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Maths Paper & Solutions - Career Point

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

QUESTIONS & SOLUTIONS<br />

CAREER POINT<br />

Q.1 If the roots of a quadratic equation are m + n and m – n, then the quadratic equation will be<br />

(A) x 2 + 2mx + m 2 – mn + n 2 = 0 (B) x 2 + 2mx + (m – n) 2 = 0<br />

(C) x 2 – 2mx + m 2 – n 2 = 0 (D) x 2 + 2mx + m 2 – n 2 = 0<br />

Solution [C]<br />

Quadratic equation whose roots are m + n, m – n is<br />

x 2 –((m + n) + (m – n))x + (m + n) + (m – n) = 0<br />

x 2 – 2mx + m 2 – n 2 = 0<br />

Q.2 If α, β are the roots of x 2 + px – q = 0 and γ, δ are roots of x 2 – px + r = 0 then what is (β + γ) (β + δ) equal<br />

to?<br />

(A) p + r (B) p + q (C) q + r (D) p – q<br />

Solution [C]<br />

x 2 + px – q = 0<br />

α + β = – p ...(1)<br />

αβ = –q ...(2)<br />

x 2 – px + r = 0<br />

γ + δ = p ...(3)<br />

γδ = r ...(4)<br />

Now<br />

(β + γ) (β + δ)<br />

= β 2 + (γ + δ)β + γδ<br />

= β 2 + pβ + r using (3) & (4)<br />

= q + r Q (β is root of x 2 + px – q = 0<br />

⇒ β 2 + pβ – q = 0<br />

⇒ β 2 + pβ = q)<br />

Q.3 Consider the following statements :<br />

1. The sum of cubes of first 20 natural numbers is 44400.<br />

2. The sum of squares of first 20 natural numbers is 2870.<br />

Which of the above statements is/are correct ?<br />

(A) 1 only (B) 2 only (C) Both 1 and 2 (D) Neither 1 nor 2<br />

Solution [B]<br />

Q 1 3 + 2 3 + 3 3 + ..... + n 3 ⎛ n(n + 1) ⎞<br />

= ⎜ ⎟<br />

⎝ 2 ⎠<br />

∴ 1 2 + 2 3 + 3 3 + .... + 20 3 ⎛ 20.21⎞<br />

= ⎜ ⎟<br />

⎝ 2 ⎠<br />

= (10 × 21) 2<br />

= 44100<br />

1 2 + 2 2 + 3 2 + ........ + n 2 = 6<br />

1 n(n + 1)(2n + 1)<br />

2<br />

2<br />

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1 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

∴ 1 2 + 2 2 + ........ + 20 2 = 6<br />

1 20.21.41 = 2870<br />

∴ (B) is correct<br />

Q.4 Consider the following statements :<br />

1. (ω 10 + 1) 7 + ω = 0<br />

2. (ω 105 + 1) 10 = p 10 for some prime number p<br />

where ω ≠ 1 is a cubic root of unity. Which of the above statements is/are correct ?<br />

(A) 1 only (B) 2 only (C) Both 1 and 2 (D) Neither 1 nor 2<br />

Solution [B]<br />

Q ω is cube root of unity<br />

∴ ω 3 = 1<br />

and 1 + ω + ω 2 = 0<br />

Now<br />

(ω 10 + 1) 7 + ω<br />

= ((ω 3 ) 3 ω + 1) 7 + ω<br />

= (ω + 1) 7 + ω Q ω 3 = 1<br />

= –ω 14 + ω Q 1 + ω + ω 2 = 0<br />

= –(ω 3 ) 4 ω 2 + ω<br />

= –ω 2 + ω ∴ ω 3 = 1<br />

≠ 0<br />

and<br />

(ω 105 + 1) 10<br />

= ((ω 3 ) 35 + 1) 10<br />

= (1 + 1) 10 Q ω 3 = 1<br />

= 2 10<br />

∴ (ω 105 + 1) 10 = 2 10 and 2 is prime<br />

∴ (B) is correct<br />

1 1 1<br />

Q.5 What is the sum of first eight terms of the series 1 − + − + ... ?<br />

2 4 8<br />

89<br />

(A) 128<br />

57<br />

(B) 384<br />

85<br />

(C) 128<br />

(D) none of the above<br />

Solution [C]<br />

1 1 1<br />

1 − + − + ......<br />

2 4 8<br />

Sum of first 'n' terms of G.P.<br />

⎛<br />

8<br />

⎟ ⎟ ⎞<br />

⎜ ⎛ 1 ⎞<br />

1 − ⎜ − ⎟ 1<br />

⎜<br />

S n =<br />

⎝ ⎝ 2 ⎠ 1−<br />

1.<br />

⎠<br />

= 256<br />

⎛ 1 ⎞ 1<br />

1 − ⎜ − ⎟ 1+<br />

⎝ 2 ⎠ 2<br />

=<br />

255<br />

256<br />

3<br />

2<br />

85<br />

= 128<br />

CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.) Ph.: 0744-3040000<br />

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2 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.6 The number of permutations that can be formed from all the letters of the word 'BASEBALL' is :<br />

(A) 540 (B) 1260 (C) 3780 (D) 5040<br />

Solution [D]<br />

BASEBALL<br />

AA, BB, E, LL, S<br />

No. of permutation using all letters<br />

=<br />

8!<br />

2!2!2!<br />

= 5040<br />

Q.7 The relation 'has the same father as' over the set of children is :<br />

(A) only reflexive<br />

(B) only symmetric<br />

(C) only transitive<br />

(D) an equivalence relation<br />

Solution [D]<br />

Reflexive<br />

aRb = given<br />

⇒ a has same father as b<br />

aRa = a is same father as a is true<br />

∴ it is reflexive<br />

Transitive<br />

aRb is true<br />

bRc true<br />

∴ aRc is also true because if a has same father as b & b has same father as c then a will have same father as c<br />

Symmetric<br />

aRc is given<br />

bRa is true<br />

Q If a has same father as a then be has same father as b<br />

Q.8 If the roots of the quadratic equation 3x 2 – 5x + p = 0 are real and unequal, then which one of the following is<br />

correct ?<br />

Solution [B]<br />

25<br />

(A) p = 12<br />

Q 3x 2 – 5x + p = 0<br />

has real and distinct roots<br />

∴ D > 0<br />

(–5) 2 – 4(3) × p > 0<br />

25<br />

25 – 12p > 0 ⇒ p < 12<br />

25<br />

(B) p < 12<br />

25<br />

(C) p > 12<br />

25<br />

(D) p ≤ 12<br />

Q.9 The decimal representation of the number (1011) 2 in binary system is :<br />

(A) 5 (B) 7 (C) 9 (D) 11<br />

Solution [D]<br />

(1011) 2 = 1 × 2 3 + 0 × 2 2 + 1 + 2 1 + 1 × 2 0<br />

= 8 + 0 + 2 + 1<br />

= (11) 10 = 11<br />

CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.) Ph.: 0744-3040000<br />

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3 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.10 The decimal number (57.375) 10 when converted to binary number takes the form :<br />

(A) (111001.011) 2 (B) (100111.110) 2 (C) (110011.101) 2 (D) (111011.011) 2<br />

Solution [A]<br />

(57.375) 10 = (111001.011) 2<br />

(57) 10 = (111001) 2<br />

(375) 10 = (.011) 2<br />

Q.11 If (log 3 x) (log x 2x) (log 2x y) = log x x 2 , then what is y equal to ?<br />

(A) 4.5 (B) 9 (C) 18 (D) 27<br />

Solution [B]<br />

log x log 2x<br />

. .<br />

log3 log x<br />

∴ log 3 y = 2<br />

⇒ y = 9<br />

log y<br />

log 2x<br />

= 2<br />

Q.12 Let P = {1, 2, 3) and a relation on set P is given by the set R = {(1, 2), (1, 3), (2, 1), (1, 1), (2, 2), (3, 3), (2, 3)}.<br />

Then R is :<br />

(A) Reflexive, transitive but not symmetric (B) Symmetric, transitive but not reflexive<br />

(C) Symmetric, reflexive but not transitive (D) None of the above<br />

Solution [A]<br />

(1, 3) not (3, 1)<br />

so not symmetric<br />

(1, 2) (2, 3) (1, 3)<br />

(2, 1) (1, 3) (7, 3)<br />

Transitive<br />

13<br />

n n+<br />

1)<br />

Q.13 The value of the sum ∑( i + i where i = − 1 is :<br />

n=<br />

1<br />

(A) i (B) – i (C) 0 (D) i – 1<br />

Solution [D]<br />

13<br />

∑<br />

n=<br />

1<br />

( i<br />

n<br />

+ i<br />

n+<br />

1)<br />

= (i + i 2 ) + (i 2 + i 3 ) ...... (i 13 + i 14 )<br />

= i + 2{i 2 + i 3 + .... + i 13 } + i 14<br />

= i + i 14 = i – 1 Q (i 2 + i 3 .... i 13 = 0)<br />

FOR THE NEXT TWO (02) QUESTION THAT FOLLOW :<br />

The sum of first 10 terms and 20 terms of an AP are 120 and 440 respectively ?<br />

