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1 Transposon and T-DNA mutagenesis

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Protocol 1. Continued<br />

2. Follow segregation of the phenotype in the progeny <strong>and</strong> screen for<br />

presence of the transposase locus (e.g. by selecting for antibiotic<br />

resistance) (see Chapter 1 for growing Arabidopsis under selective<br />

conditions). If the mutant contains the transposase locus, screen<br />

100-1000 progeny for wild-type looking revertants to test the stability<br />

of the mutant phenotype.<br />

3. If the mutant does not contain a transposase locus, screen siblings to<br />

find a family expressing transposase. When found, screen the progeny<br />

as in step 2. Alternatively screen the F, from cross 2 for families with<br />

transposase. When found, screen progeny as in step 2. Only proceed<br />

when revertants are found.<br />

4. Identify a transposon insertion co-segregating with the mutation.<br />

Preferably use a population without transposase (e.g. F2 from cross I),<br />

segregating 3:l for wild-type:mutant. Alternatively, use a population<br />

with transposase, such as the F2 from cross 2, or revertant <strong>and</strong> mutant<br />

progeny of the original mutant when the mutant contained the transposase<br />

locus. Perform a Southern blot analysis on about 50 plants for<br />

an I element tagged mutant (multiple inserts), or on about 10 plants<br />

(half mutant, half wild-type revertant) for a Ds tagged mutant (single<br />

or a few inserts). Load equal amounts of <strong>DNA</strong> per lane to distinguish<br />

between homozygous <strong>and</strong> hemizygous inserts. Make use of other<br />

populations if no co-segregating transposon can be identified.<br />

5. Isolate genomic <strong>DNA</strong> flanking the co-segregating transposable element<br />

by IPCR (Protocol 2) using preferably <strong>DNA</strong> template from a plant<br />

lacking the transposase locus <strong>and</strong> carrying less than five copies of<br />

transposon inserts (especially for I element-induced mutants). If no<br />

plants with less than five inserts was found, use a backcross of the<br />

mutant with wild-type (F, cross 1 x wild-type). to reduce the<br />

transposon copy number.<br />

6. Confirm the cloning of genomic <strong>DNA</strong> flanking the transposon by:<br />

(a) Hybridizing the IPCR probe to a Southern blot containing <strong>DNA</strong><br />

from mutant <strong>and</strong> revertant plants, to reveal homozygous inserts in<br />

mutant <strong>and</strong> hemizygous or no inserts in revertant plants.<br />

(b) Analysis of the insertion site. Determine the sequence of <strong>DNA</strong><br />

fragments carrying genomic <strong>DNA</strong> flanking the transposon insert<br />

using the IPCR fragments as template. Design PCR primers for the<br />

amplification of the insertional target site from wild-type <strong>DNA</strong>.<br />

PCR amplify the target site sequences from wild-type, revertant,<br />

<strong>and</strong> mutant alleles without inserts. Clone the PCR products <strong>and</strong><br />

determine their <strong>DNA</strong> sequence. All revertants should have at least<br />

one allele with (near) wild-type <strong>DNA</strong> sequence. All mutants should<br />

have only alleles featuring frameshifts, aberrant termination, or<br />

amino acid exchanges.<br />

7. Isolate genomic <strong>and</strong> c<strong>DNA</strong> clones from appropriate A phage libraries<br />

using the IPCR products as probes, <strong>and</strong> determine their <strong>DNA</strong> sequence.<br />

Homozygous mutant plants may not always contain a transposon insert in<br />

both mutant alleles. Occasionally, one of the inserts may transpose <strong>and</strong> leave<br />

an excision footprint behind, thus generating a stable mutant allele. When<br />

transposon insertions occur in coding regions, this is rather a rule than<br />

exception. Upon insertion, both Ds <strong>and</strong> I element generate a target site<br />

duplication of 8 bp <strong>and</strong> 3 bp respectively. Excision of these elements often<br />

deletes or duplicates a few base pairs leading to a frameshift or gen'erating a<br />

stop codon. An adequate proof for cloning the correct gene can therefore be<br />

obtained by correlating the sequence of excision alleles with the plant<br />

phenotype. Revertant plants should have at least one allele for encoding a<br />

wild-type-like protein, whereas both alleles of a mutant should display an<br />

aberrant reading frame.<br />

0<br />

I 1<br />

Protocol 2.<br />

Equipment <strong>and</strong> reagents<br />

Isolation of <strong>DNA</strong> probes flanking /element inserts in<br />

Arabidopsis thaliana by IPCR<br />

Eppendorf tubes<br />

Liauid nitroaen<br />

1 ~obendorf-;ha~ed . . . arinders -<br />

14'C, 37°C. 65'C incubator<br />

Thermocycler<br />

<strong>DNA</strong> extraction buffer: 0.3 M NaCI, 50 mM<br />

~~i~ p~ 7.5, z0 m~ EDTA, 2% ( ,I<br />

. TE: 10 mM Tris-HCI, 1 mM EDTA pH 8<br />

. DNase-free RNase A (10 mg/ml stock)<br />

. Enzymes: Hinfl, <strong>DNA</strong> polymerase I Klenow I<br />

fragment, Sail<br />

Spermidine (Sigma): prepare a 100 mM<br />

stock, store at -20°C<br />

2.5 mM dNTPs (2.5 mM each dNTP)<br />

sarkosyl, 0.5% (w/v) SDS, 5 M urea, 5% (vk) 0.3 sodium acetate pH 5.5<br />

phenol (eguilibrated) (52); the first five T4 <strong>DNA</strong> ligase<br />

ingredients' are mixed as a 2 X stock<br />

0.45 M NaCl<br />

solution, <strong>and</strong> urea <strong>and</strong> phenol are added . T , <strong>DNA</strong> ~ polymerase<br />

before use<br />

10 x PCR buffer<br />

Phenol (saturated):chloroform (1:1)<br />

10 x TBE: 108 g Tris base, 55 g boric acid,<br />

100%. 70% (vh) ethanol 9.3 g Na,EDTA per litre<br />

lsopropanol<br />

1.2% (wh) agarose (electrophoresis grade)<br />

Primers:<br />

in 0.5 X TBE<br />

1st PCR lLJl (120 ng/~I) GAA TIT AGG GAT CCA 7TC ATA AGA GTG T<br />

lRJl(120 ng/pl) lTG TGT CGA CAT GGA GGC TTC CCA TCC GGG GA<br />

2nd PCR lLJ2 (120 nylpl) A T AAA AGC CTC GAG TTC ATC GGG A<br />

IRJ2 (120 ng/pl) AGG TAG TCG ACT GAT GTG CGC GC<br />

3rd PCR ITlR (105 ng/kl) GAC ACT CCT TAG ATC TtT TCT TGT AGT G<br />

A. lsolation of <strong>DNA</strong> from a single plant (52ja (especially for I elements)<br />

1. Harvest 100-150 mg of leaf or preferably inflorescence tissue per plant<br />

in an Eppendorf tube. Freeze in liquid N2.

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