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Vol. 10 No 6 - Pi Mu Epsilon

Vol. 10 No 6 - Pi Mu Epsilon

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478 PI <strong>Mu</strong> EPSILON JOURNAL<br />

A VISUAL REPRESENTATION OF THE SEQUENCE SPACE<br />

479<br />

= Y" doo (tt- 1 (pj_ 1<br />

) , tt- 1 (pj) )<br />

/':'1<br />

Since x- 1 (pj_ 1<br />

) and x- 1 (pj) differ by only one digit in ~th place, (where ~<br />

is the index of the j th term in which a differs from 't) we have<br />

ct-cx- 1 (pj_ 1<br />

), x- 1 (pj)) = 4- so<br />

2 J<br />

..,<br />

.. ~<br />

..<br />

=~<br />

= d..,(a,'t). 0<br />

Thus, (P, d,) is a geometric model of the sequence space.<br />

a u a<br />

• • • •<br />

2<br />

(a.)<br />

Figure 6<br />

(b.)<br />

p<br />

•<br />

I<br />

- 2<br />

u<br />

•<br />

Additional Theorems<br />

We close by proving some of the claims stated in the introduction.<br />

Theorem 4.1. There does not exist an isometric embedding from<br />

(E , d..,) into (Jln, ds> where d• denotes the Euclidean metric,<br />

ds(x,y) = lx- yj.<br />

Proof. Since (1: , dz) can be considered to be a subspace of<br />

(!:,d .. ) it suffices to show that 1: does not embed isometrically into<br />

lln. Suppose k : Lz - Jln is an isometric bijection. Then<br />

dz (u, 13> = jk(u) - k I for any u, 13 E 1: . Consider the points:<br />

a = k(OO)<br />

't = 1t(01)<br />

p = x(<strong>10</strong>)<br />

v = k(ll)<br />

Ia - -rl = d 2 (00, 01)<br />

lor- vi= dz(01,ll)<br />

Ia- vi= dz(OO,ll)<br />

1<br />

- 2<br />

= 1<br />

3<br />

- 2<br />

Thus a,

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