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Kater’s <strong>Reversible</strong> <strong>Pendulum</strong><br />

<strong>Advanced</strong> <strong>Lab</strong><br />

Seth Hopper<br />

December 8, 2003<br />

Abstract<br />

I measured the local acceleration due to gravity using Kater’s <strong>Reversible</strong> <strong>Pendulum</strong>. The<br />

pendulum could be suspended in two positions, and when the periods of the two positions were<br />

equal, the setup allowed for a simple measurement of g. I calculated g within 0.1% of the<br />

accepted value for Richmond, IN.<br />

Contents<br />

1


1 Introduction<br />

The local acceleration due to gravity is perhaps the most commonly used constant in all physics<br />

calculations. It can be measured many different ways, some with more accuracy than others. The<br />

method I used in this lab involved a reversible pendulum, developed by Kater in 1817.<br />

Kater’s reversible pendulum is a physical pendulum with movable masses on either end, as<br />

depicted in Figure<br />

2 Theory<br />

In order to motivate the use of the reversible pendulum, we consider the scenario depicted in Figure<br />

2. We assume that the masses M 1 and M 2 have been positioned as to make the periods of the two<br />

Figure 1:<br />

orientations of the pendulum equal. Here the physical pendulum is suspended from a knife edge<br />

at point P 1 . The center of mass is at point C, and the distance between these two points is, as<br />

displayed, h 1 . Let the total mass of the pendulum be M and the moment of inertia about point P 1<br />

2


e I P1 . Then, the torque on the pendulum from gravity is<br />

τ = I P1<br />

d 2 θ<br />

dt 2 = −Mgh 1 sin(θ). (1)<br />

For our purposes, let us only consider cases when θ is small; then we can make the approximation<br />

sin(θ) = θ. Then the period for this physical pendulum becomes<br />

√<br />

I P1<br />

T = 2π . (2)<br />

Mgh 1<br />

Now, we recognize that from the parallel axis theorem that<br />

I P1 = I C + Mh 2 1 (3)<br />

where I C , is the moment of inertia about the center of mass of the pendulum. At this point we<br />

define the radius of gyration k of the pendulum about C to be<br />

k = √ I C /M. (4)<br />

Hence, Equation<br />

. We assume that the masses M 1 and M 2 have been positioned as to make the periods of the<br />

two orientations of the pendulum equal. Here the physical pendulum is suspended from a knife<br />

edge at point P 1 . The center of mass is at point C, and the distance between these two points is,<br />

as displayed, h 1 . Let the total mass of the pendulum be M and the moment of inertia about point<br />

P 1 be I P1 . Then, the torque on the pendulum from gravity is<br />

τ = I P1<br />

d 2 θ<br />

dt 2 = −Mgh 1 sin(θ). (5)<br />

For our purposes, let us only consider cases when θ is small; then we can make the approximation<br />

3


Figure 2:<br />

sin(θ) = θ. Then the period for this physical pendulum becomes<br />

√<br />

I P1<br />

T = 2π . (6)<br />

Mgh 1<br />

Now, we recognize that from the parallel axis theorem that<br />

I P1 = I C + Mh 2 1 (7)<br />

where I C , is the moment of inertia about the center of mass of the pendulum. At this point we<br />

define the radius of gyration k of the pendulum about C to be<br />

k = √ I C /M. (8)<br />

Hence, Equation<br />

4


3 Procedure<br />

The key to measuring the acceleration due to gravity with Kater’s reversible pendulum is finding<br />

a positioning where the period is identical when the pendulum is flipped vertically and suspended<br />

from the other knife edge. In finding this position, I used the following equipment.<br />

3.1 Equipment<br />

1. EM-12 Kater’s <strong>Reversible</strong> <strong>Pendulum</strong> with stable wall mount<br />

2. PASCO Scientific Photogate<br />

3. Apple <strong>Computer</strong> running Science Workshop<br />

4. <strong>Lab</strong> Jack Adjustable Stand<br />

5. 2 Meter Stick<br />

6. Calipers<br />

7. Straight Blade Screwdriver<br />

3.2 In General<br />

I set up the equipment as shown in Figure<br />

Figure 3:<br />

The equipment setup for measuring periods of the Kater pendulum.<br />

5


There are many different orientations that will yield equal upright and inverted periods for the<br />