Q.14 What is its first term ?<br />

(A) 2 (B) 3 (C) 4 (D) 5<br />

Q.15 What is the common difference ?<br />

(A) 1 (B) 2 (C) 3 (D) 4<br />

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4 / 33


MATHEMATICS<br />

Solution [14(B) & 15(C)]<br />

S 10 = 120, S 20 = 440<br />

10 (2a + 9d) = 120<br />

2<br />

2a + 9d = 24 ...(1)<br />

20 (2a + 19d) = 440<br />

2<br />

2a + 19d = 44 ...(2)<br />

Solving (1) and (2) we get<br />

a = 3, d = 2<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.16 If a non-empty set A contains n elements, then its power set contains how many elements ?<br />

(A) n 2 (B) 2 n (C) 2n (D) n + 1<br />

Solution [B]<br />

Power set is set of all subsets<br />

∴ no of subsets will be 2 n<br />

Q.17 Let A = {x ∈ W, the set of whole numbers and x < 3}, B = {x ∈ N, the set of natural numbers and 2 ≤ x < 4}<br />

and C = {3, 4}, then how many elements will (A ∪ B) x C contains ?<br />

(A) 6 (B) 8 (C) 10 (D) 12<br />

Solution [B]<br />

A = {0, 1, 2}, B = {2, 3}, C = {3, 4}<br />

∴ A ∪ B = {0, 1, 2, 3}<br />

∴ no of elements in (A ∪ B)x C will be 8<br />

Q.18 What is the modulus of<br />

2 + i where i = − 1 ?<br />

2 − i<br />

(A) 3 (B) 1/2 (C) 1 (D) None of the above<br />

Solution [C]<br />

2 + i<br />

2 − i<br />

=<br />

3 = 1<br />

3<br />

Q.19 What is the number of diagonals which can be drawn by joining the angular points of a polygon of 100 sides?<br />

(A) 4850 (B) 4950 (C) 5000 (D) 10000<br />

Solution [A]<br />

C 2 – n<br />

100 C 2 – 100<br />

100 × 99<br />

= – 100<br />

2<br />

= 4950 – 100<br />

= 4850<br />

CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.) Ph.: 0744-3040000<br />

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5 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.20 The angles of a triangle are in AP and the least angle is 30º. What is the greatest angle (in radian) ?<br />

π<br />

π<br />

π<br />

(A) (B) (C) (D) π<br />

2 3 4<br />

Solution [A]<br />

2B = A + C ...(1)<br />

A + B + C = 180º ...(2)<br />

⇒ B = 60º<br />

Least angle = 30º<br />

∴ Greatest angle = 2<br />

π<br />

Q.21 If each element in a row of a determinant is multiplied by the same factor r, then the value of the<br />

determinant?<br />

(A) is multiplied by r 3<br />

(B) in increased by 3r<br />

(C) remains unchanged<br />

(D) is multiplied by r<br />

Solution [A]<br />

Q.22 The inverse of a diagonal matrix is a :<br />

(A) symmetric matrix<br />

(C) diagonal matrix<br />

Solution [C]<br />

(B) skew-symmetric matrix<br />

(D) none of the above<br />

Q.23 If A =<br />

⎡3<br />

⎢<br />

⎢<br />

5<br />

⎢⎣<br />

7<br />

4⎤<br />

⎥ ⎡3<br />

6<br />

⎥<br />

and B = ⎢<br />

8⎥<br />

⎣4<br />

⎦<br />

5<br />

6<br />

7⎤<br />

8<br />

⎥ , then which one of the following is correct ?<br />

⎦<br />

(A) B is the inverse of A (B) B is the adjoint of A (C) B is the transpose of A (D) None of the above<br />

Solution [C]<br />

Q.24<br />

⎡x⎤<br />

⎡y⎤<br />

⎡z⎤<br />

⎡10⎤<br />

If the sum of matrices<br />

⎢ ⎥<br />

⎢<br />

x<br />

⎥<br />

,<br />

⎢ ⎥<br />

⎢<br />

y<br />

⎥<br />

and<br />

⎢ ⎥<br />

⎢<br />

0<br />

⎥<br />

is the matrix<br />

⎢ ⎥<br />

⎢<br />

5<br />

⎥<br />

, then what is the value of y ?<br />

⎢⎣<br />

y⎥⎦<br />

⎢⎣<br />

z⎥⎦<br />

⎢⎣<br />

0⎥⎦<br />

⎢⎣<br />

5 ⎥⎦<br />

(A) –5 (B) 0 (C) 5 (D) 10<br />

Solution [B]<br />

x + y + z = 10 ...(1)<br />

x + y = 5 ...(2)<br />

y + z = 5 ...(3)<br />

⇒ z = 5<br />

⇒ y = 0<br />

Q.25 If the matrix AB is zero matrix, then which one of the following is correct ?<br />

(A) A must be equal to zero matrix or B must be equal to zero matrix<br />

(B) A must be equal to zero matrix and B must be equal to zero matrix<br />

(C) It is not necessary that either A is zero matrix or B is zero matrix<br />

(D) None of the above<br />

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6 / 33


MATHEMATICS<br />

Solution [C]<br />

AB = 0 does not implies that<br />

either A is zero or B is zero<br />

ex.<br />

⎡1<br />

⎢<br />

⎣0<br />

0⎤<br />

0<br />

⎥ ⎦<br />

⎡0<br />

⎢<br />

⎣0<br />

0⎤<br />

⎡0<br />

0⎤<br />

1<br />

⎥ = ⎢ ⎥<br />

⎦ ⎣0<br />

0 ⎦<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.26<br />

⎡ α 2 2⎤<br />

If the matrix<br />

⎢ ⎥<br />

⎢<br />

− 3 0 4<br />

⎥<br />

is not invertible, then :<br />

⎢⎣<br />

1 −1<br />

1⎥⎦<br />

(A) α = –5 (B) α = 5 (C) α = 0 (D) α = 1<br />

Solution [A]<br />

⎡ α 2 2⎤<br />

⎢ ⎥<br />

⎢<br />

− 3 0 4<br />

⎥<br />

= 0<br />

⎢⎣<br />

1 −1<br />

1⎥⎦<br />

α(4) – 2(–3 – 4) + 2(3) = 0<br />

4α + 14 + 6 = 0<br />

α = –5<br />

Q.27 The value of the determinant<br />

x<br />

y<br />

z<br />

2<br />

2<br />

2<br />

1<br />

1<br />

1<br />

y<br />

z<br />

x<br />

2<br />

2<br />

2<br />

+ z<br />

+ x<br />

2<br />

+ y<br />

2<br />

2<br />

is :<br />

(A) 0 (B) x 2 + y 2 + z 2 (C) x 2 + y 2 + z 2 + 1 (D) None of the above<br />

Solution [A]<br />

x<br />

y<br />

z<br />

2<br />

2<br />

2<br />

1<br />

1<br />

1<br />

y<br />

z<br />

x<br />

2<br />

2<br />

2<br />

+ z<br />

+ x<br />

2<br />

+ y<br />

C 3 → C 3 + C 1<br />

x<br />

y<br />

z<br />

2<br />

2<br />

2<br />

1<br />

1<br />

1<br />

x<br />

x<br />

x<br />

2<br />

2<br />

2<br />

2<br />

+ y<br />

+ y<br />

+ y<br />

2<br />

2<br />

2<br />

2<br />

+ z<br />

+ z<br />

+ z<br />

2<br />

2<br />

2<br />

= (x 2 + y 2 + z 2 )<br />

x<br />

y<br />

z<br />

2<br />

2<br />

2<br />

1<br />

1<br />

1<br />

1<br />

1<br />

1<br />

= 0<br />

Q.28 A square matrix [a ij ] such that a ij = 0 for i ≠ j and a ij = k where k is a constant for i = j is called :<br />

(A) diagonal matrix, but not scalar matrix<br />

(B) scalar matrix<br />

(C) unit matrix<br />

(D) None of the above<br />

Solution [B]<br />

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7 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.29 What is the value of sin 15º ?<br />

