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Structure and detection of Kelvin-Helmholtz vortices in the ... - GPSM

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How can <strong>the</strong> secondary velocity shear be<br />

produced<br />

v<br />

1<br />

2<br />

1<br />

M<br />

1v<br />

r<br />

⎧<br />

⎪v1<br />

=<br />

⎪<br />

⎨<br />

⎪<br />

⎪<br />

v2<br />

=<br />

⎩<br />

∴<br />

− v<br />

2<br />

M<br />

2v2<br />

= = ≅<br />

a r<br />

M<br />

M<br />

2<br />

1<br />

a r<br />

2<br />

r<br />

= a r<br />

a<br />

1<br />

M<br />

1<br />

leads to,<br />

1<br />

−<br />

M<br />

2<br />

r<br />

=<br />

M1<br />

a r<br />

M<br />

1<br />

v2<br />

M2<br />

v1<br />

1−<br />

M<br />

M<br />

1<br />

2<br />

⎛ ∆ VSEC<br />

∝ rSEC<br />

⎜1<br />

− 1<br />

⎝ N<br />

RATIO<br />

r SEC = curvature radius <strong>of</strong> <strong>the</strong><br />

2nd velocity shear layer<br />

⎞<br />

⎟<br />

⎠<br />

At a certa<strong>in</strong> radial distance from <strong>the</strong> vortex center, <strong>the</strong> centrifugal<br />

force exert<strong>in</strong>g on <strong>the</strong> lighter <strong>and</strong> heavier fluids must be equal.<br />

↓<br />

Then, <strong>the</strong> shear velocity depends on <strong>the</strong> mass ratio <strong>and</strong> on <strong>the</strong><br />

curvature radius <strong>of</strong> <strong>the</strong> shear layer.

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