Kater pendulum. In fact, for every position of M 1 there is one position of M 2 where the periods will<br />

be identical. I placed M 1 at one position and moved M 2 , making measurements every 5 cm until<br />

the periods were equal. Then I took more accurate measurements of the position of M 2 , moving it<br />

only 2 cm at a time in the range where I found the periods to be equal.<br />

3.3 The Specifics<br />

I hung the pendulum from the wall mount with M 1 at the top. Using the adjustable stand, I placed<br />

the photogate directly underneath the bottom of the pendulum so that when the pendulum was at<br />

its minimum it blocked the signal between the two sensors of the photogate. When the pendulum<br />

would oscillate the photogate would report every time the signal was interrupted, which was every<br />

half period. These signals were sent to the computer running Science Workshop software, which<br />

measured the time intervals between interrupts. These intervals were displayed on the screen, and<br />

I observed them for many different positions of M 1 2 .<br />

I started M 2 78 cm from the bottom of the pendulum (as oriented in Figure<br />

4 Results and Conclusions<br />

The following graphs display the periods of the Kater reversible pendulum in both orientations as<br />

a function of the position of M 2 . The intersection of the lines indicates the position where the<br />

periods for the different orientations of the pendulum are equal. The second graph is basically a<br />

zoom of the first graph, and I see that the intersection occurs at 2.006 s.<br />

The formula for g comes<br />

from Equation<br />

How accurate is this Well, a formula for the local acceleration due to gravity is as follows.<br />

g = 9.780 318 4(1 + 0.005 302 4 sin 2 L − 0.000 005 9 sin 2 2L) − 3.086 × 10 −6 H (9)<br />

Here L is the latitude and H is the height above sea level. For Richmond, IN the latitude is 39.83 ◦<br />

1 The computer actually displayed whole periods, not half periods, so it only output data every other signal<br />

interrupt.<br />

6


2.06<br />

2.04<br />

2.02<br />

”Up”<br />

”Down”<br />

2<br />

1.98<br />

Period (s)<br />

1.96<br />

1.94<br />

1.92<br />

1.9<br />

1.88<br />

1.86<br />

0<br />

0.1<br />

0.2<br />

0.3 0.4 0.5<br />

M2 Position (cm)<br />

0.6<br />

0.7<br />

0.8<br />

2.06<br />

2.05<br />

”Up Zoom”<br />

”Down Zoom”<br />

2.04<br />

Period (s)<br />

2.03<br />

2.02<br />

2.01<br />

2<br />

0<br />

0.02<br />

0.04<br />

0.06 0.08 0.1<br />

M2 Position (cm)<br />

0.12<br />

0.14<br />

0.16<br />

and the elevation is 286.2 m. Hence, the local acceleration due to gravity should be<br />

g = 9.780 318 4(1 + 0.005 302 4 sin 2 (39.83) − (10)<br />

5.9 × 10 −6 sin 2 (2 · 39.83)) − 3.086 × 10 −6 · 286.2<br />

7


g = 9.801 m/s 2 . (11)<br />

The acceptable range for my result is<br />

9.637 m/s 2 ≤ g ≤ 9.985 m/s 2 . (12)<br />

Clearly the accepted value for g falls well within this range. In fact, my result is barely .1% off<br />

from the accepted value. Perhaps my range of uncertainty is too large. However, I do believe that<br />

the uncertainty in H is accurate. It would not surprise me, on the other hand, if the uncertainty<br />

in T were smaller than I estimated.<br />

In conclusion, I conclude that the data I took from the reversible Kater pendulum gave conclusive<br />

results that concur with those taken by other people in this world. The possible reasons for<br />

differences between my results and the accepted values include that my elevation and latitude are<br />

probably not exactly what I found by searching on the Internet. Also, there could be local mineral<br />

deposits that could alter the local value of g from what would be accepted. I ignored any friction,<br />

and also made the approximation that sin(θ) = θ, but I doubt if either of these played a role in<br />

any inaccuracies. If I had to guess, and I do, I think the uncertainties in T and H were mostly<br />

responsible for the majority of my discrepancy.<br />

8

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