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Precalculus Chapter 6 Worksheet Graphing Sinusoidal Functions in ...

Precalculus Chapter 6 Worksheet Graphing Sinusoidal Functions in ...

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<strong>Precalculus</strong> <strong>Chapter</strong> 6 <strong>Worksheet</strong><br />

<strong>Graph<strong>in</strong>g</strong> <strong>S<strong>in</strong>usoidal</strong> <strong>Functions</strong> <strong>in</strong> Degree Mode<br />

F<strong>in</strong>d the amplitude, period, phase (horizontal) displacement and translation (vertical displacement).<br />

Then use the <strong>in</strong>formation to f<strong>in</strong>d the critical po<strong>in</strong>ts and sketch two cycles for the graph (one to the right<br />

and one to the left of the center po<strong>in</strong>t).<br />

1. y = 7 + 4cos3( θ − 10 ° )<br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

_________<br />

_________<br />

_________<br />

_________<br />

2. y = − 10 + 20s<strong>in</strong> 2( θ + 30 ° )<br />

3.<br />

4.<br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

1<br />

y = 3− 5cos ( θ + 90 ° )<br />

2<br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

_________<br />

_________<br />

_________<br />

_________<br />

_________<br />

_________<br />

_________<br />

_________<br />

1<br />

1000 + 3000s<strong>in</strong> ( 60 )<br />

3 θ + °<br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

5. y = 11− 6s<strong>in</strong>( θ − 17 ° )<br />

_________<br />

_________<br />

_________<br />

_________<br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

_________<br />

_________<br />

_________<br />

_________


<strong>Precalculus</strong> <strong>Chapter</strong> 6 <strong>Worksheet</strong><br />

<strong>Graph<strong>in</strong>g</strong> <strong>S<strong>in</strong>usoidal</strong> <strong>Functions</strong> <strong>in</strong> Radian Mode<br />

F<strong>in</strong>d the amplitude, period, phase (horizontal) displacement and translation (vertical displacement).<br />

Then use the <strong>in</strong>formation to f<strong>in</strong>d the critical po<strong>in</strong>ts and sketch two cycles for the graph (one to the right<br />

and one to the left of the center po<strong>in</strong>t).<br />

1.<br />

2.<br />

1<br />

y = 3+ 2cos ( x − π )<br />

5<br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

_________<br />

_________<br />

_________<br />

_________<br />

2 π <br />

y = − 4 + 5s<strong>in</strong> x<br />

+ 3 2 <br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

_________<br />

_________<br />

_________<br />

_________<br />

π <br />

3. y = 2 − 6cos3x<br />

+ <br />

6 <br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

π<br />

4. 2 + 6s<strong>in</strong> ( 1)<br />

4 x −<br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

_________<br />

_________<br />

_________<br />

_________<br />

_________<br />

_________<br />

_________<br />

_________<br />

π<br />

5. y = −5 − 4s<strong>in</strong> ( x + 2)<br />

3<br />

Amplitude:<br />

Period:<br />

Phase:<br />

Translation:<br />

_________<br />

_________<br />

_________<br />

_________


<strong>Graph<strong>in</strong>g</strong> Tangent and Reciprocal <strong>Functions</strong><br />

Graph the follow<strong>in</strong>g:<br />

Assume the function is circular (use radians) if the <strong>in</strong>dependent variable is x and trigonometric (use<br />

degrees) if the <strong>in</strong>dependent variable is θ. Graph two cycle of each.<br />

1. y = tan 2θ<br />

9. y = 4 + 3tanπ<br />

x<br />

π<br />

2. y = cot x 3<br />

10. y = − 5 + 3cot 4θ<br />

π<br />

3. y = csc x 2<br />

11. y = − 6 + 2csc5θ<br />

4. y = sec3θ<br />

π<br />

12. y = 1+<br />

4sec x 10<br />

5. y = 2cot x<br />

13. y = − 1+ 3cot 2( θ − 30 ° )<br />

6.<br />

1<br />

y = tan θ<br />

2<br />

π<br />

14. y = 2 + 5tan ( x − 3)<br />

8<br />

7.<br />

1<br />

y = sec θ<br />

3<br />

π<br />

15. y = 4 + 6sec ( x + 1)<br />

2<br />

8. y = 2cscθ<br />

16. − 3+ 2csc 4( θ + 10 ° )


<strong>Precalculus</strong> <strong>Worksheet</strong><br />

Section 6.8<br />

F<strong>in</strong>d the pr<strong>in</strong>cipal value to 2 decimal places for θ, or 4 decimal places for x.<br />

1.<br />

2.<br />

3.<br />

4.<br />

−<br />

θ = S<strong>in</strong><br />

1 0.195<br />

−<br />

θ = Cos<br />

1 ( − 0.2843)<br />

x = Cos −1 0.845<br />

x = S<strong>in</strong> −1 ( − 0.97)<br />

F<strong>in</strong>d the pr<strong>in</strong>cipal value to 2 decimal places for θ, or 4 decimal places for x, gett<strong>in</strong>g the general solution<br />

and the first three positive values of θ and x.<br />

5.<br />

6.<br />

7.<br />

8.<br />

9.<br />

10.<br />

11.<br />

12.<br />

θ =<br />

θ =<br />

−1<br />

cos 0.91<br />

−1<br />

s<strong>in</strong> 0.53<br />

θ = −<br />

−1<br />

cos ( 0.15)<br />

θ = −<br />

x =<br />

x =<br />

−1<br />

s<strong>in</strong> ( 0.16)<br />

−1<br />

cos 0.26<br />

−1<br />

s<strong>in</strong> 0.98<br />

x = −<br />

−1<br />

cos ( 0.11)<br />

x = −<br />

−1<br />

s<strong>in</strong> ( 0.63)<br />

F<strong>in</strong>d the exact pr<strong>in</strong>cipal value of θ and x.<br />

13. θ = Cos<br />

2<br />

−1 1 <br />

14. θ = S<strong>in</strong> − <br />

2 <br />

1 2<br />

15. x = S<strong>in</strong> <br />

− <br />

2 <br />

<br />

1 1<br />

16. x = Cos − <br />

− <br />

2 <br />

−1 3<br />

17.<br />

x = Cos −1 5 (Surprise?!)<br />

−<br />

18. θ = S<strong>in</strong><br />

1 ( − 3) (Surprise!!?)

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