had 2 significant figures, so this answer must be rounded off to 85 cm.<br />

Note that if you had stopped after taking only one result, it would have given 81 cm.<br />

To find the absolute error for the average value:<br />

( highest value ! lowest value)<br />

absolute error =<br />

2<br />

In this example, the absolute error is:<br />

88 " 81<br />

= ±3.5 cm<br />

2<br />

This must be rounded off to 1 significant figure, i.e.±4, so the average rebound height <strong>and</strong><br />

its absolute error is:<br />

85±4 cm.<br />

Remember, absolute errors should be:<br />

• recorded to 1 significant figure<br />

• have the same level of precision as the data value<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Repeat Samples worksheet<br />

A group of students took the following measurements of the length, width <strong>and</strong> depth of a<br />

swimming pool.<br />

Depth (m) Width (m) Length (m)<br />

3.01 8.75 50.03<br />

3.04 8.70 50.10<br />

2.98 8.63 50.07<br />

2.97 8.68 50.01<br />

3.00 8.71 49.98<br />

3.02 8.72 49.97<br />

3.03 8.67 50.00<br />

(a) Calculate the average depth, width <strong>and</strong> length of the pool. Include absolute errors with<br />

your answers.<br />

(b) Use your answers to determine these quantities. Include both absolute <strong>and</strong> percentage<br />

errors with your answers.<br />

(i) The top surface area of the pool.<br />

(ii) The volume of the pool.<br />

(iii) The perimeter of the pool bottom.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

HOMEWORK EXERCISE: MARBLES!<br />

Name:<br />

In an experiment, Lyn had to measure the time taken for a marble to drop through a tube<br />

filled with water. She made two marks on the tube; one near the top <strong>and</strong> one near the bottom.<br />

She started the stopwatch just as the marble passed the top mark <strong>and</strong> stopped timing as the<br />

marble passed the bottom mark.<br />

She repeated the experiment 5 times.<br />

Trial number time(s)<br />

1 3.2<br />

2 2.7<br />

3 2.9<br />

4 3.5<br />

5 3.3<br />

water<br />

Lyn then filled the tube with cooking oil <strong>and</strong> repeated the experiment. Her results were:<br />

Trial number time(s)<br />

1 6.7<br />

2 6.5<br />

3 6.7<br />

4 6.7<br />

5 6.8<br />

oil<br />

1. In which experiment does the data seem to be more accurate? Discuss.<br />

2. For each of the experiments above, calculate the average time that the marble took to<br />

travel between the marks. Include the absolute error in your answer.<br />

3. If the distance between the marks was 1.05±0.01 m, determine the average speed of the<br />

marble as it fell through each liquid. Include absolute errors <strong>and</strong> units in your answers.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

DATA ANALYSIS<br />

Experimental Design<br />

The SCIENTIFIC METHOD is an objective, unbiased <strong>and</strong> powerful way of investigating<br />

phenomena. This scientific approach has only been developed over the past few centuries <strong>and</strong><br />

it has led to the explosion in knowledge <strong>and</strong> technological advances during that time.<br />

First, observed facts or data are sorted into some logical order. Then a hypothesis or<br />

explanation is put forward. This hypothesis is used to make predictions that can be tested to<br />

either support or disprove the hypothesis. From the results of these tests, conclusions can be<br />

drawn. If enough data has been collected, it may be possible to propose a law that predicts<br />

future outcomes. A theory (explanation of why the law works) could then be proposed <strong>and</strong><br />

subjected to further testing.<br />

When designing an experiment to investigate the relationship between two variables, it is<br />

important that you control the variables in the experiment to ensure that the experiment is<br />

fair.<br />

• The variable that you are controlling <strong>and</strong> making changes to is called the<br />

INDEPENDENT VARIABLE.<br />

• The variable that responds to the changes in the independent variable is called the<br />

DEPENDENT VARIABLE.<br />

• The factors that remained the same throughout the experiment are called CONTROLLED<br />

VARIABLES.<br />

EXAMPLES: For each of these experiments, identify the independent, dependent <strong>and</strong> what<br />

could act as controlled variables.<br />

Experiment 1: Ten seeds were planted in each of 5 pots (A-E) containing Budget Potting<br />

Mix. The pots were given the following amounts of water each day for 40 days: A: 50 mL, B:<br />