(A)<br />

2<br />

3 −1<br />

2<br />

(B)<br />

Solution [A]<br />

sin 15º = sin(45º – 30º)<br />

= sin 45º . cos 30º – cos 45º . sin 30º<br />

2<br />

3 +1<br />

2<br />

(C)<br />

3 −1<br />

3 + 1<br />

(D)<br />

3 + 1<br />

3 −1<br />

=<br />

1 3 1 1<br />

. – .<br />

2 2 2 2<br />

=<br />

2<br />

3 −1<br />

2<br />

Q.30 If 4 sin 2 θ = 1, where 0 < θ < 2π, how many values does θ take ?<br />

(A) 1 (B) 2 (C) 4 (D) None of these<br />

Solution [C]<br />

4 sin 2 θ = 1<br />

sin 2 1<br />

θ = 4<br />

⇒ sin θ = ± 2<br />

1<br />

⇒ sin θ = 2<br />

1 , sin θ = – 2<br />

1<br />

π 5π 7π 11π<br />

⇒ θ = , , , 6 6 6 6<br />

{Q 0 < θ < 2π}<br />

Q.31 What is the value of sin 18º cos 36º equal to ?<br />

(A) 4 (B) 2 (C) 1 (D) 1/4<br />

Solution [C]<br />

sin 18º . cos 36º =<br />

5 −1<br />

5 + 1<br />

. =<br />

4 4<br />

5 − 1 = 1<br />

4<br />

⎡ −1⎛<br />

3 ⎞ −1⎛<br />

4 ⎞⎤<br />

Q.32 What is sin ⎢sin<br />

⎜ ⎟ + sin ⎜ ⎟⎥ equal to ?<br />

⎣ ⎝ 5 ⎠ ⎝ 5 ⎠ ⎦<br />

(A) 0 (B) 1/2 (C) 1 (D) 2<br />

Solution [C]<br />

⎡ −1⎛<br />

3 ⎞ −1⎛<br />

4 ⎞⎤<br />

sin ⎢sin<br />

⎜ ⎟ + sin ⎜ ⎟⎥ ⎣ ⎝ 5 ⎠ ⎝ 5 ⎠ ⎦<br />

⎛ − 3 ⎞<br />

= sin ⎜sin 1 ⎛ − 4 ⎞<br />

⎟ . cos ⎜sin 1 ⎛ − 3 ⎞<br />

⎟ + cos ⎜sin 1 ⎛ − 4 ⎞<br />

⎟ . sin ⎜sin 1 ⎟<br />

⎝ 5 ⎠ ⎝ 5 ⎠ ⎝ 5 ⎠ ⎝ 5 ⎠<br />

=<br />

3<br />

.<br />

5<br />

3<br />

5<br />

4 4<br />

+ . = 1<br />

5 5<br />

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8 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

13<br />

Q.33 If sec α = where 270º < α < 360º, then what is sin α equal to ?<br />

5<br />

(A) 13<br />

5<br />

12<br />

(B) 13<br />

12<br />

(C) – 13<br />

13<br />

(D) – 12<br />

Solution [C]<br />

13 5<br />

sec α = ⇒ cos α = 5<br />

13<br />

Q 270º < α < 360º<br />

12<br />

⇒ sin α = – 13<br />

Q.34 What is tan(–585º) equal to ?<br />

(A) 1 (B) –1 (C) – 2 (D) – 3<br />

Solution [B]<br />

tan(–585º)<br />

= – tan 585º<br />

= –tan(720º – 135º)<br />

= {–tan(135º)}<br />

= tan 135º<br />

= –1<br />

Q.35 Consider the following statements :<br />

1. The value of cos 46º – sin 46º is positive<br />

2. The value of cos 44º – sin 44º is negative<br />

Which of the above statements is/are correct ?<br />

(A) 1 only (B) 2 only (C) Both 1 and 2 (D) Neither 1 nor 2<br />

Solution [D]<br />

cos 46º – sin 46º is negative<br />

cos 44º – sin 44º is positive<br />

Hence (D) is correct.<br />

Q.36 The line making an angle (–120º) with x-axis is situated in the :<br />

(A) first quadrant (B) second quadrant (C) third quadrant (D) fourth quadrant<br />

Solution<br />

Data insufficient<br />

Q.37 The angle subtended at the centre of a circle of radius 3 cm by an arc of length 1 cm is :<br />

30º<br />

(A)<br />

π<br />

Solution [B]<br />

arc<br />

angle = radius<br />

1 60º<br />

= radian ⇒ 3 π<br />

(B)<br />

60º<br />

π<br />

(C) 60º<br />

(D) None of the above<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.38 If sin A =<br />

2 and cos B =<br />

1<br />

5<br />

10<br />

where A and B are acute angles, then what is A + B equal to ?<br />

(A) 135º (B) 90º (C) 75º (D) 60º<br />

Solution [A]<br />

sin A =<br />

2 1<br />

, cos B =<br />

5<br />

10<br />

∴ cos A =<br />

∴ sin (A + B) =<br />

∴ A + B = 135º<br />

1 3 , sin B =<br />

5 10<br />

2<br />

50<br />

+<br />

3<br />

50<br />

=<br />

5<br />

50<br />

=<br />

1<br />

2<br />

Q.39 The top of a hill observed from the top and bottom of a building of height h is at angles of eleveation α and β<br />

respectively. The height of the hill is :<br />

h cotβ<br />

h cot α<br />

h tan α<br />

(A)<br />

(B)<br />

(C)<br />

(D) None of the above<br />

cotβ − cot α<br />

cot α − cotβ<br />

tan α − tanβ<br />

Solution [B]<br />

A<br />

E<br />

α<br />

C<br />

x<br />

h<br />

β<br />

D<br />

d<br />

Let height is x<br />

from ∆ABD<br />

B<br />

x = tan β ...(1)<br />

d<br />

from ∆ACE<br />

x − h<br />

= tan α ...(2)<br />

d<br />

from (1) & (2)<br />

tan α<br />

x – h = d tan α = x<br />

tanβ<br />

x(tan β – tan α) = h tan β<br />

h tanβ<br />

∴ x =<br />

tanβ − tan α<br />

=<br />

h cot α<br />

cot α − cotβ<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.40 From the top of a lighthouse 70 m high with its base at sea level, the angle of depression of a boat is 15º. The<br />

distance of the boat from the foot of the lighthouse is :<br />

(A) 70(2 – 3 )m (B) 70(2 + 3 )m (C) 70(3 – 3 )m (D) 70(3 + 3 )m<br />

Solution [B]<br />

70<br />

x<br />

from triangle<br />

15º<br />

70 = tan 15º<br />

x<br />

=<br />

x =<br />

3 − 1 = 2 – 3<br />

3 + 1<br />

70<br />

2 −<br />

3<br />

= 70(2 + 3 )<br />

Q.41 The locus of a point equidistant from three collinear points is :<br />

(A) a straight line (B) a pair of points (C) a point (D) the null set<br />

Solution [D]<br />

Q.42 The equation of the locus of a point which is always equidistant from the points (1, 0) and (0, –2) is :<br />

(A) 2x + 4y + 3 = 0 (B) 4x + 2y + 3 = 0 (C) 2x + 4y – 3 = 0 (D) 4x + 2y – 3 = 0<br />

Solution [A]<br />

Let point is (h, k)<br />

∴ (h – 1) 2 + (k – 0) 2 = (h – 0) 2 + (k + 2) 2<br />

h 2 + 1 – 2h + k 2 = h 2 + k 2 + 4 + 4k<br />

2h + 4k + 3 = 0<br />

∴ Locus is 2x + 4y + 3 = 0<br />

Q.43 The points (5, 1), (1, –1) and (11, 4) are :<br />

(A) collinear<br />

(C) vertices of equilateral triangle<br />

Solution [A]<br />

∴ A(5, 1), B(1, –1), C(11, 4)<br />

m AB = m BC = m AC<br />

slope are equal<br />

(B) vertices of right angled triangle<br />

(D) vertices of an isosceles triangle<br />

Q.44 What is the perpendicular distance between the parallel lines 3x + 4y = 9 and 9x + 12 y + 28 = 0 ?<br />

(A) 7/3 units (B) 8/3 units (C) 10/3 units (D) 11/3 units<br />

Solution [D]<br />

3x + 4y – 9 = 0 ……. (1)<br />

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11 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

3x + 4y +<br />

28 = 0 ……..(2)<br />

3<br />

distance between parallel lines =<br />

55 11<br />

⇒ ⇒ units<br />

15 3<br />

28<br />

+ 9<br />

3<br />

3<br />

2<br />

+ 4<br />

2<br />

Q.45 Let p, q, r, s be the distances from origin of the points (2, 6), (3, 4), (4, 5) and (–2, 5) respectively. Which one<br />

of the following is a whole number ?<br />

(A) p (B) q (C) r (D) s<br />

Solution [B]<br />

p =<br />

q =<br />

r =<br />

s =<br />

2<br />

2<br />

2 + 6 ⇒ 40<br />

2<br />

2<br />

3 + 4 = 5<br />

2<br />

2<br />

4 + 5 41<br />

2<br />

2<br />

2 + 5 = 29<br />

Q.46 From the point (4, 3) a perpendicular is dropped on the x-axis as well as on the y-axis. If the lengths of<br />

perpendiculars are p, q respectively, then which one of the following is correct ?<br />

