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Reflection: its concepts and applications in geometry - ResearchGate

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Asia-Pacific Forum on Science Learn<strong>in</strong>g <strong>and</strong> Teach<strong>in</strong>g, Volume 5, Issue 3, Article 7, p.2 (Dec., 2004)<br />

MAN Yiu Kwong<br />

<strong>Reflection</strong>: <strong>its</strong> <strong>concepts</strong> <strong>and</strong> <strong>applications</strong> <strong>in</strong> <strong>geometry</strong><br />

Def<strong>in</strong>ition: If a transformation f has the property that some fixed l<strong>in</strong>e l is the<br />

perpendicular bisector of the segment PP' for any po<strong>in</strong>t P <strong>in</strong> the plane <strong>and</strong> P' = f(P),<br />

then f is a reflection with respect to l. The l<strong>in</strong>e l is called the l<strong>in</strong>e of reflection.<br />

The po<strong>in</strong>t P' is called the image of reflection of P. The def<strong>in</strong>ition implies that P <strong>and</strong> P'<br />

are located at the opposite sides of l <strong>and</strong> they are equidistant from l. It is a basic<br />

property of reflection. A related concept <strong>in</strong> optics is the law of reflection, which states<br />

that the angle of <strong>in</strong>cidence (the angle between the <strong>in</strong>com<strong>in</strong>g ray <strong>and</strong> the normal to the<br />

reflect<strong>in</strong>g surface) is equal to the angle of reflection (the angle between the outgo<strong>in</strong>g<br />

ray <strong>and</strong> the normal), as illustrated <strong>in</strong> Figure 1.<br />

θ<br />

2<br />

θ<br />

1<br />

θ<br />

1<br />

= θ 2<br />

Figure 1<br />

This phenomenon is due to the Fermat's pr<strong>in</strong>ciple, which states that light pass<strong>in</strong>g<br />

through a homogeneous medium (such as air) follows the shortest distance, <strong>in</strong> order to<br />

m<strong>in</strong>imize energy (see Gay, D., 1998 <strong>and</strong> Hecht, E., 1998). The mathematical reason<br />

beh<strong>in</strong>d this law of optics can be expla<strong>in</strong>ed <strong>in</strong> Figure 2, where D' denotes the image of<br />

reflection of D. S<strong>in</strong>ce the ray of light takes a path so as to m<strong>in</strong>imize the total distance<br />

of travel DE+EC (= D'E+EC), therefore D', E <strong>and</strong> C must be coll<strong>in</strong>ear. Hence, we<br />

have ∠CEA = ∠D'EB =∠DEB <strong>and</strong> so θ 1 = 90 o - ∠DEB = 90 o - ∠CEA = θ 2 .<br />

Copyright (C) 2004 HKIEd APFSLT. Volume 5, Issue 3, Article 7 (Dec., 2004). All Rights Reserved.

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