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knowledge, science, and the universe chapter 1 - Physical Science ...

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SECTION 3–3 Weight <strong>and</strong> Acceleration 31<br />

15 m/sec<br />

0 m/sec 15 m/sec<br />

9.8 m/sec<br />

9.8 m/sec<br />

15 m/sec<br />

19.6 m/sec<br />

19.6 m/sec<br />

15 m/sec<br />

29.4 m/sec<br />

29.4 m/sec<br />

15 m/sec<br />

39.2 m/sec<br />

39.2 m/sec<br />

figure 3.3<br />

The green ball is thrown to <strong>the</strong> right at 15 m/sec at <strong>the</strong> same<br />

time <strong>the</strong> blue ball is dropped. However, both will hit <strong>the</strong><br />

ground at <strong>the</strong> same time because <strong>the</strong> acceleration of all<br />

falling bodies is <strong>the</strong> same regardless of <strong>the</strong>ir initial velocities.<br />

instead of vertically, with an initial speed of 15<br />

m/sec, as indicated in Figure 3.3. This time it<br />

follows a curved path as it falls. Curved motion<br />

appears more complicated, but can be simplified<br />

by separating <strong>the</strong> path of <strong>the</strong> ball into horizontal<br />

<strong>and</strong> vertical parts. At <strong>the</strong> end of <strong>the</strong> first<br />

second, <strong>the</strong> ball is still moving horizontally with<br />

a speed of 15 m/sec, but in addition it is falling<br />

with a vertical speed of 9.8 m/sec downward.<br />

After ano<strong>the</strong>r second, <strong>the</strong> downward speed has<br />

increased to 19.6 m/sec, while <strong>the</strong> horizontal<br />

motion remains unchanged. As things progress<br />

<strong>the</strong> horizontal part of <strong>the</strong> motion never changes,<br />

while <strong>the</strong> downward velocity continues to<br />

increase at <strong>the</strong> rate of 9.8 m/sec every second<br />

because <strong>the</strong> force of gravity pulls only in that<br />

direction. This change in <strong>the</strong> downward speed<br />

of <strong>the</strong> ball is <strong>the</strong> same as if <strong>the</strong> ball had no initial<br />

motion at all. It may not be obvious, but<br />

two balls positioned at <strong>the</strong> same height, with<br />

one dropped at <strong>the</strong> same instant as <strong>the</strong> second<br />

ball is thrown horizontally, will hit <strong>the</strong> ground<br />

at <strong>the</strong> same time because <strong>the</strong> downward acceleration<br />

on both is <strong>the</strong> same.<br />

In all three examples—dropping a rock,<br />

throwing a ball into <strong>the</strong> air, <strong>and</strong> throwing a ball<br />

horizontally—<strong>the</strong> initial velocities are all different<br />

but <strong>the</strong> accelerations, <strong>and</strong> <strong>the</strong>refore <strong>the</strong><br />

way <strong>the</strong> velocities change, are all <strong>the</strong> same.<br />

3–3 wEIGhT ANd<br />

ACCELERATION<br />

Now suppose you were to drop both a<br />

basketball- sized boulder <strong>and</strong> a baseball- sized<br />

rock from <strong>the</strong> same height. You might expect<br />

<strong>the</strong> boulder to drop more rapidly than <strong>the</strong> rock,<br />

because it is much heavier. But upon dropping<br />

<strong>the</strong> two rocks you find that, despite <strong>the</strong>ir great<br />

difference in size <strong>and</strong> weight, <strong>the</strong>ir accelerations<br />

are exactly <strong>the</strong> same. Their weights do not affect<br />

how <strong>the</strong>y accelerate!<br />

Look again at Newton’s Second Law of<br />

Motion. The large boulder has greater mass<br />

than <strong>the</strong> smaller rock so it is harder to accelerate.<br />

Yet <strong>the</strong>y both accelerate at <strong>the</strong> same rate so<br />

<strong>the</strong> force on <strong>the</strong> boulder has to be greater than <strong>the</strong><br />

force on <strong>the</strong> rock.<br />

You are familiar with this, of course. More<br />

massive things weigh more <strong>and</strong> weight just<br />

refers to <strong>the</strong> force of gravity on an object.<br />

Weight <strong>and</strong> mass are exactly proportional, with<br />

<strong>the</strong> proportionality factor being <strong>the</strong> acceleration<br />

g. If “w” is weight, Newton’s second law<br />

for this case is simply<br />

w = mg<br />

which clearly expresses <strong>the</strong> proportionality. So<br />

weight<br />

The force of gravity on an<br />

object.

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