(A) p = q (B) 3p = 4q (C) 4p = 3q (D) p + q = 5<br />

Solution [C]<br />

p = 3, q = 4<br />

⇒ 4p = 3q<br />

Q.47 What is the value of λ if the straight line (2x + 3y + 4) + λ(6x – y + 12) = 0 is parallel to y-axis ?<br />

(A) 3 (B) – 6 (C) 4 (D) – 3<br />

Solution [A]<br />

⎛ 6λ + 2 ⎞<br />

Slope = – ⎜ ⎟<br />

⎝ 3 – λ ⎠<br />

For slope not to be defined λ = 3<br />

Q.48 The line y = 0 divides the line joining the points (3, – 5) and (–4, 7) in the ratio -<br />

(A) 3 : 4 (B) 4 : 5 (C) 5 : 7 (D) 7 : 9<br />

Solution [A]<br />

–4λ + 3<br />

= 0<br />

λ + 1<br />

λ = 4<br />

3 ⇒ 3 : 4<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.49 The sum of the focal distances of a point on the ellipse<br />

2<br />

2<br />

x y<br />

+ = 1 is -<br />

4 9<br />

(A) 4 units (B) 6 units (C) 8 units (D) 10 units<br />

Solution [B]<br />

PS + PS' = 2b = 2 × 3 = 6<br />

Q.50 The eccentricity e of an ellipse satisfies the condition -<br />

(A) e < 0 (B) 0 < e < 1 (C) e = 1 (D) e > 1<br />

Solution [B]<br />

0 < e < 1<br />

Q.51 The equation of a straight line which makes an angle 45° with the x-axis with y-intercept 101 units is -<br />

(A) 10x + 101y = 1 (B) 101x + y = 1 (C) x + y – 101 = 0 (D) x – y + 101 = 0<br />

Solution [D]<br />

y = mx + c<br />

y = x + 101<br />

Q.52 If the points (2, 4), (2, 6) and (2 + 3 , k) are the vertices of an equilateral triangle, then what is the value of k ?<br />

(A) 6 (B) 5 (C) – 3 (D) 1<br />

Solution [B]<br />

AB = BC ⇒ (k – 4) 2 + 3 = 4<br />

k – 4 = ± 1<br />

k = 5, 3<br />

AC = BC<br />

3 + (k – 6) 2 = 4<br />

(k – 6) 2 = 1<br />

(k – 6) = ± 1<br />

k = 7 , 5<br />

∴ k = 5<br />

Q.53 If the distance between the points (7, 1, – 3) and (4, 5, λ) is 13 units, then what is one of the values of λ ?<br />

(A) 20 (B) 10 (C) 9 (D) 8<br />

Solution [C]<br />

2<br />

2<br />

( 7 – 4) + (1 – 5) + ( λ + 3) = 13<br />

9 + 16 + λ 2 + 9 + 6λ = 169<br />

λ 2 + 6λ – 135 = 0<br />

λ = 9, – 15<br />

2<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.54 If a line OP of length r (where 'O' is the origin) makes an angle α with x-axis and lies in the xz-plane, then<br />

what are the coordinates of P ?<br />

(A) (r cos α, 0, r sin α) (B) (0, 0, r sin α) (C) (r cos α, 0, 0) (D) (0, 0, r cos α)<br />

Solution [A]<br />

The coordinate of P will be (r cos α, 0, r sin α)<br />

Q y coordinate will be zero<br />

Q.55 What is the distance of the point (1, 2, 0) from yz-plane is -<br />

(A) 1 units (B) 2 units (C) 3 units (D) 4 units<br />

Solution [A]<br />

Distance of (1, 2, 0) from yz-plane is 1.<br />

Q.56 What are the direction cosines of a line which is equally inclined to the positive directions of the axes ?<br />

1 1 1<br />

1 1 1<br />

1 1 1<br />

1 1 1<br />

(A) , , (B) – , , (C) – ,– , (D) , ,<br />

3 3 3<br />

3 3 3<br />

3 3 3 3 3 3<br />

Solution [A]<br />

If a line makes angle α, β, γ<br />

with axes then direction cosines cos α, cos β, cos γ such that cos 2 α + cos 2 β + cos 2 γ = 1<br />

if α = β = γ<br />

cos 2 α + cos 2 α + cos 2 α = 1<br />

3cos 2 α = 1<br />

⇒ cos α =<br />

1<br />

3<br />

Q.57 What is the angle between the lines<br />

(A) 2<br />

π<br />

(B) 3<br />

π<br />

x – 2<br />

1<br />

Solution [A]<br />

x – 2 y + 1 z + 2<br />

= =<br />

1 – 2 1<br />

Direction ratios are proportional to 1, –2, 1<br />

x –1<br />

1<br />

=<br />

3<br />

y +<br />

2<br />

3<br />

2<br />

=<br />

z + 5<br />

2<br />

Direction ratios are proportional to 1, 2<br />

3 , 2<br />

=<br />

y + 1 z + 2 =<br />

– 2 1<br />

(C) 6<br />

π<br />

and<br />

x –1<br />

1<br />

=<br />

2 y + 3<br />

3<br />

=<br />

z + 5 ?<br />

2<br />

(D) None of these<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

cos θ =<br />

a<br />

=<br />

1<br />

π<br />

⇒ θ = 2<br />

2<br />

1<br />

2<br />

a a<br />

1<br />

2<br />

2<br />

1<br />

+ b<br />

+ (–2)<br />

+ b b<br />

1<br />

2<br />

1<br />

+ c<br />

2<br />

2<br />

a<br />

2<br />

+ 1<br />

+ c c<br />

2<br />

2<br />

1<br />

+ b<br />

1<br />

2<br />

2<br />

2<br />

2<br />

+ c<br />

2<br />

2<br />

⎛ 3 ⎞<br />

(1)(1) + (–2) ⎜ ⎟ + (1)(2)<br />

⎝ 2 ⎠<br />

⎛ 2 ⎞<br />

+ ⎜ ⎟<br />

⎝ 3 ⎠<br />

2<br />

2<br />

+ 1<br />

= 0<br />

Q.58 What is the equation to the plane through (1, 2, 3) parallel to 3x + 4y – 5z = 0 ?<br />

(A) 3x + 4y + 5z + 4 = 0 (B) 3x + 4y – 5z + 14 = 0 (C) 3x + 4y – 5z + 4 = 0 (D) 3x + 4y – 5z – 4 = 0<br />

Solution [C]<br />

Let equation of plane parallel to<br />

3x + 4y – 5z = 0 is<br />

3x + 4y – 5z + λ = 0<br />

Q it passes through (1, 2, 3)<br />

∴ 3(1) + 4(2) – 5(3) + λ = 0<br />

⇒ 3 + 8 – 15 + λ = 0<br />

⇒ λ = 4<br />

∴ equation of plane is 3x + 4y – 5z + 4 = 0<br />

Q.59 What are the direction ratios of the line of intersection of the planes x = 3z + 4 and y = 2z – 3<br />

(A) 〈1, 2, 3〉 (B) 〈2, 1, 3〉 (C) 〈3, 2, 1〉 (D) 〈1, 3, 2〉<br />

Solution [C]<br />

x = 3z + 4<br />

and y = 2z –3<br />

⇒<br />

⇒<br />

x – 4<br />

3<br />

x – 4<br />

3<br />

= z and<br />

=<br />

y + 3<br />

2<br />

y + 3<br />

2<br />

= 1<br />

z<br />

= z<br />

∴ Direction ratios are proportional to 〈3, 2, 1〉<br />

Q.60 What is the equation to the straight line passing through (a, b, c) and parallel to z-axis ?<br />