100 mL, C: 150 mL, D: 200 mL, E: 250 mL.<br />

Experiment 2: Jenny wanted to see if the colour of food influenced whether kindergarten<br />

children would choose it for lunch. She put food colouring into 4 identical bowls of mashed<br />

potato <strong>and</strong> counted how many children chose each colour. The colours were red, green,<br />

yellow <strong>and</strong> blue.<br />

Experiment 3: James wished to investigate the relationship between the angle of a Hot<br />

Wheels track <strong>and</strong> the time that a car takes to travel down the track. He used 1.50 m of track,<br />

placed it at an angle of 10° to the horizontal <strong>and</strong> timed how long the toy car took to travel<br />

down it. He repeated this with angles of 20°, 30°, 40° <strong>and</strong> 50°.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

How to write up a Formal Practical Report!<br />

The main reason that scientists report on the results of their experiments is so that others can<br />

read <strong>and</strong> underst<strong>and</strong> what was done <strong>and</strong> what the results may tell us. Obviously, for this<br />

purpose to be achieved, a lot of care needs to taken when writing up experiments <strong>and</strong><br />

communicating your findings. When writing up a practical report, your expression should be<br />

clear, concise <strong>and</strong> unambiguous.<br />

Each formal experiment report that you write should contain the following headings:-<br />

AIM: Every experiment must have an aim (or aims) otherwise there is no point doing it!<br />

The aim could be to investigate the nature of the relationship between two (or more)<br />

variables. This investigation could be qualitative (describe the general nature of the<br />

relationship) or quantitative (define a precise mathematical relationship).<br />

You should discuss the variables involved. Identify:-<br />

the independent variable (the one you were manipulating),<br />

the dependent variable (the one that changes when the independent variable is changed) <strong>and</strong><br />

controlled variables (things that you have kept unchanged).<br />

APPARATUS: list the laboratory equipment that was used. It is not necessary to include<br />

items such as pens <strong>and</strong> calculators.<br />

METHOD: This is a description of how you <strong>and</strong> your partner performed the experiment.<br />

This should be written in past tense <strong>and</strong> in the third person (i.e. no names!).<br />

✘ We recorded the temperature every 10 seconds.<br />

✓ The temperature was recorded every 10 seconds.<br />

Explain clearly what you did. Include descriptions of any modifications that you had to make<br />

or any problems that you encountered. Describe steps that you undertook to ensure that the<br />

data that you collected was accurate.<br />

It is important to include a scientific diagram of how the apparatus was set up.<br />

RESULTS: These are usually placed in tables <strong>and</strong> graphs.<br />

Tables should include the names <strong>and</strong> abbreviated units of the quantities that you measured.<br />

Record an appropriate number of significant figures in your table.<br />

Table 1: time for car to travel down ramp at different angles<br />

Length of ramp = 2.35±0.05 m<br />

Angle (±0.5º) Time (±0.1 s)<br />

5.3 6.4<br />

6.4 5.2<br />

Underneath the table, explain how you decided on the uncertainty values that you used.<br />

Include sample calculations with your explanations.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Graphs should include the same information as the tables, but marked on the axes:<br />

Time(s)<br />

Graph 1: Time vs Angle for car travelling down ramp<br />

×<br />

×<br />

×<br />

×<br />

Angle (º)<br />

Graphs can be done on computer or by h<strong>and</strong>. If on computer, show the grid lines. If by h<strong>and</strong>,<br />

use pencil <strong>and</strong> do on graph paper.<br />

Give your graph a detailed heading. Make sure that the scale is marked along each axis.<br />

Mark in the main numerical values (not the data points) <strong>and</strong> make sure that each scale is<br />

even! Most graphs will start from the origin.<br />

Mark points as small crosses <strong>and</strong> show the line of best fit. If this is straight, use a ruler. If it is<br />

a curved, carefully sketch one smooth curved definite line that travels as close to as many<br />

points as possible. Don’t play join the dots!<br />

ANALYSIS: This usually consists of a series of directed questions relating to the data. This<br />

is the most important part of the report. Make sure that you explain your findings clearly<br />

giving full responses.<br />

In the analysis sections of Student Designed Investigations, you should begin by having a<br />

general discussion of the data. Refer to your tables <strong>and</strong> graphs. Then try to identify any<br />

patterns or trends that seem evident. Ensure that your discussion is detailed.<br />

