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Y:\How to solve 2 dimension relative velocity problems.wpd

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6. The math, with vec<strong>to</strong>r addition there are many options and these are classified by<br />

graphical and analytical means. In this tu<strong>to</strong>rial we will concentrate on the most efficient<br />

analytical means. When adding two vec<strong>to</strong>rs the Law of Sines and Cosines is probably<br />

best. However, the component method is easier <strong>to</strong> visualize. I will show both solutions<br />

for each problem.<br />

i. Practice 1: A large panel van has a <strong>velocity</strong> of<br />

30 m/s at 20° S of E in still air. A gust of<br />

wind of 20 m/s due East <strong>relative</strong> <strong>to</strong> the Earth<br />

strikes the van. What is the resultant <strong>velocity</strong><br />

of the van <strong>relative</strong> <strong>to</strong> the Earth, during the<br />

gust<br />

(1) Component method.<br />

Vec<strong>to</strong>r (v) and angle (2)<br />

X-comp<br />

v x = vcos2<br />

Y-comp<br />

v y = vsin2<br />

V va = 30 m/s, 20° V vax = 28.19 V vay = -10.26<br />

V vE = 20 m/s, 0° V vax = 20 V vEy = 0<br />

Resultant V vEx = 48.19 V vEy = -10.26<br />

Note using your diagram, YOU determine is a component is positive or negative.<br />

2 2 2 2<br />

vE vEx vEy<br />

v = v + v = 48.19 + ( − 10.26) = 49.3<br />

v −10.26<br />

θ = = = °<br />

v<br />

48.19<br />

−1 vEy −1<br />

tan ( ) tan ( ) 12.0 S of E<br />

vEx<br />

2 2<br />

vE<br />

=<br />

va<br />

+<br />

aE<br />

−<br />

va aE<br />

2 2<br />

30 20 2(30)(20)cos160 49.2<br />

m s<br />

m s<br />

v v v 2( v )( v )cosθ<br />

v<br />

vE<br />

= + − =<br />

−1 vaE<br />

sinθ<br />

−1<br />

20sin160<br />

β = sin ( ) = sin ( ) = 8.0°<br />

v<br />

49.2<br />

vE<br />

α = 20°− β = 12.0°<br />

(2) Law of sines and cosines

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