(A)<br />

(C)<br />

x – a<br />

1<br />

x – a<br />

0<br />

=<br />

=<br />

y – b<br />

0<br />

y – b<br />

1<br />

=<br />

=<br />

z – c<br />

0<br />

z – c<br />

0<br />

(B)<br />

(D)<br />

x – a<br />

0<br />

x – a<br />

0<br />

Solution [B]<br />

Equation of line passing through (a, b, c) and parallel to z-axis is<br />

x – a<br />

0<br />

=<br />

y – b<br />

0<br />

=<br />

z – c<br />

1<br />

=<br />

=<br />

y – b<br />

0<br />

y – b<br />

1<br />

=<br />

=<br />

z – c<br />

1<br />

z – c<br />

1<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.61 What is 1+ x –1<br />

equal to ?<br />

x→0<br />

x<br />

(A) 0 (B) 1/2 (C) 1 (D) –1/2<br />

Solution [B]<br />

lim<br />

x→0<br />

1+ x – 1<br />

x<br />

=<br />

( 1 + x – 1)( 1 + x + 1)<br />

lim<br />

x→ 0 x( 1 + x + 1 )<br />

= lim (1 + x – 1)<br />

x→ 0 x( 1+<br />

x + 1 )<br />

= lim 1<br />

x→ 0 ( 1+<br />

x + 1 )<br />

1<br />

= 2<br />

Q.62 What is 2(1 – cos x)<br />

x→0<br />

2<br />

x<br />

equal to ?<br />

(A) 0 (B) 1/2 (C) 1/4 (D) 1<br />

Solution [D]<br />

x lim →0<br />

=<br />

=<br />

x lim →0<br />

x lim →0<br />

(1 – cos x)<br />

2.<br />

2<br />

x<br />

⎛ 2 x ⎞<br />

⎜2sin<br />

⎟<br />

2<br />

2.<br />

⎝ ⎠<br />

2<br />

x<br />

⎛<br />

⎜ sin<br />

4. ⎜<br />

⎜ x<br />

⎝ 2<br />

x<br />

2<br />

⎞<br />

2<br />

⎟<br />

⎟<br />

⎟<br />

⎠<br />

× 4<br />

1 = 1<br />

Q.63 Consider the following ?<br />

1.<br />

2.<br />

lim x→0<br />

x lim →0<br />

1 exists.<br />

x<br />

1<br />

e<br />

x<br />

does not exist<br />

which of the above is/are correct ?<br />

(A) 1 only (B) 2 only (C) Both 1 and 2 (D) Neither 1 nor 2<br />

Solution [B]<br />

lim<br />

x→0<br />

1 does not exist<br />

x<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q L.H.L. =<br />

lim<br />

–<br />

x→0<br />

1 = – ∞<br />

x<br />

R.H.L. =<br />

1<br />

lim<br />

+<br />

= + ∞<br />

x→0 x<br />

∴ limit does not exist<br />

x lim →0<br />

1<br />

e<br />

x<br />

does not exist<br />

Q L.H.L. =<br />

lim<br />

–<br />

x→0<br />

1<br />

e<br />

x<br />

= e –∞ = 0<br />

R.H.L. =<br />

1<br />

lim<br />

x<br />

+<br />

x→0<br />

∴ limit does not exist<br />

∴ (B) is correct<br />

e = e +∞ = ∞<br />

Q.64 If x m + y m dy x<br />

= 1 such that = – , then what should be the value of m ?<br />

dx y<br />

(A) 0 (B) 1 (C) 2 (D) None of the above<br />

Solution [C]<br />

mx m–1 + my m–1 dy = 0<br />

dx<br />

m–1<br />

dy x = –<br />

m– 1<br />

dx y<br />

∴ m –1 = 1<br />

m = 2<br />

= – y<br />

x<br />

x 2<br />

Q.65 Which one of the following is correct in respect of the function f(x) = for x ≠ 0 and f(0) = 0 ?<br />

| x |<br />

(A) f(x) is discontinuous every where<br />

(B) f(x) is continuous every where<br />

(C) f(x) is continuous at x = 0 only<br />

(D) f(x) is discontinuous at x = 0 only<br />

Solution [B]<br />

x 2<br />

f(x) = , x ≠ 0<br />

| x |<br />

f(0) = 0<br />

⎧–<br />

x<br />

⎪<br />

f(x) = ⎨ x<br />

⎪<br />

⎩ 0<br />

for<br />

for<br />

x < 0<br />

x > 0<br />

x = 0<br />

∴ f(x) is continuous every where<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.66 What is<br />

lim<br />

x→ 2<br />

2<br />

x – 4<br />

x – 2<br />

lim<br />

x→ 2 2<br />

x – 4<br />

equal to ?<br />

(A) 0 (B) 1/4 (C) 1/2 (D) 1<br />

Solution [B]<br />

x – 2<br />

= lim x – 2<br />

x→ 2 (x – 2)(x + 2 )<br />

⇒<br />

1<br />

lim<br />

x→ 2 (x + 2 )<br />

= 4<br />

1<br />

Q.67 The radius of a circle is uniformly increasing at the rate of 3 cm/s. What is the rate of increase in area, when<br />

the radius is 10 cm ?<br />

(A) 6π cm 2 /s (B) 10π cm 2 /s (C) 30π cm 2 /s (D) 60π cm 2 /s<br />

Solution [D]<br />

dr = 3<br />

dt<br />

A = πr 2<br />

dA dr = π2r<br />

dt dt<br />

= π.2.10.3<br />

= 60π cm 2 /s<br />

Q.68<br />

x + 5<br />

Let f: R → R be a function whose inverse is . What is f(x) equal to ?<br />

3<br />

(A) f(x) = 3x + 5 (B) f(x) = 3x – 5 (C) f(x) = 5x – 3 (D) f(x) does not exist<br />

Solution [B]<br />

x + 5<br />

y =<br />

3<br />

y is inverse of f(x)<br />

3y = x + 5<br />

∴ f(x) will be inverse of y<br />

x = 3y – 5<br />

f(x) = 3x – 5<br />

Q.69 Consider the following statements –<br />

dy<br />

1. If y = ln(sec x + tan x), then = sec x dx<br />

dy<br />

2. If y = ln (cosec x – cot x), then = cosec x<br />

dx<br />

Which of the above is/are correct ?<br />

(A) 1 only (B) 2 only (C) Both 1 and 2 (D) Neither 1 nor 2<br />

Solution [C]<br />

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18 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

1. y = ln(sec x + tan x)<br />

dy 1 = (sec x tan x + sec 2 x)<br />

dx (secx + tan x)<br />

= secx<br />

2. y = ln (cosec x – cot x)<br />

dy 1 = [–cosec x cot x + cosec 2 x]<br />

dx (cosecx – cot x)<br />

⇒ cosec x<br />

= cosec x<br />

[cosecx – cot x]<br />

(cosecx – cot x)<br />

Q.70 If f(x) = 2 sin x , then what is the derivative of f(x) ?<br />

(A) 2 sin x ln 2 (B) (sin x)2 sin x–1 (C) (cosx)2 sin x– 1 (D) None of the above<br />

Solution [D]<br />

f(x) = 2 sin x<br />

f '(x) = 2 sinx . ln 2. cosx<br />

Q.71 The function f(x) = x 3 – 3x 2 + 6 is an increasing function for -<br />

(A) 0 < x < 2 (B) x < 2 (C) x > 2 or x < 0 (D) all x<br />

Solution [C]<br />

f(x) = x 3 – 3x 2 + 6<br />

f '(x) = 3x 2 – 6x<br />

= 3x(x – 2)<br />

∴ f '(x) > 0 ∀ x ∈ (–∞, 0] ∪ [2, ∞)<br />

Q.72 Consider the following statements:<br />

1. If f(x) = x 3 and g(y) = y 3 then f = g<br />

2. Identity function is not always a bijection.<br />

Which of the above statements is/are correct ?<br />

(A) 1 only (B) 2 only (C) Both 1 and 2 (D) Neither 1 nor 2<br />

Solution [A]<br />

f(x) = x 3<br />

f(y) = y 3<br />

f and g are identical function<br />

⇒ f = g<br />

f(x) = x is an identity function and identity function is always one-one-onto<br />

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19 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.73 Let A = {x ∈ R, |x ≥ 0|}. A function f: A → A is defined by f(x) = x 2 . Which one of the following is correct ?<br />

(A) The function does not have inverse<br />

(B) f is its own inverse<br />

(C) The function has an inverse but f is not its own inverse<br />

(D) None of the above<br />

Solution [C]<br />

Q.74 If y = ln(e mx + e –mx dy<br />

), then what is at x = 0 equal to ?<br />

dx<br />

(A) –1 (B) 0 (C) 1 (D) 2<br />

Solution [B]<br />

y = log e (e mx + e –mx )<br />

dy 1 = (e mx .m + e –mx (–m))<br />

–mx<br />

dx (e<br />

+ e )<br />

=<br />

(e<br />

m<br />

mx +<br />

e<br />

–mx<br />

(e mx – e –mx )<br />

)<br />

⎛ dy ⎞<br />

⎜ ⎟<br />

⎝ dx ⎠<br />

x=<br />

0<br />

= 0<br />

Q.75 What is the minimum value of |x| ?<br />

(A) – 1 (B) 0 (C) 1 (D) 2<br />

Solution [D]<br />

min. value of |x| is 0<br />

Q.76 What is<br />

∫<br />

a e dx<br />

x<br />

x<br />

equal to ?<br />

Solution [C]<br />

x<br />

x<br />

a e<br />

(A) + c (B) a x e x + c (C)<br />

ln a<br />

Where c is the constant of integration.<br />

∫<br />

a<br />

x<br />

e<br />

x<br />

dx<br />

x<br />

∫<br />

(ae ) dx =<br />

(ae)<br />

+ c<br />

log (ae)<br />

e<br />

x<br />

x<br />

x<br />

a e<br />

ln(ae)<br />

+ c (D) None of the above<br />

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20 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