Can you find the relationship between the variables? You can use graphical analysis to<br />

establish a quantitative relationship. Make sure that you fully explain the process that you<br />

have undertaken, showing gradient calculations, etc.<br />

What do current theories say about the relationship between your variables? Discuss how<br />

your findings compare with theory. You will be assessed on the depth of your analysis. A full<br />

<strong>and</strong> detailed analysis will be rewarded; a brief <strong>and</strong> superficial analysis will not.<br />

CONCLUSION: This is a response to the Aim. Briefly state your main findings from doing<br />

the experiment. If you have found a relationship, state what it is.<br />

DISCUSSION OF UNCERTAINTIES: In any experiment involving measurements,<br />

uncertainties will arise. In point form, you should discuss where these uncertainties occurred.<br />

Don’t explain how you arrived at the actual values again. For example:<br />

During this experiment, uncertainties occurred for the following reasons:<br />

As the car was released, it may have been pushed or retarded slightly.<br />

Stopwatches were used to measure the time taken by the car. Allowing for reaction times, this<br />

led to an uncertainty in these measurements.<br />

On some occasions, the car did not travel directly along the ramp, leading to an uncertainty in<br />

the distance measurements.<br />

There was an uncertainty associated with drawing a line of best fit.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Doing Graphs <strong>and</strong> Tables on EXCEL<br />

Open EXCEL <strong>and</strong> enter your data in the spreadsheet. Put the x co-ordinate data in column 1<br />

<strong>and</strong> the y co-ordinate data in column 2. Include the units that were used in brackets. For<br />

example, if you wished to plot a speed vs time graph:<br />

time ( 0.2s) speed ( 0.4 m s -1 )<br />

0.0 0.6<br />

1.0 2.5<br />

2.0 3.8<br />

3.0 5.9<br />

4.0 7.4<br />

5.0 9.3<br />

NB: EXCEL cannot do ± signs, so you will need to enter the ±’s by h<strong>and</strong> after printing out<br />

the table.<br />

Producing a Graph<br />

Highlight the table, including the headings, <strong>and</strong> then click on the “chart wizard” icon.<br />

STEP 1: Select x-y scatter (without plotted lines).<br />

STEP 2:<br />

<strong>Data</strong> range: series in: columns.<br />

STEP 3: Titles –<br />

Chart title: Graph 1: speed vs time for parachute (You can<br />

also type your name here)<br />

Value X axis: time(s)<br />

Value Y axis: speed (m/s)<br />

Gridlines – show MAJOR gridlines<br />

Legend – untick ‘show legend’<br />

<strong>Data</strong> labels: none<br />

STEP 4:<br />

Chart location – as new sheet → FINISH<br />

Plotting a line of best fit<br />

In physics, we would like you to rule or sketch your own line of best fit so that your<br />

graphing skills improve!<br />

For your own purposes, you may wish to use EXCEL to do this:<br />

In the toolbar, click on CHART – ADD TRENDLINE.<br />

TYPE: select the line that best matches the data. For straight lines, choose LINEAR.<br />

OPTIONS: If you want the line to pass through the origin; set intercept = 0<br />

NB: don’t display the equation on the chart.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Plotting Error Bars<br />

Click on one of the points on your graph. This should highlight all of the points.<br />

Click FORMAT – SELECTED DATA SERIES<br />

To set the error bars, choose the X ERROR BARS <strong>and</strong> Y ERROR BARS folders. In each<br />

folder, you should:<br />

Display: BOTH<br />

Error amount: FIXED VALUE – insert your absolute error for each variable.<br />

NB: you cannot enter different uncertainty values for one particular variable. These would<br />

need to be done manually if required.<br />

The graph below has uncertainties of ±0.2s for the time values <strong>and</strong> ±0.4m/s for the speed<br />

values.<br />

Graph 1: speed vs time for car rolling down ramp A Einstein 11RCH<br />

12<br />

10<br />

8<br />

Speed (m/s)<br />

6<br />

4<br />

2<br />

0<br />

-1 0 1 2 3 4 5 6<br />

Time (s)<br />

Your chart is now ready to PRINT!<br />

Use this data to do your own table <strong>and</strong> graph. H<strong>and</strong> this in for HOMEWORK!!<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Graphical <strong>Analysis</strong> of <strong>Data</strong><br />

In many experiments, the goal is to determine a relationship between two variables. This can<br />

be done by plotting a graph with the independent variable on the horizontal-axis <strong>and</strong> the<br />

dependent variable on the vertical-axis.<br />

The shape of the graph can then be used to establish the nature of the relationship!<br />

