Answers to all pages - Hodder Plus Home
Answers to all pages - Hodder Plus Home
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Model answers<br />
4 (a)<br />
y<br />
5<br />
4<br />
3<br />
2<br />
1<br />
– 5<br />
– 4<br />
– 3 – O<br />
2 – 1 1 2 3 4 5<br />
x<br />
– 1<br />
– 2<br />
– 3<br />
– 4<br />
– 5<br />
(b) 2·5<br />
5 (a) ( – 2, – 1) in table<br />
y<br />
10<br />
– – 2<br />
–<br />
3 1<br />
O<br />
1 2 3<br />
– 10<br />
x<br />
(b) – 2 <strong>to</strong> – 1·7, – 0·4 <strong>to</strong> – 0·2, 2·0 <strong>to</strong> 2·2<br />
(c) y = 2x + 2 drawn,<br />
– 2·3 <strong>to</strong> – 2·0, – 0·6 <strong>to</strong> – 0·3, 2·5 <strong>to</strong> 2·8<br />
6 Manipulate x 3 – 2x – 1 = 0 <strong>to</strong> give x 3 = 2x + 1.<br />
The line <strong>to</strong> draw is y = 2x + 1.<br />
y<br />
8<br />
4<br />
y = 2x + 1<br />
– 2 – 1 O<br />
1 2<br />
– 4<br />
x<br />
y = x 3<br />
– 8<br />
The solution is where the line cuts the curve.<br />
x = – 1, – 0·6 or 1·6<br />
IGCSE Revision Guide for Mathematics Model <strong>Answers</strong> © 2004, <strong>Hodder</strong> & S<strong>to</strong>ugh<strong>to</strong>n Educational<br />
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