1<br />

Q.77 What is<br />

∫<br />

x | x | dx equal to ?<br />

–1<br />

(A) 2 (B) 1 (C) 0 (D) –1<br />

Solution [C]<br />

Let f(x) = x|x|<br />

1<br />

I =<br />

∫<br />

–1<br />

x<br />

| x | dx<br />

Q f(x) is an odd function<br />

∴ I = 0<br />

1<br />

tan x<br />

Q.78 What is<br />

∫<br />

dx equal to ?<br />

2<br />

1+<br />

x<br />

(A)<br />

Solution [B]<br />

2<br />

π<br />

1<br />

8<br />

0<br />

–1<br />

–1<br />

tan x<br />

I =<br />

∫<br />

dx,<br />

2<br />

1+<br />

x<br />

0<br />

tan –1 x = t<br />

1<br />

dx = dt<br />

2<br />

1+<br />

x<br />

π/<br />

4<br />

I =<br />

∫<br />

t dt<br />

0<br />

2<br />

π<br />

(B) 32<br />

(C) 4<br />

π<br />

(D) 8<br />

π<br />

⎡<br />

2<br />

t ⎤<br />

= ⎢ ⎥<br />

⎣ 2 ⎦<br />

π / 4<br />

0<br />

= 2<br />

1<br />

⎛<br />

2<br />

π ⎞<br />

⎜ ⎟<br />

⎝ 16 ⎠<br />

2<br />

π<br />

= 32<br />

π/<br />

2<br />

Q.79 What is<br />

∫sin 2x ln(cot x) dx equal to ?<br />

0<br />

(A) 0 (B) π ln 2 (C) –π ln2 (D)<br />

Solution [A]<br />

π/<br />

2<br />

I =<br />

∫sin<br />

2x ln(cot x) dx<br />

0<br />

⎛ π ⎞<br />

Q f ⎜ – x ⎟ = – f(x)<br />

⎝ 2 ⎠<br />

⎪⎧<br />

2a<br />

⎪⎫<br />

⎨∫<br />

f (x) dx = 0, if f (2a – x) = –f (x) ⎬<br />

⎪⎩ 0<br />

⎪⎭<br />

∴ I = 0<br />

πln 2<br />

2<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.80 What is the area of the portion of the curve y = sin x, lying between x = 0, y = 0 and x = 2π ?<br />

(A) 1 square unit (B) 2 square unit (C) 4 square unit (D) 8 square unit<br />

Solution [C]<br />

π<br />

Area = 2<br />

∫sin<br />

x dx<br />

0<br />

π<br />

= 2[–<br />

cos x] 0<br />

= –2(–1 –1)<br />

= 4<br />

ln x<br />

Q.81 What is<br />

∫ dx equal to ?<br />

x<br />

(A)<br />

2<br />

(ln x)<br />

2<br />

+ c (B)<br />

Where c is constant of integration<br />

Solution [A]<br />

ln x<br />

I =<br />

∫<br />

dx<br />

x<br />

put<br />

ln x = t<br />

1 dx = dt<br />

x<br />

I =<br />

∫ t dt<br />

t 2<br />

= 2<br />

(ln x)<br />

2<br />

+ c (C) (ln x) 2 + c (D) None of the above<br />

=<br />

2<br />

(ln x)<br />

2<br />

+ c<br />

Q.82 What is the area of the region bounded by the lines y = x, y = 0 and x = 4 ?<br />

(A) 4 square units (B) 8 square units (C) 12 square units (D) 16 square units<br />

Solution [B]<br />

(4, 4)<br />

(0, 0) (4, 0)<br />

y = x<br />

x = 4<br />

Area = 2<br />

1 × 4 × 4 = 8 square unit<br />

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22 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

⎛ 1 1 ⎞<br />

Q.83 What is<br />

∫ ⎜ – ⎟dx<br />

equal to ?<br />

2 2<br />

⎝ cos x sin x ⎠<br />

(A) 2 cosec 2x + c (B) –2cot 2x + c (C) 2sec 2x + c (D) –2tan 2x + c<br />

Where c is constant of integration<br />

Solution [A]<br />

⎛ 1 1 ⎞<br />

∫⎜<br />

– ⎟dx<br />

2 2<br />

⎝ cos x sin x ⎠<br />

=<br />

∫<br />

sec 2 x dx –<br />

∫<br />

cosec x dx<br />

= tan x + cot x + c<br />

=<br />

sin x<br />

cos x<br />

2<br />

sin x<br />

+<br />

cos x<br />

sin x<br />

2<br />

cos x<br />

+ c<br />

+<br />

=<br />

+ c<br />

sin x.cos x<br />

1<br />

=<br />

+ c<br />

sin x.cos x<br />

2<br />

= + c<br />

sin 2x<br />

= 2 cosec 2x + c<br />

where c is constant of integration<br />

2<br />

Q.84<br />

3<br />

d y ⎛<br />

2<br />

d y ⎞<br />

What is the degree of the differential equaltion + 2 ⎜ ⎟<br />

3<br />

2<br />

dx<br />

dx<br />

⎝ ⎠<br />

dy<br />

– + y = 0 dx<br />

(A) 6 (B) 3 (C) 2 (D) 1<br />

Solution [D]<br />

3<br />

d y ⎛<br />

2<br />

d y ⎞<br />

+ 2 ⎜ ⎟<br />

3<br />

2<br />

dx<br />

dx<br />

⎝ ⎠<br />

degree = 1<br />

2<br />

dy<br />

– + y = 0 dx<br />

Q.85 Consider a differential equation of order m and degree n. Which one of the following pairs is not feasible ?<br />

(A) (3, 2) (B) (2, 3/2) (C) (2, 4) (D) (2, 2)<br />

Solution [B]<br />

Degree of differential equation cannot be fraction<br />

Q.86 The differential equation respresenting the family of curves y = a sin(λx + a) is -<br />

(A)<br />

d<br />

2<br />

dx<br />

y<br />

2<br />

+ λ 2 y = 0 (B)<br />

Solution [A]<br />

y = a sin (λx + α)<br />

dy = a cos (λx + α). λ<br />

dx<br />

= aλ cos (λx + α)<br />

d<br />

2<br />

dx<br />

y<br />

2<br />

– λ 2 y = 0 (C)<br />

2<br />

2<br />

d y<br />

+ λy = 0 (D) none of the above<br />

2<br />

dx<br />

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23 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

d<br />

2<br />

dx<br />

y<br />

2<br />

= aλ(–sin(λx + α)).λ<br />

= – λ 2 y sin (λx + α)<br />

= –λ 2 y<br />

d<br />

2<br />

dx<br />

y<br />

2<br />

+ λ 2 y = 0<br />

Q.87<br />

dy<br />

The differential equation y + x = a where 'a' is any constant represents -<br />

dx<br />

(A) A set of straight lines (B) A set of ellipses (C) A set of circles (D) None of the above<br />

Solution [C]<br />

dy<br />

y. + x = a dx<br />

∫ y . dy = ∫<br />

( a – x) dx<br />

y 2 x 2<br />

= ax – + c<br />

2 2<br />

x 2 +<br />

2<br />

y 2 – ax – c = 0<br />

2<br />

x 2 + y 2 – 2ax – 2c = 0<br />

Which is a circle<br />

2<br />

Q.88<br />

⎛ dy ⎞ ⎛ dy ⎞<br />

For the differential equation ⎜ ⎟⎠ –x ⎜ ⎟ + y = 0, which one of the following is not its solution ?<br />

⎝ dx ⎝ dx ⎠<br />

(A) y = x – 1 (B) 4y = x 2 (C) y = x (D) y = – x –1<br />

Solution [C]<br />

2<br />

⎛ dy ⎞ ⎛ dy ⎞<br />

⎜ ⎟⎠ – x. ⎜ ⎟ + y = 0<br />

⎝ dx ⎝ dx ⎠<br />

dy<br />

if y = x – 1 then = 1 dx<br />

⎛ dy ⎞<br />

2 ⎛ dy ⎞<br />

⎜ ⎟ − x⎜<br />

⎟ y<br />

⎝ dx ⎠ ⎝ dx ⎠<br />

+<br />

= (1) 2 – x (1) + (x – 1)<br />

= 1 – x + x – 1<br />

= 0<br />

⇒ y = x – 1 is a solution<br />

if 4y = x 2<br />

dy dy x<br />

4 ⋅ = 2x ⇒ =<br />

dx dx 2<br />

∴<br />

⎛ dy ⎞<br />

2 ⎛ dy ⎞<br />

⎜ ⎟ − x⎜<br />

⎟ y<br />

⎝ dx ⎠ ⎝ dx ⎠<br />

+<br />

⎛ x ⎞<br />

= ⎜ ⎟<br />

⎝ 2 ⎠<br />

2<br />

2<br />

x x<br />

− x ⋅ +<br />

2 4<br />

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24 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

