Precalculus Chapter 6 Worksheet Graphing Sinusoidal Functions in ...
Precalculus Chapter 6 Worksheet Graphing Sinusoidal Functions in ...
Precalculus Chapter 6 Worksheet Graphing Sinusoidal Functions in ...
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<strong>Precalculus</strong> <strong>Chapter</strong> 6 <strong>Worksheet</strong><br />
<strong>Graph<strong>in</strong>g</strong> <strong>S<strong>in</strong>usoidal</strong> <strong>Functions</strong> <strong>in</strong> Degree Mode<br />
F<strong>in</strong>d the amplitude, period, phase (horizontal) displacement and translation (vertical displacement).<br />
Then use the <strong>in</strong>formation to f<strong>in</strong>d the critical po<strong>in</strong>ts and sketch two cycles for the graph (one to the right<br />
and one to the left of the center po<strong>in</strong>t).<br />
1. y = 7 + 4cos3( θ − 10 ° )<br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
_________<br />
_________<br />
_________<br />
_________<br />
2. y = − 10 + 20s<strong>in</strong> 2( θ + 30 ° )<br />
3.<br />
4.<br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
1<br />
y = 3− 5cos ( θ + 90 ° )<br />
2<br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
_________<br />
_________<br />
_________<br />
_________<br />
_________<br />
_________<br />
_________<br />
_________<br />
1<br />
1000 + 3000s<strong>in</strong> ( 60 )<br />
3 θ + °<br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
5. y = 11− 6s<strong>in</strong>( θ − 17 ° )<br />
_________<br />
_________<br />
_________<br />
_________<br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
_________<br />
_________<br />
_________<br />
_________
<strong>Precalculus</strong> <strong>Chapter</strong> 6 <strong>Worksheet</strong><br />
<strong>Graph<strong>in</strong>g</strong> <strong>S<strong>in</strong>usoidal</strong> <strong>Functions</strong> <strong>in</strong> Radian Mode<br />
F<strong>in</strong>d the amplitude, period, phase (horizontal) displacement and translation (vertical displacement).<br />
Then use the <strong>in</strong>formation to f<strong>in</strong>d the critical po<strong>in</strong>ts and sketch two cycles for the graph (one to the right<br />
and one to the left of the center po<strong>in</strong>t).<br />
1.<br />
2.<br />
1<br />
y = 3+ 2cos ( x − π )<br />
5<br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
_________<br />
_________<br />
_________<br />
_________<br />
2 π <br />
y = − 4 + 5s<strong>in</strong> x<br />
+ 3 2 <br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
_________<br />
_________<br />
_________<br />
_________<br />
π <br />
3. y = 2 − 6cos3x<br />
+ <br />
6 <br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
π<br />
4. 2 + 6s<strong>in</strong> ( 1)<br />
4 x −<br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
_________<br />
_________<br />
_________<br />
_________<br />
_________<br />
_________<br />
_________<br />
_________<br />
π<br />
5. y = −5 − 4s<strong>in</strong> ( x + 2)<br />
3<br />
Amplitude:<br />
Period:<br />
Phase:<br />
Translation:<br />
_________<br />
_________<br />
_________<br />
_________
<strong>Graph<strong>in</strong>g</strong> Tangent and Reciprocal <strong>Functions</strong><br />
Graph the follow<strong>in</strong>g:<br />
Assume the function is circular (use radians) if the <strong>in</strong>dependent variable is x and trigonometric (use<br />
degrees) if the <strong>in</strong>dependent variable is θ. Graph two cycle of each.<br />
1. y = tan 2θ<br />
9. y = 4 + 3tanπ<br />
x<br />
π<br />
2. y = cot x 3<br />
10. y = − 5 + 3cot 4θ<br />
π<br />
3. y = csc x 2<br />
11. y = − 6 + 2csc5θ<br />
4. y = sec3θ<br />
π<br />
12. y = 1+<br />
4sec x 10<br />
5. y = 2cot x<br />
13. y = − 1+ 3cot 2( θ − 30 ° )<br />
6.<br />
1<br />
y = tan θ<br />
2<br />
π<br />
14. y = 2 + 5tan ( x − 3)<br />
8<br />
7.<br />
1<br />
y = sec θ<br />
3<br />
π<br />
15. y = 4 + 6sec ( x + 1)<br />
2<br />
8. y = 2cscθ<br />
16. − 3+ 2csc 4( θ + 10 ° )
<strong>Precalculus</strong> <strong>Worksheet</strong><br />
Section 6.8<br />
F<strong>in</strong>d the pr<strong>in</strong>cipal value to 2 decimal places for θ, or 4 decimal places for x.<br />
1.<br />
2.<br />
3.<br />
4.<br />
−<br />
θ = S<strong>in</strong><br />
1 0.195<br />
−<br />
θ = Cos<br />
1 ( − 0.2843)<br />
x = Cos −1 0.845<br />
x = S<strong>in</strong> −1 ( − 0.97)<br />
F<strong>in</strong>d the pr<strong>in</strong>cipal value to 2 decimal places for θ, or 4 decimal places for x, gett<strong>in</strong>g the general solution<br />
and the first three positive values of θ and x.<br />
5.<br />
6.<br />
7.<br />
8.<br />
9.<br />
10.<br />
11.<br />
12.<br />
θ =<br />
θ =<br />
−1<br />
cos 0.91<br />
−1<br />
s<strong>in</strong> 0.53<br />
θ = −<br />
−1<br />
cos ( 0.15)<br />
θ = −<br />
x =<br />
x =<br />
−1<br />
s<strong>in</strong> ( 0.16)<br />
−1<br />
cos 0.26<br />
−1<br />
s<strong>in</strong> 0.98<br />
x = −<br />
−1<br />
cos ( 0.11)<br />
x = −<br />
−1<br />
s<strong>in</strong> ( 0.63)<br />
F<strong>in</strong>d the exact pr<strong>in</strong>cipal value of θ and x.<br />
13. θ = Cos<br />
2<br />
−1 1 <br />
14. θ = S<strong>in</strong> − <br />
2 <br />
1 2<br />
15. x = S<strong>in</strong> <br />
− <br />
2 <br />
<br />
1 1<br />
16. x = Cos − <br />
− <br />
2 <br />
−1 3<br />
17.<br />
x = Cos −1 5 (Surprise?!)<br />
−<br />
18. θ = S<strong>in</strong><br />
1 ( − 3) (Surprise!!?)