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Cubic Surfaces Jaap Top - Wiskunde

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Easy: every v ≠ 0 in BCH(m) has at least 5 coordinates 1.<br />

How many v have precisely 5 coordinates 1<br />

Idea: if x 1 , x 2 , x 3 , x 4 , x 5 ∈ F 2 m are the powers of α which give v,<br />

then<br />

{<br />

x1 + x 2 + x 3 + x 4 + x 5 = 0<br />

x 3 1 + x3 2 + x3 3 + x3 4 + x3 5 = 0.<br />

So the problem boils down to: count the points with coordinates<br />

in F 2 m on the projective surface S defined here.<br />

4

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