= 0 ⇒ 4y = x 2 is a solution of differential equation<br />

if y =x<br />

dy<br />

then = 1<br />

dx<br />

2<br />

⎛<br />

∴<br />

dy ⎞ ⎛ dy ⎞<br />

⎜ ⎟ − x⎜<br />

⎟ + y = 1<br />

2 − x ⋅1+<br />

x<br />

⎝ dx ⎠ ⎝ dx ⎠<br />

= 1 ≠ 0<br />

⇒ y = x is not its solution<br />

Hence (C) is correct.<br />

Q.89 What is the general solution of the differential equation x 2 dy + y 2 dx = 0 ?<br />

(A) x + y = c<br />

(B) xy = c<br />

(C) c(x + y) = xy<br />

(D) None of these<br />

Which c is the constant of integration<br />

Solution [C]<br />

x 2 dy + y 2 dx = 0<br />

x 2 dy = – y 2 dx<br />

dx dy<br />

+ = 0<br />

2 2<br />

x y<br />

on integrating, we get<br />

1 1<br />

− − = C 1<br />

where C 1 is constant of integration<br />

x y<br />

x + y<br />

= −C 1<br />

xy<br />

x + y = – C 1 (xy)<br />

1<br />

⇒ (x + y) = xy<br />

− C<br />

1<br />

⇒ C(x + y) = xy<br />

1<br />

where C = −<br />

Q.90 What is the general solution of the differential equation e x tanydx + (1 – e x ) sec 2 ydy = 0 ?<br />

(A) sin y = c(1 – e x ) (B) cos y = c(1– e x )<br />

(C) cot y = c(1 – e x )<br />

(D) None of the above<br />

where c is the constant of integration<br />

Solution [D]<br />

e x tan y dx + (1 – e x ) sec 2 y dy = 0<br />

e x tan y dx = (e x – 1) sec 2 y dy<br />

x<br />

2<br />

e sec y<br />

dx = dy<br />

x<br />

e −1<br />

tan y<br />

Integrating both side<br />

∫<br />

dx<br />

x =<br />

∫<br />

ln<br />

e<br />

e<br />

x<br />

−1<br />

e x −1<br />

tan y<br />

2<br />

C 1<br />

sec y<br />

dy ⇒ ln (e x –1) = ln tan y + ln C<br />

tan y<br />

e x −1<br />

= ln C ⇒ = C<br />

tan y<br />

⇒ (1 – e x ) = C 1 tany<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.91 EFGH is a rhombus such that the angle EFG is 60°. The magnitude of vectors FH and { EG}<br />

Solution [D]<br />

H<br />

where m is a scalar. What is the value of m ?<br />

(A) 3 (B) 1.5 (C) 2 (D) 3<br />

G<br />

m are equal<br />

E<br />

Let FH = λ & EG = G<br />

from ∆EFG<br />

2 2 2<br />

a + a − k<br />

cos60°<br />

=<br />

2<br />

2a<br />

2 2<br />

1 2a − k<br />

=<br />

2<br />

2 2a<br />

k 2 = a 2<br />

∴ k = a<br />

from ∆EFH<br />

2 2 2<br />

a + a − λ<br />

cos120°<br />

=<br />

2.a.a<br />

1 2 2<br />

2a −<br />

− =<br />

λ<br />

2<br />

2 2a<br />

–a 2 = 2a 2 –λ 2<br />

λ 2 = 3a 2<br />

∴ λ = 3a<br />

Q | FH | = m | EG |<br />

3 a = ma<br />

∴ m = 3<br />

F<br />

r r r r r<br />

Q.92 If a .b = 0 and a × b = 0 then which one of the following is correct ?<br />

(A) a r is parallel to b r<br />

(B) a r is perpendicular to b r<br />

r r r<br />

(C) a = 0 or b = 0<br />

(D) None of the above<br />

Solution [C]<br />

a⋅b = 0<br />

a & b are perpendicular<br />

a × b = 0<br />

a & b are parallel<br />

r r<br />

it is possible only when a = 0 or b = 0<br />

r r r<br />

Q.93 The vectors a ( b × a)<br />

(A) a r only<br />

(C) both a r and b r<br />

Solution [C]<br />

× is coplanar with<br />

(B) b r only<br />

(D) Neither a r or b r<br />

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26 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

r r r<br />

a × (b×<br />

a)<br />

r r r rr r<br />

⇒ (a.a)b − (ab) a<br />

r r<br />

⇒ λ b − µ a = coplanar with a r & b r<br />

CAREER POINT<br />

Q.94 Consider the following<br />

1. 4 î × 3î = 0<br />

2.<br />

4 î 4 =<br />

3î 3<br />

Which of the following above is/are correct ?<br />

(A) 1 only<br />

(B) 2 only<br />

(C) Both 1 and 2 (D) Neither 1 nor 2<br />

Solution [A]<br />

1. 4 î × 3î = 0<br />

2.<br />

4 î 4 =<br />

3î 3<br />

Q division of vector not applicable<br />

∴ only 1 st is correct<br />

Q.95 What is the value of λ for which ( λ î + ĵ − kˆ) × (3î − 2ĵ + 4kˆ) = (2î −11ĵ<br />

− 7kˆ ) ?<br />

(A) 2 (B) –2 (C) 1 (D) 7<br />

Solution [A]<br />

( λ î + ĵ − k) × (3î − 2ĵ + 4k) = (2î −11ĵ<br />

− 7k)<br />

î<br />

λ<br />

3<br />

ĵ<br />

1<br />

− 2<br />

from above<br />

4λ + 3 = 11<br />

∴ λ = 2<br />

k<br />

−1<br />

= 2î −11ĵ−<br />

7kˆ<br />

4<br />

Q.96 The magnitude of the scalar p for which the vector p ( − 3î − 2ĵ + 13kˆ ) is of unit length is<br />

(A) 1/8 (B) 1/64 (C) 182 (D)<br />

1<br />

182<br />

Solution [D]<br />

| p( − 3î − 2ĵ + 13kˆ) | = 1<br />

∴ p 9 + 4 + 169 = 1<br />

∴<br />

p =<br />

1<br />

182<br />

Q.97 The vector 2ĵ<br />

− kˆ lies<br />

(A) in the plane of XY (B) in the plane of YZ (C) in the Plane of XZ (D) along the X-axis<br />

Solution [B]<br />

given vector is 2ĵ<br />

− kˆ<br />

hence it lies in yz plane only<br />

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27 / 33


MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

Q.98 ABCD is a parallelogram. If AB = a<br />

r , BC = b<br />

r<br />

, then what is BD equal to ?<br />

(A) a<br />

r r<br />

r r<br />

+ b<br />

(B) a − b<br />

(C) a<br />

r − b<br />

r<br />

r r<br />

− (D) − a + b<br />

Solution [D]<br />

D<br />

C<br />

CAREER POINT<br />

b r<br />

A a r<br />

BC = AD<br />

AB + BD = AD<br />

∴ BD = AD − AB<br />

r<br />

⇒ b a<br />

r −<br />

B<br />

Q.99 What is the geometric mean of the sequence 1, 2, 4, 8, .........., 2 n ?<br />

(A) 2 n/2 (B) 2 (n+1)/2 (C) 2 (n + 1) –1 (D) 2 (n–1)<br />

Solution [A]<br />

G = al<br />

n<br />

= 1× 2<br />

= 2 n/2<br />

Q.100 The mean of 10 observations is 5. If 2 added to each observation and then multiplied by3, then what will be<br />

the new mean ?<br />

(A) 5 (B) 7 (C) 15 (D) 21<br />

Solution [D]<br />

xi<br />

xi<br />

x = 5 =<br />

∑ =<br />

∑<br />

n 10<br />

∑ x i = 10×<br />

5<br />

= 50<br />

if 2 is added to each number<br />

new sum = ∑ x i + n × 2<br />

= 50 + 10 × 2<br />

= 70<br />

70<br />

New mean x = = 7<br />

10<br />

Since, 3 is multiplied to each number mean is also multiplied by 3<br />

New mean = 7 × 3 = 21<br />

Q.101 What is the mean of first n odd natural numbers ?<br />

(A) n (B) (n + 1) / 2<br />

(C) n (n + 1) /2 (D) n + 1<br />

Solution [A]<br />

Sum of first n odd natural number<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

S = 1 + 3 + 5 + ............ + (2n – 1)<br />

n<br />

2<br />

S = (1 + 2n −1)<br />

= n<br />

2<br />

sum of observation n 2<br />

mean = = = n<br />

number of observation n<br />

Q.102 The arithmetic mean of numbers a, b, c, d, e is M. What is the value of<br />

