Vol. 10 No 7 - Pi Mu Epsilon
Vol. 10 No 7 - Pi Mu Epsilon
Vol. 10 No 7 - Pi Mu Epsilon
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546 PI MU EPSILON JOURNAL<br />
F d< > = g.c.d.(F ,F )<br />
g.c. m.n m n<br />
with n = 5d and I ~ m < 5d we see that Fm cannot be diYisible by 5d.<br />
To prove that the order of the multiplier m inZy~ is 4, consider the identity<br />
F n + 1 F n -1 - F: = ( -l)n .<br />
We have proved that 5d I F d, 5<br />
and it follows that 5 d I F<br />
2 .~d· <strong>No</strong>w use the<br />
identity. with n = 2 · 5d, and notice that m 2 = F . d_ 2 5 1<br />
= F . 2 5<br />
d+ . 1<br />
It follo\vs that<br />
so<br />
m 2 ~ ± l(mod5d)<br />
To show that the order of m is 4, we must prove that the sign is -1.<br />
Remember that the order ofm is Z 5 is 4, and consider the exact sequence<br />
0 (5)Z 5 a - -+ Z 5 a --+ Z~ - -+ 0<br />
The definition of the multiplier involves only additions and multiplications,<br />
and so the multiplier is preserved by the maps in this sequence. Since the order<br />
of the multiplier in z5 is 4' it must be 4 in z5d. This completes the proof<br />
<strong>No</strong>w suppose that d ~ 3. Then<br />
A(lOd) = l.c.m.(A(2d),A(5d)) = l.c.m.(3·2d-I,4·5d)=l5·<strong>10</strong>d- 1<br />
Finally let us remark that checking this formula for small values of d makes<br />
an excellent computer exercise.<br />
References<br />
1. Carmichael, R. D. , On the numerical factors of the arithmetic forms of