02.02.2015 Views

calculations on some sequence spaces - European Mathematical ...

calculations on some sequence spaces - European Mathematical ...

calculations on some sequence spaces - European Mathematical ...

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

1666 BRUNO DE MALAFOSSE<br />

Remark 3.2.<br />

If we define<br />

[<br />

A1 ,A 2<br />

]<br />

0 = { X ∈ s | A 1 (λ) (∣ ∣ A2 (µ)X ∣ ∣ ) ∈ s ◦ α}<br />

, (3.18)<br />

we get the same results as in Theorem 3.1, replacing in each case (i), (ii), (iii), and (iv) s ξ<br />

by s ◦ ξ .<br />

3.2. Sets [∆,∆ + ], [∆,C + ], [C,∆ + ], [∆ + ∆], [∆ + ,C], [∆ + ∆ + ], [C + ,C], [C + ,∆], [C + ,∆ + ],<br />

and [C + ,C + ]. We get immediately from the definiti<strong>on</strong>s of the operators ∆(ξ), ∆ + (η),<br />

C(ξ), and C + (η), the following:<br />

[<br />

∆,∆<br />

+ ] = { ∣ ∣ ∣ ∣<br />

X | λ ∣µn n x n −µ n+1 x ∣−λn−1∣µn−1 n+1 x n−1 −µ n x n = αn O(1) } ,<br />

⎧<br />

∣ ∣ ∣ ⎫<br />

[<br />

∆,C<br />

+ ] ⎨<br />

=<br />

⎩ X | λ ∞∑ ∣∣∣∣∣ ∣∣∣∣∣ x i<br />

∑<br />

∞ ∣∣∣∣∣<br />

x<br />

⎬<br />

i<br />

n<br />

−λ n−1 = α n O(1)<br />

∣ µ<br />

i=n i µ<br />

i=n−1 i<br />

⎭ ,<br />

⎧ ⎛<br />

⎞<br />

⎫<br />

[<br />

C,∆<br />

+ ] ⎨ ∣ ∣∣∣<br />

=<br />

⎩ X 1<br />

n∑<br />

∣ ⎬<br />

⎝ ∣ µk x k −µ k+1 x k+1 ⎠ = αn O(1)<br />

λ n<br />

⎭ ,<br />

k=1<br />

[<br />

∆ + ,∆ ] = { ∣ ∣ ∣ ∣<br />

X | λ ∣µn n x n −µ n−1 x ∣−λn+1∣µn+1 n−1 x n+1 −µ n x n = αn O(1) } ,<br />

⎧ ∣ ∣ ∣ ∣ ⎫<br />

[<br />

∆ + ,C ] ⎨ ∣ ∣∣∣∣∣ ∣∣∣<br />

=<br />

⎩ X λ n n<br />

∑ ∣∣∣∣∣ ∣∣∣∣∣<br />

x i − λ n+1<br />

∑ ∣∣∣∣∣ ⎬<br />

n+1<br />

x i = α n O(1)<br />

µ n µ<br />

i=1<br />

n+1<br />

⎭ ,<br />

i=1<br />

[<br />

∆ + ,∆ +] = { ∣ ∣ ∣ ∣<br />

X | λ ∣µn n x n −µ n+1 x ∣−λn+1∣µn+1 n+1 x n+1 −µ n+2 x n+2 = αn O(1) } ,<br />

⎧ ⎛ ∣ ∣⎞<br />

⎫<br />

[<br />

C + ,C ] ⎨ ∣ ∣∣∣<br />

∞<br />

=<br />

⎩ X ∑ ∣∣∣∣∣<br />

⎝ 1 1 ∑<br />

k ∣∣∣∣∣ ⎬<br />

x i<br />

⎠ = αn O(1)<br />

λ<br />

k=n k µ k<br />

⎭ ,<br />

i=1<br />

⎧<br />

⎫<br />

[<br />

C + ,∆ ] ⎨ ∣ ∣∣∣<br />

∞<br />

=<br />

⎩ X ∑ ( )<br />

1 ∣ ∣ ⎬<br />

∣µk x k −µ k−1 x k−1 = α n O(1)<br />

λ<br />

k=n k<br />

⎭ ,<br />

⎧<br />

⎫<br />

[<br />

C + ,∆ +] ⎨ ∣ ∣∣∣<br />

∞<br />

=<br />

⎩ X ∑ ( )<br />

1 ∣ ∣ ⎬<br />

∣µk x k −µ k+1 x k+1 = α n O(1)<br />

λ<br />

k=n k<br />

⎭ ,<br />

⎧ ⎛ ∣ ∣⎞<br />

⎫<br />

[<br />

C + ,C +] ⎨ ∣ ∣∣∣<br />

∞<br />

=<br />

⎩ X ∑ ∣∣∣∣∣<br />

⎝ 1 ∑<br />

∞ ∣∣∣∣∣<br />

x<br />

⎬<br />

i ⎠ = αn O(1)<br />

λ<br />

k=n k µ<br />

i=k i<br />

⎭ . (3.19)<br />

We can assert the following result, in which we do the c<strong>on</strong>venti<strong>on</strong> α n = 1forn ≤ 0.<br />

Theorem 3.3.<br />

(i) Assume that α ∈ Γ .Then<br />

[<br />

∆,∆<br />

+ ] = s (α/λµ) − if α λµ ∈ Γ ,<br />

[<br />

∆,C<br />

+ ] = s (α(µ/λ)) if λ (3.20)<br />

α ∈ Γ .<br />

(ii) The c<strong>on</strong>diti<strong>on</strong>s αλ ∈ Γ and αλ/µ ∈ Γ together imply<br />

[<br />

C,∆<br />

+ ] = s (α(λ/µ)) −. (3.21)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!