(a – M) + (b – M) + (c – M) + (d – M) + (e – M) ?<br />

(A) M (B) a + b + c + d + e (C) 0 (D) 5M<br />

Solution [C]<br />

a + b + c + d + e<br />

Mean =<br />

= M<br />

5<br />

( a − M) + (b − M) + (c − M) + (d − M) + (e − m)<br />

New mean =<br />

5<br />

⎛ a + b + c + d + e ⎞<br />

= ⎜<br />

⎟ − M<br />

⎝ 5 ⎠<br />

= M– M<br />

new mean = 0<br />

Q.103 The algebraic sum of the deviations of 20 observations measured from 30 is 2. What would be the mean of<br />

the observations ?<br />

(A) 30 (B) 32 (C) 30.2 (D) 30.1<br />

Solution [D]<br />

Standard deviation = 30<br />

algebraic sum with deviation =∑ x i h =<br />

∑ − h 2<br />

x i<br />

Mean = + h = + 30<br />

20 20<br />

= 30 + 0.1<br />

= 30.1<br />

− 2<br />

Q.104 The median of 27 observations of a variable is 18, three more observations are made and the values of these<br />

observations are 16, 18 and 50. What is the median of these 30 observations ?<br />

(A) 18 (B) 19<br />

(C) 25.5<br />

(D) Can not be determined due to insufficient data<br />

Solution [A]<br />

Median of 27 observations = 18<br />

th<br />

⎛ 27 + 1⎞<br />

then , ⎜ ⎟ observation = 18<br />

⎝ 2 ⎠<br />

14 th observation = 18<br />

Then, observation whose value is 16 come before 18,<br />

i.e. 14 th observation<br />

Now, number of observation is even = 30 observation<br />

th<br />

th<br />

⎛ 30 ⎞ ⎛ 30 ⎞<br />

⎜ ⎟ + ⎜ + 1⎟<br />

2 2<br />

median =<br />

⎝ ⎠ ⎝ ⎠<br />

2<br />

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MATHEMATICS<br />

th<br />

15 obs + 16<br />

=<br />

2<br />

18 + 18<br />

= = 18<br />

2<br />

th<br />

obs<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.105 Frequency curve may be<br />

(A) symmetrical (B) positive skew (C) negative skew (D) all the above<br />

Solution [D]<br />

Frequency curve may be<br />

(1) positive skew<br />

(2) negative skew<br />

(3) Symmetrical<br />

Q.106 The monthly family expenditure (in percentage) on different items are as follows<br />

Food Rent Cloth transport Education Others<br />

38 19 18 - - - - - - 9 6<br />

If the total monthly expenditure is Rs 9000, What is the expenditure on transport ?<br />

(A) Rs 180 (B) Rs 1000<br />

(C) Rs. 900 (D) Rs. 360<br />

Solution [C]<br />

Food Rent Cloth transport Education Others total<br />

38 19 18 - - - - - - 9 6 100%<br />

Then, Transport = 100 – (38 + 19 + 18 + 9 + 6)<br />

= 100 – (90)<br />

= 10%<br />

Total expenditure = Rs. 9000<br />

10<br />

Expenditure on Transport = × 9000<br />

100<br />

= Rs .900<br />

Q.107 If the mean of few observations is 40 and standard deviation is 8, then what is the coefficient of variation ?<br />

(A) 1% (B) 10% (C) 20% (D) 30%<br />

Solution [C]<br />

x = 40<br />

σ = 8<br />

coefficient of variance =<br />

6 × 100<br />

x<br />

8<br />

⇒ × 100 = 20%<br />

40<br />

Q.108 What is the standard deviation of 7, 9, 11, 13, 15 ?<br />

(A) 2.4 (B) 2.5 (C) 2.7 (D) 2.8<br />

Solution [D]<br />

x x – x (x – x ) 2<br />

7 – 4 16<br />

9 –2 14<br />

11 0 0<br />

13 2 4<br />

15 4 16<br />

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MATHEMATICS<br />

55<br />

x = = 11<br />

5<br />

2<br />

∑(x<br />

− x) 40<br />

σ =<br />

= ≈ 2. 8<br />

n 5<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.109 Which one of the following is a measure of dispersion ?<br />

(A) Mean (B) Median (C) Mode (D) Standard deviation<br />

Solution [D]<br />

Measure of dispersion is standard deviation<br />

Q.110 Let X and Y be two related variables. The two regression lines are given by x – y + 1 = 0 and 2x – y + 4 = 0 .<br />

The two regression lines pass through the point<br />

(A) (–4, –3) (B) (–6, –5) (C) (3, –2) (D) (–3, –2)<br />

Solution [D]<br />

Lines passing through ( ( x, y)<br />

which is intersection point of two lines<br />

Q.111 If P(E) denotes the probability of an event E, then E is called certain event if<br />

(A) P(E) = 0 (B) P(E) = 1 (C) P(E) is either 0 or 1 (D) P(E) = 1/2<br />

Solution [B]<br />

Since E is certain event,<br />

P(E) = 1<br />

Q.112 What is the probability that a leap year selected at random will contain 53 Mondays ?<br />

(A) 2/5 (B) 2/7 (C) 1/7 (D) 5/7<br />

Solution [A]<br />

1 leap year = 365 days<br />

364 = 52 × 7<br />

so<br />

366 – 367 = 2 days<br />

two possibilities are there for two monday out of seven possibilities<br />

2<br />

Hence, probability is = 7<br />

3<br />

1 2<br />

Q.113 If A and B are two events such that P (A ∪ B) = , P (A ∩ B) = , P (A) = where A is the complement<br />

4<br />

4 3<br />

of A, then what is P(B) equal to ?<br />

(A) 1/3 (B) 2/3 (C) 1/9 (D) 2/9<br />

Solution [B]<br />

2<br />

P (A) =<br />

3<br />

2 1<br />

then P (A) = 1−<br />

=<br />

3 3<br />

3 1 1<br />

= + P(B) −<br />

4 3 4<br />

3 1 1<br />

P(B)<br />

= + −<br />

4 4 3<br />

4 1 1 2<br />

= − = 1−<br />

=<br />

4 3 3 3<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

Q.114 Three coins are tossed simultaneously . What is the probability that they will fall two heads and one tail ?<br />

(A) 1/3 (B) 1/2 (C) 1/4 (D) 3/8<br />

Solution [D]<br />

Sample space = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}<br />

3<br />

P(two head and one tail) = 8<br />

Q.115 Which one of the following is correct ?<br />

(A) An event having no sample point is called an elementary event<br />

(B) An event having one sample point is called an elementary event<br />

(C) An event having two sample points is called an elementary event<br />

(D) An event having many sample points is called an elementary event<br />

Solution [B]<br />

Q.116 What is the most probable number of successes in 10 trials with probability of success 2/3 ?<br />

(A) 10 (B) 7 (C) 5 (D) 4<br />

Solution [B]<br />

p(r) = n C r ⋅ p r ⋅ q n–r<br />

n = 10, p = 2/3, q = 1/3<br />

FOR THE NEXT TWO (02) QUESTIONS THAT FOLLOW<br />

An urn contains one black ball and one green ball. A second urn contains one white and one green ball. One<br />

ball is drawn at random from each urn.<br />

Q.117 What is the probability that both balls are of same colour ?<br />

(A) 1/2 (B) 1/3 (C) 1/4 (D) 2/3<br />

Solution [C]<br />

Since, ball should be of same colour<br />

So, colour is green<br />

ways of selecting a green ball from 1 st urn = 1/2<br />

ways of selecting a green ball from II nd urn = ½<br />

1 1<br />

Now, probability that both of should be of same colour = =<br />

2×<br />

2 4<br />

Q.118 What is the probability of getting at least one green ball ?<br />

(A) 1/2 (B) 1/3 (C) 2/3 (D) 3/4<br />

Solution [D]<br />

P(at least one green ball) = 1 – P (no ball is green)<br />

= 1 – P (i.e. ball is white and black)<br />

=<br />

1 1<br />

1 − ×<br />

2 2<br />

1<br />

= 1−<br />

4<br />

3<br />

= 4<br />

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MATHEMATICS<br />

NDA-2012 EXAMINATION<br />

CAREER POINT<br />

FOR THE NEXT TWO (02) QUESTIONS THAT FOLLOW<br />

Two dice each numbered from 1 to 6 are thrown together. Let A and B be two events given by<br />

A : event number on the first die<br />

B : number on the second die is greater than 4<br />

Q.119 What is P(A ∪ B) equal to ?<br />

(A) 1/2 (B) 1/4<br />

(C) 2/3 (D) 1/6<br />

Solution [C]<br />

A : even numbers = {2, 4, 6}<br />

B : number > 4 = {5, 6} A ∩ B = {6}<br />

1<br />

P (A ∩ B) =<br />

6<br />

3 1<br />

P (A) = =<br />

6 2<br />

2 1<br />

P (B) = =<br />

6 3<br />

P(A∪B) = P(A) + P(B) –P(A∩B)<br />

1 1 1<br />

= + −<br />

2 3 6<br />

3 + 2 −1<br />

= =<br />

6<br />

4 =<br />

6<br />

2<br />

3<br />

Q.120 What is P(A∩B) equal to ?<br />

(A) 1/2 (B) 1/4<br />

(C) 2/3 (D) 1/6<br />

Solution [D]<br />

1<br />

P (A ∩ B) =<br />

6<br />

A ∩ B = {6}<br />

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