Kinematics/Newton's Laws - The Burns Home Page
Kinematics/Newton's Laws - The Burns Home Page
Kinematics/Newton's Laws - The Burns Home Page
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9/3/2009<br />
Understanding<br />
A cannonball is shot with an initial speed of 50 m/s at a launch angle of 40 0<br />
toward a castle wall 220m away. <strong>The</strong> height of the wall is 30 m. Assume that<br />
effects due to the air are negligible.<br />
(a) Show that the cannonball will strike the wall.<br />
(b) How long will it take for the cannonball to strike the wall?<br />
(c) At what height above the base of the wall will the cannonball strike?<br />
Understanding<br />
A cannonball is shot with an initial speed of 50 m/s at a launch angle of 40 0<br />
toward a castle wall 220m away. <strong>The</strong> height of the wall is 30 m. Assume that<br />
effects due to the air are negligible.<br />
(a) Show that the cannonball will strike the wall.<br />
1 2<br />
x v0<br />
xt<br />
y v0<br />
yt gt<br />
2<br />
x<br />
2<br />
t <br />
x 1 x <br />
v<br />
v0<br />
sin<br />
<br />
2<br />
0x<br />
g<br />
v0cos<br />
<br />
<br />
2 v0cos<br />
<br />
<br />
<br />
x<br />
2<br />
<br />
gx<br />
v cos x tan <br />
<br />
2 2<br />
0 <br />
<br />
2v0<br />
cos <br />
<br />
m <br />
2<br />
9.8 2 220m<br />
s<br />
220m tan 40<br />
<br />
<br />
2<br />
m 2<br />
250 cos 40<br />
s <br />
23m<br />
v 2<br />
sin 0 2 <br />
R <br />
g<br />
m <br />
50 sin 240<br />
s<br />
R <br />
<br />
m <br />
9.8<br />
2 <br />
s <br />
251m<br />
We need now only show that the<br />
height of the ball is below 30 m<br />
when the horizontal displacement<br />
is 220m<br />
This is less than 30 m, so contact<br />
Understanding<br />
A cannonball is shot with an initial speed of 50 m/s at a launch angle of 40 0<br />
toward a castle wall 220m away. <strong>The</strong> height of the wall is 30 m. Assume that<br />
effects due to the air are negligible.<br />
b) How long will it take for the cannonball to strike the wall?<br />
x<br />
t <br />
v<br />
0x<br />
x<br />
<br />
v cos 0<br />
<br />
<br />
220m<br />
m <br />
50 cos40<br />
s <br />
5.7s<br />
<br />
Understanding<br />
A cannonball is shot with an initial speed of 50 m/s at a launch angle of 40 0<br />
toward a castle wall 220m away. <strong>The</strong> height of the wall is 30 m. Assume that<br />
effects due to the air are negligible.<br />
c) At what height above the base of the wall will the cannonball strike?<br />
From (a) we have 23 m<br />
5