Linear graphs<br />

When you get a linear or straight-line graph, you can easily determine the relationship<br />

between the variables. Let us consider a simple straight line graph:<br />

v (m/s)<br />

v (m/s)<br />

gradient , m =<br />

t (s)<br />

rise<br />

run<br />

This graph shows a linear relationship between v <strong>and</strong><br />

t. The mathematical relationship is: v ∝ t.<br />

The mathematical equation is: v = mt + c<br />

gradient , m =<br />

rise<br />

run<br />

This graph shows a direct relationship between v<br />

<strong>and</strong> t. The mathematical relationship is: v ∝ t.<br />

The mathematical equation is: v = mt<br />

t (s)<br />

The unit associated with the gradient can be determined by finding the ratio of the rise/run<br />

units. In the examples above, the units of the gradient quantity are:<br />

riseunit<br />

rununit<br />

m s<br />

= = m s or m s<br />

s<br />

2 !2<br />

Examples:<br />

1. If the vertical axis is force(N) <strong>and</strong> the horizontal axis is distance(m), what will the units of<br />

the gradient be?<br />

2. If the horizontal axis is time (s) <strong>and</strong> the vertical axis is distance(m), what will the units of<br />

the gradient be?<br />

3. If the vertical axis is degrees (°) <strong>and</strong> the horizontal axis is degrees (°), what will the units<br />

of the gradient be?<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Non-linear Graphs<br />

If your graph does not show a direct or linear relationship, it will probably look like one of<br />

the lines shown below:<br />

A B C<br />

D E F<br />

These are lines obtained for common relationships other than direct or linear relationships.<br />

All of the above may be expressed mathematically as: y ∝ x n<br />

<strong>and</strong> hence by a simple equation:<br />

y = kx n<br />

where y is the dependent variable, x is the independent variable, <strong>and</strong> k <strong>and</strong> n are both<br />

constants.<br />

n is usually one of –2, -1, -½, 0, ½, 1, 2 or 3. The coefficient k has a unit, but n is<br />

dimensionless!<br />

Exercise<br />

1. For each graph shown above, write down:<br />

the type of relationship that it shows (in words).<br />

the mathematical relationship that exists between x <strong>and</strong> y.<br />

the mathematical equation between x <strong>and</strong> y.<br />

2. What is the value of n for: A? B? C? D? E? F?<br />

3. What is the value of n for a linear relationship?<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Finding the quantitative relationship!<br />

If the graph that you plot looks like one of those just discussed, you can determine the correct<br />

nature of the relationship by plotting additional graphs.<br />

• First, plot the original data.<br />

• Second, decide what the relationship could be i.e. it may look like a square relationship.<br />

• Third, plot a graph of your guess i.e. a vs b 2 . (You will need to calculate b 2 values to do<br />

this.)<br />

• Then, if this graph is a straight line, you can work out the equation.<br />

F<br />

Plot data <strong>and</strong> identify relationship.<br />

parabola ⇒ square relationship F ∝ t 2<br />

t<br />

F<br />

If this graph is linear, you can calculate the<br />

gradient <strong>and</strong> work out the equation.<br />

i.e. F = gradient × t 2<br />

t 2<br />

If your first guess was incorrect, i.e. you guessed y ∝ x 3 , your graph of y vs x 3 will not give<br />

a straight line <strong>and</strong> you will need to have another go!<br />

NB: a relationship <strong>and</strong> hence an equation can only be determined if a straight line graph<br />

has been obtained.<br />

It is important that you follow the graphical analysis process <strong>and</strong> are not influenced by<br />

your knowledge of what the relationship might be. For example, if you are investigating<br />

the relationship between light intensity I <strong>and</strong> distance d, you could find that I ∝ 1/d 2 from<br />

a text book. As a scientist, however, you must not let this affect the way that you analyse<br />

the data. You must act as though you do not know the outcome <strong>and</strong> first plot a graph of I<br />

vs d. This should be hyperbolic, so you would next plot I vs 1/d. If this is linear, you<br />

would have to conclude that your relationship was inverse in nature <strong>and</strong> be prepared to<br />

discuss why your results differed from the known value. You might find that this graph is<br />

parabolic <strong>and</strong> so would plot I vs 1/d 2 . If this graph was linear, you could conclude that<br />

there was an inverse square relationship between I <strong>and</strong> d <strong>and</strong> you would be able to say<br />

that your findings agreed with the theoretical relationship.<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Graphical <strong>Analysis</strong> Exercises<br />

