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Factoring the Sum or Difference of Two Cubes The Sum of Cubes ...

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Answers<br />

Fact<strong>or</strong>:<br />

8a<br />

+ b<br />

3 3<br />

We begin by rewriting each term as a cube and use <strong>the</strong> sum <strong>of</strong> cubes f<strong>or</strong>mula as<br />

a guide.<br />

( )( )<br />

x + y = x + y x − xy + y<br />

3 3 2 2<br />

( )( )<br />

8 a + b = (2 a) + ( b) = 2 a+ b (2 a) − (2 a)( b) + ( b)<br />

3 3 3 3 2 2<br />

So simplifying <strong>the</strong> right hand side we get:<br />

( )( )<br />

3 3 2 2<br />

8a + b = 2a+ b 4a − 2ab+ b Answer<br />

Fact<strong>or</strong>:<br />

8a<br />

− b<br />

3 3<br />

We begin by rewriting each term as a cube and use <strong>the</strong> difference <strong>of</strong> cubes<br />

f<strong>or</strong>mula as a guide.<br />

( )( )<br />

x − y = x − y x + xy + y<br />

3 3 2 2<br />

( )( )<br />

8 a − b = (2 a) − ( b) = 2 a− b (2 a) + (2 a)( b) + ( b)<br />

3 3 3 3 2 2<br />

So simplifying <strong>the</strong> right hand side we get:<br />

( )( )<br />

3 3 2 2<br />

8a − b = 2a− b 4a + 2ab+ b Answer<br />

Fact<strong>or</strong>:<br />

8a<br />

+ 27b<br />

3 3<br />

We begin by rewriting each term as a cube and use <strong>the</strong> sum <strong>of</strong> cubes f<strong>or</strong>mula as<br />

a guide.<br />

( )( )<br />

x + y = x + y x − xy + y<br />

3 3 2 2<br />

( )( )<br />

8a + 27 b = (2 a) + (3 b) = 2a+ 3 b (2 a) − (2 a)(3 b) + (3 b)<br />

3 3 3 3 2 2<br />

So simplifying <strong>the</strong> right hand side we get:<br />

( )( )<br />

3 3 2 2<br />

8a + 27b = 2a+ 3b 4a − 6ab+ 9b<br />

Answer

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