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Accuracy assessment methods and current challenges

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e.g. common scenario v another accuracy<br />

n′<br />

=<br />

( z<br />

+<br />

2<br />

α / 2<br />

2PQ<br />

z<br />

β<br />

P1<br />

Q1<br />

P2<br />

Q2<br />

)<br />

( P − P ) 2<br />

2<br />

1<br />

+<br />

<strong>and</strong> with continuity correction:<br />

n<br />

=<br />

n′<br />

⎛<br />

⎜1+<br />

1+<br />

4<br />

n′<br />

p<br />

p<br />

4 ⎟ ⎝<br />

2<br />

−<br />

1 ⎠<br />

⎞<br />

2<br />

Use acquired data to test for difference using:<br />

z<br />

=<br />

P<br />

1<br />

− P<br />

2<br />

−<br />

1<br />

2<br />

(<br />

1<br />

n<br />

+<br />

⎛ 1<br />

p(1<br />

− p)<br />

⎜ +<br />

⎝ n1<br />

1<br />

1<br />

n<br />

2<br />

1<br />

n<br />

2<br />

)<br />

⎞<br />

⎟<br />

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