1. Beneath each graph, indicate the most likely relationship that exists <strong>and</strong> state the<br />

equation expressing this relationship.<br />

P B L<br />

(a) (b) (c)<br />

Q A M<br />

2. What graph would you plot to check your answer to 1(a)?<br />

3. What graph would you plot to check your answer to 1(b)?<br />

4. What graph would you plot to check your answer to 1(c)?<br />

5. Using graphical analysis, work out the equation that defines the relationship between the<br />

pairs of variables below. Also indicate the value of k <strong>and</strong> give its unit.<br />

(a) (b) (c)<br />

mass<br />

(kg)<br />

acceleration<br />

(m s -2 )<br />

velocity<br />

(m s -1 )<br />

kinetic energy<br />

(J)<br />

diameter<br />

(cm)<br />

resistance,<br />

(Ω)<br />

1.00 98 0.00 0.00 0.60×10 -2 51.3<br />

2.00 52 1.00 2.05 1.0×10 -2 16.0<br />

4.00 24.1 2.00 7.90 1.3×10 -2 10.2<br />

5.00 20.4 3.00 17.6 1.7×10 -2 5.9<br />

10.0 9.7 4.00 32.5 3.5×10 -2 1.42<br />

In each case, the first variable is the independent variable. This must be plotted on the<br />

horizontal axis.<br />

Show your graphs <strong>and</strong> calculations on the graph paper following!<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

mass,<br />

(kg)<br />

acceleration,<br />

(m s -2 )<br />

1.00 98<br />

2.00 52<br />

4.00 24.1<br />

5.00 20.4<br />

10.0 9.7<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Answers to Worksheets <strong>and</strong> Exercises<br />

velocity<br />

(m s -1 )<br />

kinetic<br />

energy (J)<br />

0.00 0.00<br />

1.00 2.05<br />

2.00 7.90<br />

3.00 17.6<br />

4.00 32.5<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

diameter, resistance (Ω)<br />

(cm)<br />

0.60×10 -2 51.3<br />

1.0×10 -2 16.0<br />

1.3×10 -2 10.2<br />

1.7×10 -2 5.9<br />

3.5×10 -2 1.42<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

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Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Answers to Exercises<br />

