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2007-2008 Grade 8 Mathematics Item and Scoring Sampler

2007-2008 Grade 8 Mathematics Item and Scoring Sampler

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MATHEMATICS<br />

<strong>Item</strong> #27<br />

Top <strong>Scoring</strong> Response:<br />

Part A Answer<br />

Train L : 3 (hours)<br />

Train M: 3.75 (hours) or<br />

3 3 } (hours) or<br />

4<br />

3 hours <strong>and</strong> 45 minutes<br />

Train L :<br />

Support<br />

d = r • t<br />

225 = 75 • t<br />

225<br />

}<br />

75 = 75t }<br />

75<br />

3 = t<br />

Train M :<br />

225 = 60 • t<br />

225<br />

}<br />

60 = 60t }<br />

60<br />

3.75 = tmi<br />

AND<br />

(2 score points)<br />

0.5 point for 2 correct times<br />

1.5 points for complete support<br />

Sample Explanation:<br />

I used the distance formula (distance equals rate times time) for each<br />

train. I put in 225 miles for the distance <strong>and</strong> then put in each train’s<br />

speed. I then solved each equation for t to determine each train’s time<br />

to travel 225 miles.<br />

OR equivalent<br />

Part B Answer<br />

810 (miles)<br />

Train L :<br />

Train M :<br />

Support<br />

d = r • t<br />

d = 75 • 6<br />

d = 450<br />

d = 60 • 6<br />

d = 360<br />

450 + 360 = 810<br />

AND<br />

(2 score points)<br />

0.5 point for correct answer<br />

1.5 points for complete support<br />

Sample Explanation:<br />

I put the trains’ time (6) <strong>and</strong> each train’s rate into the distance formula. By<br />

multiplying rate times time, I found the distance each train traveled in 6 hours.<br />

Then, since the trains are going in opposite directions, I added the distances together<br />

to determine the total distance between them.<br />

OR equivalent<br />

<strong>Grade</strong> 8 <strong>Mathematics</strong> <strong>Item</strong> <strong>Sampler</strong> <strong>2007</strong>–<strong>2008</strong> 39

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