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Factoring the Sum or Difference of Two Cubes The Sum of Cubes ...

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<strong>Fact<strong>or</strong>ing</strong> <strong>the</strong> <strong>Sum</strong> <strong>or</strong> <strong>Difference</strong> <strong>of</strong> <strong>Two</strong> <strong>Cubes</strong><br />

<strong>The</strong> <strong>Sum</strong> <strong>of</strong> <strong>Cubes</strong> <strong>Fact<strong>or</strong>ing</strong> F<strong>or</strong>mula is:<br />

( )( )<br />

x + y = x + y x − xy + y<br />

3 3 2 2<br />

<strong>The</strong> <strong>Difference</strong> <strong>of</strong> <strong>Cubes</strong> <strong>Fact<strong>or</strong>ing</strong> F<strong>or</strong>mula is:<br />

( )( )<br />

x − y = x − y x + xy + y<br />

3 3 2 2<br />

Fact<strong>or</strong>:<br />

8a<br />

+ b<br />

3 3<br />

Fact<strong>or</strong>:<br />

8a<br />

− b<br />

3 3<br />

Fact<strong>or</strong>:<br />

8a<br />

+ 27b<br />

3 3<br />

Fact<strong>or</strong>:<br />

64x<br />

− 27y<br />

3 3<br />

Fact<strong>or</strong>:<br />

24a<br />

+ 3ax<br />

4 3


Answers<br />

Fact<strong>or</strong>:<br />

8a<br />

+ b<br />

3 3<br />

We begin by rewriting each term as a cube and use <strong>the</strong> sum <strong>of</strong> cubes f<strong>or</strong>mula as<br />

a guide.<br />

( )( )<br />

x + y = x + y x − xy + y<br />

3 3 2 2<br />

( )( )<br />

8 a + b = (2 a) + ( b) = 2 a+ b (2 a) − (2 a)( b) + ( b)<br />

3 3 3 3 2 2<br />

So simplifying <strong>the</strong> right hand side we get:<br />

( )( )<br />

3 3 2 2<br />

8a + b = 2a+ b 4a − 2ab+ b Answer<br />

Fact<strong>or</strong>:<br />

8a<br />

− b<br />

3 3<br />

We begin by rewriting each term as a cube and use <strong>the</strong> difference <strong>of</strong> cubes<br />

f<strong>or</strong>mula as a guide.<br />

( )( )<br />

x − y = x − y x + xy + y<br />

3 3 2 2<br />

( )( )<br />

8 a − b = (2 a) − ( b) = 2 a− b (2 a) + (2 a)( b) + ( b)<br />

3 3 3 3 2 2<br />

So simplifying <strong>the</strong> right hand side we get:<br />

( )( )<br />

3 3 2 2<br />

8a − b = 2a− b 4a + 2ab+ b Answer<br />

Fact<strong>or</strong>:<br />

8a<br />

+ 27b<br />

3 3<br />

We begin by rewriting each term as a cube and use <strong>the</strong> sum <strong>of</strong> cubes f<strong>or</strong>mula as<br />

a guide.<br />

( )( )<br />

x + y = x + y x − xy + y<br />

3 3 2 2<br />

( )( )<br />

8a + 27 b = (2 a) + (3 b) = 2a+ 3 b (2 a) − (2 a)(3 b) + (3 b)<br />

3 3 3 3 2 2<br />

So simplifying <strong>the</strong> right hand side we get:<br />

( )( )<br />

3 3 2 2<br />

8a + 27b = 2a+ 3b 4a − 6ab+ 9b<br />

Answer


Fact<strong>or</strong>:<br />

64x<br />

− 27y<br />

3 3<br />

We begin by rewriting each term as a cube and use <strong>the</strong> difference <strong>of</strong> cubes<br />

f<strong>or</strong>mula as a guide.<br />

( )( )<br />

x − y = x − y x + xy + y<br />

3 3 2 2<br />

( )( )<br />

64x − 27 y = (4 x) − (3 y) = 4x− 3 y (4 x) + (4 x)(3 y) + (3 y)<br />

3 3 3 3 2 2<br />

So simplifying <strong>the</strong> right hand side we get:<br />

( )( )<br />

3 3 2 2<br />

64x − 27y = 4x− 3y 16x + 12xy + 9y<br />

Answer<br />

Fact<strong>or</strong>:<br />

24a<br />

+ 3ax<br />

4 3<br />

This problem doesn’t even look like a sum <strong>or</strong> difference <strong>of</strong> cubes problem.<br />

However, <strong>the</strong>re is a common fact<strong>or</strong> in each <strong>of</strong> <strong>the</strong> two terms. It is 3a . So we<br />

can write:<br />

( )<br />

4 3 3 3<br />

24a + 3ax = 3a 8a + x Now notice that <strong>the</strong> fact<strong>or</strong> in paren<strong>the</strong>ses is a sum<br />

<strong>of</strong> two cubes and except f<strong>or</strong> <strong>the</strong> x it is <strong>the</strong> same expression that was fact<strong>or</strong>ed in<br />

<strong>the</strong> first exercise on this sheet. So we can write:<br />

( ) ( )( )<br />

4 3 3 3 2 2<br />

24a + 3ax = 3a 8a + x = 3a 2a+ x 4a − 2ax+ x Answer

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