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Linear <strong>Momentum</strong><br />

Sunday, November 21, 2010<br />

1


Homework Problems<br />

Nolan - Honors Physics<br />

4,5,7,10,16,19<br />

22,25,28,30,<br />

33,37,40,42,<br />

51,62,63,64<br />

Sunday, November 21, 2010<br />

2


<strong>Momentum</strong><br />

P=mv<br />

m = mass (kg)<br />

v = velocity (m/s)<br />

p = <strong>Momentum</strong><br />

“the quantity of motion”<br />

kg m/s<br />

Sunday, November 21, 2010<br />

3


Vector Quantity<br />

As with velocity before, the<br />

direction can be expressed by<br />

angle, map directions, or only<br />

a positive or negative<br />

Sunday, November 21, 2010<br />

4


Conservation of<br />

<strong>Momentum</strong><br />

In a closed system, the total<br />

momentum will remain a<br />

constant<br />

Sunday, November 21, 2010<br />

5


Linear Collisions<br />

Sunday, November 21, 2010<br />

6


Perfectly Inelastic<br />

In the inelastic collision the two<br />

objects have the same final velocity<br />

Sunday, November 21, 2010<br />

7


Example<br />

Mass A : Vi = 25 m/s<br />

m = 4 kg<br />

Mass B : Vi = -30 m/s<br />

m = 6 kg<br />

Find the Final Velocity After<br />

an Inelastic Collision<br />

Sunday, November 21, 2010<br />

8


Example<br />

Mass A : Vi = 25 m/s<br />

m = 4 kg<br />

Mass B : Vi = -30 m/s<br />

m = 6 kg<br />

From Conservation of <strong>Momentum</strong><br />

4(25) + 6(-30) = 4(Vaf) + 6(Vbf)<br />

100 + -180 = 10 (Vf)<br />

-80 = 10 Vf<br />

Vf = -8 m/s<br />

Sunday, November 21, 2010<br />

9


Mass A : Vi = 10 m/s<br />

m = 5 kg<br />

Mass B : Vi = -15 m/s<br />

m = 7 kg<br />

V f = 4 m/s<br />

(5)(10) + (7)(-15) = 5(Va) + 7(4)<br />

(50) + (-105) = 5(Va) + (28)<br />

Example<br />

Sunday, November 21, 2010<br />

10


Inelastic<br />

Coefficient of<br />

Restitution<br />

Values from 0-1<br />

A ratio of:<br />

Separation Velocity<br />

divided by the<br />

Approach Velocity<br />

Sunday, November 21, 2010<br />

11


Find the Coefficient<br />

V = 5 m/s<br />

V = - 3 m/s<br />

V = -1 m/s<br />

V = 3 m/s<br />

Sunday, November 21, 2010<br />

12


Find the Coefficient<br />

V a = 5 - (-3) = 8<br />

V = 5 m/s<br />

V = - 3 m/s<br />

V = -1 m/s<br />

V = 3 m/s<br />

V s = 3 - (-1) = 4<br />

Sunday, November 21, 2010<br />

13


Coefficient of Restitution<br />

e = Vs / Va<br />

e = (V aF - V bF ) / (V bI -V 1aI )<br />

For the example: e = 0.5<br />

Sunday, November 21, 2010<br />

14


Inelastic Example<br />

An object hits a wall with<br />

a velocity of 5 m/s.<br />

e = 0.4<br />

Find the return velocity.<br />

Sunday, November 21, 2010<br />

15


Inelastic Example<br />

An object hits a wall with a<br />

velocity of 5 m/s. e = 0.4<br />

Va = 5 - 0 = 5 (as expected)<br />

Vs = .4 (5)<br />

2 m/s = 0 - Vf<br />

Vf= -2 m/s<br />

Sunday, November 21, 2010<br />

16


Perfectly Elastic<br />

In the elastic collision Kinetic<br />

Energy is conserved<br />

The coefficient of restitution<br />

is 1.0<br />

Sunday, November 21, 2010<br />

17


Example<br />

Mass A : Vi = 10 m/s<br />

m = 5 kg<br />

Mass B : Vi = -15 m/s<br />

m = 7 kg<br />

(5)(10) + (7)(-15) = 5(V a ) + 7(V b )<br />

10 - (-15) = V b - V a<br />

25+V a =V b<br />

50-105 = 5V a +7(V a )+7(25)<br />

Sunday, November 21, 2010<br />

18


Collisions in 2 Dimensions<br />

Sunday, November 21, 2010<br />

19


Car :<br />

Vi = 10 m/s, E<br />

m = 500 kg<br />

Truck :<br />

Vi = 15 m/s, N<br />

m = 900 kg<br />

Sunday, November 21, 2010<br />

20


Car :<br />

Vi = 10 m/s, E<br />

m = 500 kg<br />

Truck :<br />

Vi = 15 m/s, N<br />

m = 900 kg<br />

In the X<br />

(500)(10) = (1400)(V x )<br />

In the Y<br />

(900)(-15) = (1400)(V y )<br />

Sunday, November 21, 2010<br />

21


(V x )=3.571 m/s<br />

(V y )=9.643 m/s<br />

find the resultant velocity<br />

V= 10.28 m/s<br />

at 69.7 o 22<br />

Sunday, November 21, 2010


2 Dimension<br />

9 Ball :<br />

V i = 10 m/s<br />

m = 350 g<br />

2 Ball :<br />

V i = 0 m/s<br />

m = 300 kg<br />

Sunday, November 21, 2010<br />

23


9 Ball :<br />

V i = 8 m/s<br />

θ = 34 o<br />

9 Ball :<br />

V i = 10 m/s<br />

m = 350 g<br />

2 Ball :<br />

V i = 0 m/s<br />

m = 300 kg<br />

In the X<br />

(0.35)(10) + 0 = (0.35)(8cos34) + (0.3)(V x )<br />

In the Y<br />

0 + 0 = (0.35)(8sin34) + (0.3)(V y )<br />

Sunday, November 21, 2010<br />

24


Ballistic<br />

Pendulum<br />

Bullet :<br />

Vi = 250 m/s<br />

m = 50 g<br />

Log :<br />

Vi = 0 m/s<br />

m = 1.0 kg<br />

FIND THE<br />

FINAL HEIGHT<br />

Sunday, November 21, 2010<br />

25


Bullet :<br />

Vi = 250 m/s<br />

m = 50 g<br />

V i » V f » KE» PE<br />

Log :<br />

Vi = 0 m/s<br />

m = 1.0 kg<br />

0.05(250) = 1.05(V f )<br />

V f = 11.9 m/s<br />

KE = .5(1.05)(11.9 2 ) = 74.4 J<br />

PE=74.4J=(1.05)(9.8)(H)<br />

H=7.23m<br />

Sunday, November 21, 2010<br />

26


Impulse<br />

J= F t<br />

J (Impulse Ns)<br />

F (Force N)<br />

t (time s)<br />

Sunday, November 21, 2010<br />

27

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