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7.2 Reducing Rational Functions

7.2 Reducing Rational Functions

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624 Chapter 7 <strong>Rational</strong> <strong>Functions</strong><br />

Similarly, if we insert x = 4 in the left-hand side of equation (15),<br />

2x − 6<br />

x 2 − 7x + 12 = 2(4) − 6<br />

(4) 2 − 7(4) + 12 = 2 0 .<br />

Again, division by zero is undefined. The left-hand side of equation (15) is undefined<br />

if x = 4, so the result in equation (15) is not valid if x = 4. Note that the right-hand<br />

side of equation (15) is also undefined at x = 4.<br />

However, the algebraic work we did above guarantees that the left-hand side of<br />

equation (15) will be identical to the right-hand side of equation (15) for all other<br />

values of x. For example, if we substitute x = 5 into the left-hand side of equation (15),<br />

2x − 6<br />

x 2 − 7x + 12 = 2(5) − 6<br />

(5) 2 − 7(5) + 12 = 4 2 = 2.<br />

On the other hand, if we substitute x = 5 into the right-hand side of equation (15),<br />

2<br />

x − 4 = 2<br />

5 − 4 = 2.<br />

Hence, both sides of equation (15) are identical when x = 5. In a similar manner, we<br />

could check the validity of the identity in equation (15) for all other values of x.<br />

You can use the graphing calculator to verify the identity in equation (15). Load<br />

the left- and right-hand sides of equation (15) in Y= menu, as shown in Figure 1(a).<br />

Press 2nd TBLSET and adjust settings as shown in Figure 1(b). Be sure that you<br />

highlight AUTO for both independent and dependent variables and press ENTER on each<br />

to make the selection permanent. In Figure 1(b), note that we’ve set TblStart = 0<br />

and ∆Tbl = 1. Press 2nd TABLE to produce the tabular results shown in Figure 1(c).<br />

(a) (b) (c)<br />

Figure 1. Using the graphing calculator to check that the left- and right-hand sides of<br />

equation (15) are identical.<br />

Remember that we placed the left- and right-hand sides of equation (15) in Y1 and<br />

Y2, respectively.<br />

• In the tabular results of Figure 1(c), note the ERR (error) message in Y1 when<br />

x = 3 and x = 4. This agrees with our findings above, where the left-hand side of<br />

equation (15) was undefined because of the presence of zero in the denominator<br />

when x = 3 or x = 4.<br />

• In the tabular results of Figure 1(c), note that the value of Y1 and Y2 agree for all<br />

other values of x.<br />

Version: Fall 2007

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