Prefixes<br />

(a) 6,000,000 W<br />

(b) 6,000,000 W<br />

(c) 0.5 s<br />

(d) 15,000,000 m<br />

(e) 0.000000003 m<br />

(f) 25,000,000,000 Hz<br />

(g) 0.000005 m<br />

(h) 0.00025 s<br />

Conversion of <strong>Units</strong><br />

(a) 100 mm 2<br />

(b) 1.0×10 6 m 2<br />

(c) 1.0×10 -6 m 2<br />

(d) 1.0×10 6 mm 2<br />

(e) 1.0×10 12 µm 2<br />

(f) 1.0×10 3 mm 3<br />

(g) 1.0×10 6 cm 3<br />

(h) 1.0×10 -18 m 3<br />

(i) 1.0×10 -9 km 3<br />

(j) 1.0×10 -9 m 3<br />

Worksheet: <strong>Units</strong> <strong>and</strong> Conversions<br />

1(a) 25 m<br />

(b) 3.3×10 -8 m<br />

(c) 360 m<br />

2(a) 0.15 m 2<br />

(b) 6.0×10 -8 m 2<br />

(c) 4.2×10 5 m 2<br />

3(a) 35 cm 3<br />

(b) 3.0×10 6 cm 3<br />

(c) 5.6×10 -5 cm 3<br />

4(a) 0.37 A<br />

(b) 0.09 A<br />

(c) 3.0×10 -8 A<br />

5(a) 4.4×10 4 g<br />

(b) 64 g<br />

(c) 70 kg<br />

6. kg m s -1<br />

N m<br />

m s -1<br />

m s -2<br />

N s<br />

A s<br />

J C -1<br />

V A -1<br />

Significant Figures<br />

1(a) micrometer<br />

(b) 30 cm ruler<br />

(c) metre ruler<br />

2(b) 2, 6.3×10 -6 A<br />

(c) 2,<br />

(d) 3,<br />

(e) 3,<br />

(f) 3,<br />

(g) 2 or 3,<br />

3(a) 4<br />

(b) 2<br />

(c) 4<br />

(d) 3<br />

(e) 2<br />

(f) 3<br />

4. 335.31 m<br />

5. 6883 m 2<br />

7. 6.2 m s -1<br />

2.7×10 4 J<br />

3.53×10 5 m<br />

6.07×10 -6 m<br />

2.50×10 -7 A<br />

150 kg<br />

Uncertainties in <strong>Measurement</strong>s<br />

1. 5.4 mm 3<br />

0.5 N<br />

360 K<br />

30°C<br />

55 cm<br />

740 g<br />

0.3 N<br />

2 (a) ±0.1 g (b) ±1°C (c) ±0.01 mA (d) ±0.001 mm<br />

Uncertainty Exercises<br />

1(a) 57±1 cm<br />

(b) 112±1 m s -1<br />

(c) 1.6±0.1 mg<br />

(d) 64±2 m<br />

(e) 0.085±0.003 kV<br />

(f) 10.4±0.1 mm<br />

(g) 15±3 mA<br />

(h) 0.3±0.2 kg<br />

(i) 27.0±0.1 kg<br />

(j) 45±2 m<br />

2(a) 1.8%<br />

(b) 0.9%<br />

(c) 6.3%<br />

(d) 3.1%<br />

(e) 3.5%<br />

(f) 1%<br />

(g) 20%<br />

(h) 67%<br />

(i) 0.4%<br />

(j) 4.4%<br />

3(a) 2.6±0.1<br />

(b) 0.5±0.1<br />

(c) 1.90±0.01<br />

(d) 30±1<br />

(e) 0.017±0.001A<br />

(f) 110±5V<br />

(g) 2.7±0.1V<br />

(h) 25±5mA<br />

(i) 3.9±0.1V<br />

33


Penleigh <strong>and</strong> Essendon Grammar School<br />

<strong>Data</strong> <strong>Analysis</strong> Booklet<br />

Error <strong>Analysis</strong> Exercises<br />

1(a) 61.7±0.6 m; 61.7 m ±1.0%<br />

(b) 63.0±0.8 m; 63.0 m ±1.3%<br />

(c) 94.5 m 2 ±1.7%; 95±2 m 2<br />

(d) 110 m 2 ±3.5%; 110±4 m 2<br />

(e) 24.0±0.3 m; 24.0 m ±1.3%<br />

(f) 390 m 3 ±4.1%; 390±20 m 3<br />

Repeat samples worksheet<br />

(a) D = 3.01±0.04 m<br />

W = 8.69±0.06 m<br />

L = 50.02±0.07 m<br />

(b) (i) 435 m 2 ±0.8%; 435±3 m 2<br />

(ii) 1310 m 3 ± 2.1%; 1310±30 m 3<br />

(iii) 117.4 ± 0.3 m; 117.4 m ± 0.3%<br />

Graphical <strong>Analysis</strong> Exercises<br />

1(a) square; P = kQ 2<br />

(b) inverse; B = k/A<br />

(c) square root; L = k√A<br />

2. P vs Q 2<br />

3. B vs 1/A<br />

4. L vs √M<br />

5(a) k = 100 kg m s -2 ; a = 100/m<br />

(b) k = 2.0 J m -2 s 2 ; E K = 2.0 v 2<br />

(c) k = 0.0018 Ω cm 2 ; R = 0.0018/d 2<br />

Homework Exercise: Marbles!<br />

1 The percentage error for oil is much lower.<br />

The times for oil are more accurate because the<br />

marble would be moving more slowly making it<br />

easier to time precisely.<br />

2 water: 3.1±0.4 s; oil; 6.7±0.2 s<br />

3 water: 0.34±0.05 m s -1 ; oil: 0.16±0.01 m s -1<br />

Non-linear Graphs Exercise<br />

1(a) independent; y is independent of x; no<br />

equation<br />

(b) square; y ∝ x 2 ; y = kx 2<br />

(c) cubic; y ∝ x 3 ; y = kx 3<br />

(d) square root; y ∝ √x; y = k√x<br />

(e) inverse; y ∝ 1/x; y = k/x<br />

(f) inverse square; y ∝ 1/x 2 ; y = k/x 2<br />

2(a) 0<br />

(b) 2<br />

(c) 3<br />

(d) 0.5<br />

(e) –1<br />

(f) –2<br />

3. one<br />

34

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